Audited 05 Aug 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

General Form Equation Circle Calculator

Convert a circle's centre (h, k) and radius r into general form x² + y² + Dx + Ey + F = 0, with the coefficients D, E and the constant F worked out.

General Form Equation Circle Calculator

General-form constant F
-12
The constant F = h² + k² − r² in x² + y² + Dx + Ey + F = 0.
General-form x coefficient D
-4
General-form y coefficient E
6

Background.

The centre-radius equation of a circle is the one people find easiest to picture, but much of the algebra done with circles happens in the expanded, general form x² + y² + Dx + Ey + F = 0. Once the brackets are multiplied out, the equation is a polynomial like any other: it can be added to or subtracted from another equation, substituted into, and solved alongside a line or a second curve without carrying squared binomials around.

That is why intersection problems are usually set up in general form. To find where a circle meets the x-axis, put y = 0 and what remains, x² + Dx + F = 0, is an ordinary quadratic. To find where two circles cross, subtract one general-form equation from the other: the x² and y² terms cancel, leaving the equation of the straight line through both crossing points. Coordinate-geometry courses and the simplest algebraic methods for fitting a circle to measured points both lean on this form.

Each coefficient carries a piece of geometry. D and E are simply −2h and −2k, so they record the centre with the sign flipped and doubled. F = h² + k² − r² is the squared distance from the origin to the centre minus the squared radius. That makes F the product of the circle's two x-intercepts, and also of its two y-intercepts, whenever those intercepts exist. A negative F means the intercepts straddle the origin, which is another way of saying the origin sits inside the circle.

The page works in one direction only, from a centre and a positive radius to D, E and F, with the x² and y² coefficients fixed at 1. It does not fit a circle through measured points or handle a radius of zero.

What is general form equation circle calculator?

The general form of a circle's equation is x² + y² + Dx + Ey + F = 0, the expanded version of (x − h)² + (y − k)² = r². It belongs to the wider family of second-degree equations Ax² + Bxy + Cy² + Dx + Ey + F = 0; a circle is the case with no xy term and equal x² and y² coefficients, here scaled to 1. The three numbers D, E and F identify the circle completely.

How to use this calculator.

  1. Enter the x-coordinate of the centre as h and the y-coordinate as k, keeping their signs. A centre written as (y + 3) in a bracketed equation has k = −3.
  2. Enter the radius r, which must be positive. If you only know the diameter, halve it; if you know the area, r is the square root of area ÷ π.
  3. Read D and E, then the constant F, and assemble the equation as x² + y² + Dx + Ey + F = 0, writing a negative coefficient with a minus sign in place of the plus.
  4. To check the result, substitute any point you know is on the circle, such as (h + r, k); the left-hand side should come to zero.

The formula.

(x-h)^2+(y-k)^2=r^2; expanded form x^2+y^2-2hx-2ky+h^2+k^2-r^2=0

Expanding (x − h)² + (y − k)² = r² gives x² − 2hx + h² + y² − 2ky + k² − r² = 0. Grouping like terms, the x coefficient is D = −2h, the y coefficient is E = −2k, and everything without a variable collects into F = h² + k² − r². D and E depend only on the centre, so moving the circle sideways changes them while resizing it does not. F depends on all three inputs, and because r² is subtracted it drops as the circle grows. Substituting any point (x₀, y₀) into the left-hand side gives the squared distance from that point to the centre minus r²: negative inside the circle, zero on it, positive outside.

A worked example.

Example

Take the circle centred at (2, −3) with radius 5. The x coefficient is D = −2 × 2 = −4 and the y coefficient is E = −2 × (−3) = 6. The constant is F = 2² + (−3)² − 5² = 4 + 9 − 25 = −12. The general form is therefore x² + y² − 4x + 6y − 12 = 0. The new form puts the intercepts within reach. Setting y = 0 leaves x² − 4x − 12 = 0, which factors as (x − 6)(x + 2) = 0, so the circle crosses the x-axis at 6 and −2. Their product, 6 × (−2), is −12, equal to F; setting x = 0 instead gives y² + 6y − 12 = 0, with roots of about 1.583 and −7.583, whose product is again −12.

center Y-3
center X2
radius5

Frequently asked questions.

Why would I want the general form if the standard form is easier to read?
Because it behaves like an ordinary polynomial. Substituting a line such as y = mx + c into it gives a quadratic whose discriminant tells you at once whether the line cuts the circle, touches it or misses it. Subtracting two circles' general forms gives the line through their intersection points.
My textbook shows 2x² + 2y² − 8x + 12y − 24 = 0. Is that the same circle?
Yes. Multiplying every term of a general-form equation by the same non-zero number does not change the set of points it describes. Divide through by the coefficient of x², here 2, to get x² + y² − 4x + 6y − 12 = 0, then read off D, E and F.
How do I find where two circles intersect using the general form?
Write both in general form and subtract one from the other. The squared terms cancel, leaving a linear equation called the radical axis, which passes through both intersection points. Solve that line together with either circle to get the points; if the resulting quadratic has no real roots, the circles do not meet.
What does the value of F tell me?
F is the squared distance from the origin to the centre minus the squared radius. Negative F puts the origin inside the circle, zero puts it on the circle, positive puts it outside. When the circle crosses an axis, F also equals the product of the two intercepts on that axis.
What do I get if I plug a point outside the circle into the left-hand side?
A positive number equal to the square of the tangent length from that point to the circle. For the circle x² + y² − 4x + 6y − 12 = 0 and the point (8, 5), the left-hand side is 75, so a tangent drawn from (8, 5) touches the circle after about 8.660 units.

How this page was produced

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(x-h)^2+(y-k)^2=r^2; expanded form x^2+y^2-2hx-2ky+h^2+k^2-r^2=0
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