Audited 05 Aug 2026·Last updated 15 Sept 2026·3 citations·Tier 2·0 uses

Area Quadrilateral Calculator

Quadrilateral area calculator: split on a known diagonal and apply Heron's formula to both triangles — sides alone never determine the area.

Area Quadrilateral Calculator

Quadrilateral area
12
Primary result from the named standard variant.
Perimeter
14

Background.

Ask for the area of a triangle with sides 3, 4, 5 and one answer exists: 6. Ask for the area of a quadrilateral with sides 3, 4, 3, 4 and the honest reply is a question — which one? Those four sides bound a rectangle of area 12, every slimmer parallelogram down to a degenerate sliver of area 0, and kites besides: quadrilaterals hinge. Four sides fix a triangle but not a four-sided shape, and any calculator that returns an area from four sides alone has silently guessed the shape for you.

The missing fact is one diagonal. A diagonal braces the hinge — carpenters know this as the reason a gate gets a cross-brace — and mathematically it splits the quadrilateral into two triangles, each now rigid with three known sides. Heron's classical formula turns each triangle's three sides into its area, and the quadrilateral's area is their sum. That is exactly this page's method: enter sides a, b, c, d and the diagonal that separates the (a, b) corner-pair from the (c, d) pair, and it returns the summed area plus the perimeter.

The approach handles any convex quadrilateral — no need for right angles, parallel sides, or a recognised name — which makes it the practical tool for irregular plots of land, sheet-metal offcuts, and room floors that refuse to be rectangles. Field surveyors have measured exactly these five lengths with a tape for centuries precisely because they determine the figure.

Two cautions frame the tool: the diagonal must actually reach between the correct opposite corners (each triangle's three sides must satisfy the triangle inequality, which the page checks), and for a non-convex, dented quadrilateral the split is only valid across a diagonal that stays inside the shape — as the scope note beside the result records.

What is area quadrilateral calculator?

This calculator finds the area of a general quadrilateral from its four sides and one diagonal, by triangulation: the diagonal e splits the figure into a triangle with sides (a, b, e) and another with sides (c, d, e), each of whose areas follows from Heron's formula — √(s(s−x)(s−y)(s−z)) with s the semi-perimeter — and the total is their sum. The diagonal is not optional decoration: four side lengths leave a quadrilateral free to flex through a whole family of shapes with different areas, and the diagonal is the brace that pins down which shape you mean. Perimeter is the plain sum a+b+c+d.

How to use this calculator.

  1. Label the sides in order around the shape — a, b, c, d — and measure the diagonal that runs between the corner where a meets d and the corner where b meets c, so it separates the a-b pair from the c-d pair.
  2. Enter all five lengths in the same unit; the area returns in that unit squared.
  3. If the calculator rejects the inputs, the three sides of one triangle violate the triangle inequality — almost always a sign the other diagonal was measured, or a side order was swapped.
  4. For real plots and rooms, measure the diagonal rather than deriving it: a taped diagonal is the ground truth that makes the five numbers determine the figure.
  5. Cross-check irregular shapes by computing with the other diagonal too (relabelling sides accordingly) — agreement of the two areas is a strong audit of all five measurements.

The formula.

Split on a known diagonal; area = Heron(a,b,e)+Heron(c,d,e); perimeter=a+b+c+d

Triangulation rests on rigidity: three sides determine a triangle completely (SSS congruence), so a quadrilateral cut by a diagonal becomes two solvable pieces. Heron's formula supplies each piece's area from sides alone — for sides x, y, z and semi-perimeter s = (x+y+z)/2, area = √(s(s−x)(s−y)(s−z)) — no angles or heights required, which is what makes tape-measure-only surveying possible. The quadrilateral's area is Heron(a, b, e) + Heron(c, d, e) for diagonal e, and its correctness needs the diagonal to lie inside the figure (true for every diagonal of a convex quadrilateral; true for one of the two in a concave one). The negative test is as informative as the positive: if s(s−x)(s−y)(s−z) goes negative, no triangle with those sides exists — the entered ‘diagonal’ cannot span those corners — and the page refuses rather than inventing a shape. The engine evaluates both Heron roots and the sum in Decimal arithmetic, rounding once to twelve significant digits.

