Audited 05 Aug 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Circumcenter Of A Triangle Calculator

Find a triangle's circumcenter and circumradius from the coordinates of its three vertices: the one point equally distant from all three corners.

Circumcenter Of A Triangle Calculator

Circumcenter x
3
The x coordinate of the circumcenter, in the same units as the vertex coordinates.
Circumcenter y
4
Circumradius
5

Background.

Any three points that do not lie on one straight line sit on exactly one circle. The centre of that circle is the triangle's circumcenter, the single point the same distance from all three corners, and that shared distance is the circumradius.

On paper, you find it by drawing the perpendicular bisectors of the sides. Every point on one bisector is equally far from the two ends of that side, so the point where two bisectors cross is equally far from all three vertices, and the third bisector is forced through the same spot. In coordinates the construction becomes algebra: set the squared distances from an unknown centre to each vertex equal, let the squared terms cancel in pairs, and solve the two linear equations that remain. The page does this with a closed-form determinant formula.

Where the centre lands says something about the triangle. In an acute triangle it lies inside; in a right triangle it sits exactly on the midpoint of the hypotenuse; in an obtuse triangle it falls outside, beyond the longest side. A circumcenter outside the triangle is therefore not a mistake.

The same problem turns up well outside the classroom. Three marks on the rim of a broken plate, or on a curved wall, are enough to recover the full circle and its centre. In computational geometry, the circumcenters of the triangles in a Delaunay triangulation are the corners of the matching Voronoi diagram.

If the three points are collinear, no circle passes through them, and the page refuses them instead of returning a meaningless centre. Nearly collinear points are accepted, but expect a very distant centre and an enormous radius, because the circle through them is almost a straight line.

What is circumcenter of a triangle calculator?

The circumcenter of a triangle is the centre of its circumscribed circle, the unique circle that passes through all three vertices. It is the intersection of the perpendicular bisectors of the sides, and its distance to each vertex is the circumradius, R. For a triangle with sides a, b and c and area K, R = abc ÷ 4K. It is one of the classical triangle centres alongside the centroid, incenter and orthocenter, and in an equilateral triangle all four are the same point.

How to use this calculator.

  1. Enter the x and y coordinates of vertex A, then B, then C. The order of the vertices does not change the centre.
  2. Use one unit for all six numbers, whether metres, millimetres or grid squares; the radius comes out in that same unit.
  3. When recovering a circle from a real object, mark three points spread as widely around the arc as you can. Points bunched close together let small measuring errors move the centre a long way.
  4. Read the centre's x and y coordinates and the radius. A centre that lies outside the triangle simply means one of its angles is obtuse.

The formula.

Solve equal squared distances from the center to three noncollinear vertices

The centre (Ux, Uy) must satisfy (Ux − x1)² + (Uy − y1)² = (Ux − x2)² + (Uy − y2)² = (Ux − x3)² + (Uy − y3)². Expanding and subtracting these removes Ux² and Uy², leaving two linear equations whose solution is Ux = [S1(y2 − y3) + S2(y3 − y1) + S3(y1 − y2)] ÷ D and Uy = [S1(x3 − x2) + S2(x1 − x3) + S3(x2 − x1)] ÷ D, where each Sᵢ = xᵢ² + yᵢ² and D = 2[x1(y2 − y3) + x2(y3 − y1) + x3(y1 − y2)]. D equals four times the triangle's signed area, so it is zero precisely when the points are collinear, which is the case the page rejects. The radius is the distance from the centre to vertex A, √[(Ux − x1)² + (Uy − y1)²]. With D in the denominator, a thin triangle with a small area pushes the centre a long way off.

A worked example.

Example

Take A = (0, 0), B = (6, 0) and C = (0, 8), a right triangle with its right angle at A. First the denominator: D = 2[0 × (0 − 8) + 6 × (8 − 0) + 0 × (0 − 0)] = 2 × 48 = 96. The squared lengths from the origin are S1 = 0, S2 = 36 and S3 = 64. Then Ux = [0 + 36 × (8 − 0) + 64 × (0 − 0)] ÷ 96 = 288 ÷ 96 = 3, and Uy = [0 + 36 × (0 − 0) + 64 × (6 − 0)] ÷ 96 = 384 ÷ 96 = 4. The circumcenter is (3, 4), and its distance to A is √(3² + 4²) = 5, the circumradius. That point is the midpoint of the hypotenuse from (6, 0) to (0, 8), as it must be for a right triangle, and the radius is half the hypotenuse of 10. Move C to (1, 1), making the angle at C obtuse, and the centre drops outside the triangle to (3, −2), with a radius of √13 ≈ 3.606.

y10
x10
y20
x26
y38
x30

Frequently asked questions.

Why is the circumcenter outside my triangle?
Because the triangle has an obtuse angle. The circumcenter lies inside only when all three angles are acute, sits on the hypotenuse's midpoint for a right triangle, and falls beyond the longest side otherwise. The triangle (0, 0), (6, 0), (1, 1) has its circumcenter at (3, −2), below the base.
How do I find the centre of a circle from three points on its edge?
Treat the three points as the corners of a triangle and enter their coordinates: the circumcenter is the circle's centre and the circumradius is its radius. This works for a partial arc too, such as a curved kerb or a broken plate, provided the points are spread out rather than clustered.
Can three points on a straight line have a circumcenter?
No. The perpendicular bisectors of collinear points are parallel and never meet, so no circle passes through all three, and the page rejects them. Points that are almost collinear do have one, but far away: (0, 0), (6, 0) and (3, 0.1) give a centre at (3, −44.95) and a radius of 45.05.
How is the circumcenter different from the centroid and the incenter?
The centroid is the average of the three vertices, the triangle's balance point; the incenter is where the angle bisectors meet, the centre of the largest circle that fits inside. Both always lie inside the triangle. For (0, 0), (6, 0), (0, 8) the centroid is (2, 2.667) and the incenter (2, 2), while the circumcenter is (3, 4).
Is there a quick way to check the circumradius from the side lengths?
Yes: R = abc ÷ 4K, where a, b and c are the sides and K the area. The 6-8-10 right triangle has area 24, so R = 6 × 8 × 10 ÷ 96 = 5. For any right triangle the shortcut is simpler still, since the radius is always half the hypotenuse.

How this page was produced

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Quanta Calculator
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Method
Solve equal squared distances from the center to three noncollinear vertices
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