Audited 05 Aug 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Circle Theorems Calculator

Find an inscribed angle from its intercepted arc in degrees. The angle at the circle is half the arc, the rule behind Thales and cyclic quadrilaterals.

Circle Theorems Calculator

°
Inscribed angle
60
The angle at the circumference, in degrees: half the intercepted arc.

Background.

Draw a chord across a circle and pick a point on the circle on one side of it. Join that point to the chord's two ends, and the angle you make is the same wherever on that side you put the point. Slide it along and the triangle changes shape completely, yet the angle at the circle never moves. That constancy is the inscribed angle theorem, and the angle's size is fixed by one thing: the arc on the far side, which the angle is said to intercept. The angle is exactly half of that arc.

Most of the circle theorems in school geometry are this one rule in different clothes. An angle in a semicircle intercepts 180° of arc, so it must be 90°. Two angles standing on the same arc are equal because each is half of it. Opposite corners of a quadrilateral drawn inside a circle add to 180° because between them they intercept all 360°. And the angle at the centre is twice the angle at the circumference because a central angle simply equals its arc.

Give the page the intercepted arc in degrees and it returns the inscribed angle. In a real problem the work is usually in finding the right arc. It is the one lying inside the angle, across the circle from the vertex, and when the vertex sits on the shorter arc the intercepted arc is the longer one, so the angle comes out obtuse.

Arc measure means degrees of turn, the same as the central angle, not the length of the curve. The angle between a tangent and a chord obeys the same halving rule as a limiting case. Angles made by chords crossing inside the circle, or by secants meeting outside it, combine two arcs instead, and those are not computed here.

What is circle theorems calculator?

An inscribed angle has its vertex on a circle and its two sides running along chords. The arc it intercepts is the part of the circle between the two chord ends that lies inside the angle. Arc measure is given in degrees and equals the central angle standing on the same arc, so a full circle measures 360°. The inscribed angle theorem says the inscribed angle is exactly half its intercepted arc, whatever the size of the circle and wherever on the remaining arc the vertex sits.

How to use this calculator.

  1. Find the arc the angle intercepts by tracing from one chord end to the other along the side of the circle away from the vertex. If the problem gives the central angle on that arc instead, use it; the number is the same.
  2. If you only know the arc the vertex sits on, subtract it from 360° first. A vertex on a 100° arc intercepts the remaining 260°.
  3. If you have an arc length and a radius rather than degrees, convert first: arc in degrees = arc length ÷ radius × 180 ÷ π.
  4. Enter the arc, from 0° to 360°, and read the inscribed angle in degrees. The two ends of that range are limiting cases where the angle collapses, not angles you can actually draw.

The formula.

Inscribed angle = intercepted arc / 2

Inscribed angle = intercepted arc ÷ 2. The proof is short. Join the centre O to the vertex P. When one side of the angle, PA, passes through the centre, the other side PB and the radius OB form triangle OPB, which is isosceles because OP and OB are both radii. Its two base angles are equal, and the exterior angle at O, which is the central angle on the arc, equals their sum: twice the inscribed angle. Every other position of P splits into two such cases, added or subtracted. Since an arc's measure equals its central angle, halving the arc gives the inscribed angle. Nothing else enters: not the radius, not the chord length, not where the vertex sits, provided it stays off the intercepted arc. An arc of 180° gives a right angle, smaller arcs give acute angles and larger arcs obtuse ones.

A worked example.

Example

A chord cuts off a 120° arc, and a point on the rest of the circle is joined to the chord's two ends. Halving the arc gives 120 ÷ 2 = 60, so the inscribed angle is 60°. The central angle on the same arc is the full 120°, twice as large, and the chord itself is √3 times the radius, about 1.732 r, although neither length affects the angle. Now move the vertex across the chord, onto the 120° arc. It intercepts the remaining 360 − 120 = 240°, so the angle there is 120°. The two angles add to 60 + 120 = 180°, which is exactly why opposite angles of a cyclic quadrilateral are supplementary.

intercepted Arc120

Frequently asked questions.

Why is the angle in a semicircle always a right angle?
A diameter cuts the circle into two 180° arcs, and an angle standing on either one is half of 180°, which is 90°. This is Thales' theorem. It also gives a workshop trick: lay the corner of a set square on a circle, and the two points where its edges cross the circle are the ends of a diameter.
How do I tell which arc an inscribed angle intercepts?
Look inside the angle. The intercepted arc runs between the two points where the angle's sides meet the circle, on the side away from the vertex. If the vertex sits on a 100° arc, the angle opens onto the other 260°, so it measures 130°, not 50°.
What is the difference between an arc's measure and its length?
Measure is an angle, length is a distance. A 5 cm arc on a circle of radius 4 cm turns through 5 ÷ 4 = 1.25 radians, or about 71.62°. That 71.62° is what goes into this page, and the inscribed angle standing on it is about 35.81°.
Why do opposite angles of a cyclic quadrilateral add up to 180°?
Each of the two opposite angles intercepts the arc on the far side of the diagonal joining the other two corners, and those two arcs together make the whole 360° circle. Half of each arc, added together, is half of 360°, which is 180°, whatever the shape of the quadrilateral.
Can I use this for the angle between a tangent and a chord?
Yes. That angle also equals half the arc it cuts off, a result known as the alternate segment theorem, because it is the limiting case of an inscribed angle whose vertex slides into one end of the chord. Enter the arc lying inside the tangent-chord angle.
What about the angle where two chords cross inside a circle?
That needs a different rule: the angle equals half the sum of the two arcs it and its vertical opposite intercept. Chords crossing to cut off arcs of 70° and 110° meet at (70 + 110) ÷ 2 = 90°. Secants meeting outside the circle use half the difference of the arcs instead.

How this page was produced

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Method
Inscribed angle = intercepted arc / 2
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