A worked example.

Example

A plot has sides a = 3, b = 4, c = 3, d = 4, and a taped diagonal of 5 running between the corners that separate the 3-4 pairs. The diagonal makes two triangles, each with sides 3, 4, 5. Heron's formula on the first: semi-perimeter s = (3+4+5)/2 = 6, area = √(6×(6−3)×(6−4)×(6−5)) = √(6×3×2×1) = √36 = 6. The second triangle is identical: another 6. Total area = 6 + 6 = 12, and the perimeter is 3+4+3+4 = 14. The 3-4-5 sides are the giveaway: each triangle is right-angled, so this particular quadrilateral is a 3×4 rectangle, and 12 checks against length×width instantly. But the diagonal was doing real work — with the same four sides and a diagonal of 4.5 instead, the two Heron triangles are slimmer and the area drops to about 10.9; push the diagonal toward 1.1 and the shape collapses toward a sliver. Same sides, different diagonal, different quadrilateral: the fifth measurement is what made the first answer 12 rather than anything else.

side D4
side C3
diagonal5
side B4
side A3

Frequently asked questions.

Why can't the area be computed from the four sides alone?
Because quadrilaterals are not rigid. Picture four rods hinged at their ends: without a brace they sway through infinitely many shapes — the 3, 4, 3, 4 example flexes from a rectangle (area 12) through ever-flatter parallelograms toward area 0 — all with identical sides. Triangles have no such freedom (three sides lock the shape), which is exactly why one diagonal, by cutting the figure into two triangles, restores a unique answer. Any four-sides-only calculator has assumed a specific shape on your behalf.
Which diagonal do I measure — a quadrilateral has two?
The one that separates the side-pairs as entered: it must connect the corner where sides a and d meet to the corner where b and c meet, so that one triangle has sides (a, b, diagonal) and the other (c, d, diagonal). Measuring the other diagonal with the same labelling usually produces a triangle-inequality failure — the page's rejection is your hint — or, worse, a plausible-looking wrong area. When in doubt, relabel the sides walking around the shape from one end of the diagonal you actually taped.
Does this work for a concave (dented) quadrilateral?
With care. A concave quadrilateral has one diagonal inside the figure and one outside; the split-and-sum is valid only across the interior diagonal. Using the exterior one makes the two triangles overlap, and their sum overstates the true area (the correct combination there would be a difference, not a sum). Convex shapes — all corners bulging outward — are safe with either diagonal. For seriously irregular boundaries, subdividing into more triangles with additional measured diagonals extends the same method indefinitely.
How is this related to the formulas for squares, trapezoids, and cyclic quadrilaterals?
They are all special cases that trade generality for fewer measurements. A square's area needs one number because equal sides and right angles are promised; a trapezoid's ½(b₁+b₂)h assumes parallel sides; Brahmagupta's elegant √((s−a)(s−b)(s−c)(s−d)) assumes all four corners lie on a circle — the cyclic case, which happens to be the maximum-area shape for given sides. The diagonal-plus-Heron method assumes nothing, which is why it asks for the fifth measurement the special formulas smuggle in as a shape promise.
The calculator says my measurements are invalid — what went wrong?
One of the two triangles fails the triangle inequality: its diagonal is longer than the two adjoining sides can reach (or shorter than their difference). Field causes, in rough order: the other diagonal was taped than the labelling implies; sides were recorded out of walking order, pairing the wrong sides with the diagonal; a transcription slip (metres versus feet on one number is a classic); or the ‘quadrilateral’ has a reflex corner and the taped diagonal lies outside it. Re-walk the boundary, confirm which corners the tape actually joined, and relabel from there.

How this page was produced

Published by
Quanta Calculator
Primary sources
3 cited below
Method
Split on a known diagonal; area = Heron(a,b,e)+Heron(c,d,e); perimeter=a+b+c+d
Published
Last verified

Built with AI assistance and verified by automated tests against the cited sources — every worked example on this page is computed by the same code that runs the calculator. How we build and check calculators.

In this category

Embed

Quanta Pro

Paid features are coming later.

  • All 1560 calculators remain free
  • No billing is enabled
Coming soon