Audited ·Last updated 29 Jul 2026·8 citations·Tier 2·0 uses

Black Hole Temperature Calculator (Hawking Radiation)

Hawking temperature, Bekenstein–Hawking entropy, radiated power and evaporation time from a black hole's mass — or solve back for the mass.

Black Hole Temperature Calculator

What are you starting from?
SI kilograms. Reference masses: Sun 1.98841 × 10³⁰ (PDG 2024) · Sagittarius A* 8.5442 × 10³⁶ · M87* 1.2925 × 10⁴⁰ · a hole at exactly the CMB temperature 4.5016 × 10²² · a hole evaporating in one age of the universe 1.7294 × 10¹¹. Must be greater than zero.
Used in the temperature → mass route. Thermodynamic (absolute) temperature only. A one-solar-mass hole sits at 6.17026 × 10⁻⁸ K; the cosmic microwave background is at 2.72548 K. Must be greater than zero.
Hawking temperature (K)
0
T_H = ħc³/(8πGMk_B), in kelvin. Thermodynamic temperature of the thermal spectrum an observer at infinity sees. Exact in the semiclassical regime, for a non-rotating hole.
Mass (kg)
1,988,410,000,000,000,000,000,000,000,000
Mass (M☉)
1
Event-horizon radius (m)
2,953.2503
Entropy S / k_B (dimensionless)
104,889,158,490,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000
Entropy S (J/K)
1,448,151,117,810,000,000,000,000,000,000,000,000,000,000,000,000,000,000
Radiated power — idealised (W)
0
Evaporation time — idealised (years)
20,954,927,238,900,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000
Evaporation time — idealised (s)
661,287,211,834,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000
T_H ÷ T_CMB
0
Conventions and limits for this result
Schwarzschild (zero spin, zero charge) and semiclassical: the spacetime is treated classically while the radiation field is quantum. T_H and the Bekenstein–Hawking entropy are exact in that regime; a spinning Kerr hole of the same mass is colder. The radiated power and evaporation time are an IDEALISATION — a perfect blackbody of area 4πr_s² emitting photons only. Page (1976) computed the real emission for a hole hot enough to evaporate and found roughly 9.7 times more power once greybody factors and other particle species are included, so a true lifetime is about an order of magnitude shorter than the figure shown. Absorption of the cosmic microwave background is not modelled anywhere on this page. WARNING: this hole is colder than the 2.72548 K cosmic microwave background, so today it absorbs more energy than it radiates and is GROWING, not evaporating. Every black hole heavier than about 4.50 × 10²² kg — which is every black hole ever observed — is in this state. The evaporation time above is therefore not a prediction; it is what the lifetime would be in an empty, cold universe.

Background.

Black holes are not black. In 1974 Stephen Hawking showed that quantum field theory in the curved spacetime around a horizon forces the hole to radiate with an exactly thermal spectrum, at a temperature fixed entirely by its mass: T_H = ħc³/(8πGMk_B). This calculator returns that temperature, along with the Bekenstein–Hawking entropy, the radiated power and an evaporation-time estimate — and it will run the relation backwards, giving the mass a hole must have to sit at a temperature you specify.

The first thing the numbers tell you is that Hawking radiation is astrophysically irrelevant for every black hole anyone has ever observed. A one-solar-mass hole has a Hawking temperature of 6.17026 × 10⁻⁸ kelvin — sixty-two nanokelvin, about 44 million times colder than the cosmic microwave background. Sagittarius A* comes in at 1.4 × 10⁻¹⁴ K and M87* at 9.5 × 10⁻¹⁸ K. Because temperature falls as 1/M, bigger holes are colder, and because the radiated power falls as 1/M², bigger holes are dimmer. The only holes that radiate appreciably are the ones far too light to form from a collapsing star.

That leads directly to the caveat that matters most, and it belongs here rather than buried in an FAQ. **Any black hole colder than the 2.72548 K microwave background absorbs more energy from that background than it emits, so it is growing, not evaporating.** The crossover sits at 4.5016 × 10²² kg, roughly six-tenths of a percent of the Moon's mass. Every black hole ever detected is enormously heavier than that, which means every evaporation time this page prints for a real object is not a prediction — it is the lifetime the hole would have in an empty, cold universe. The calculator says so on the result itself whenever the condition applies.

The second caveat concerns which numbers are exact and which are idealisations, because they are not all the same kind of quantity. The temperature and the entropy are exact semiclassical results: they follow from the horizon's surface gravity and area with no free parameters, and Wald's review states them in natural units as T = κ/2π and S = A/4, which restore to precisely the SI expressions used here. The radiated power and the evaporation time are different. They come from the textbook idealisation of a perfect blackbody of area 4πr_s² emitting photons and nothing else. Don Page computed the real emission in 1976 and found roughly 2 × 10⁻⁴ ħc⁶G⁻²M⁻² for a hole hot enough to matter — about 9.7 times the naive coefficient — of which 81% is neutrinos, 17% photons and 2% gravitons. So the true lifetime of an evaporating hole is roughly an order of magnitude shorter than the figure shown. This page prints the standard textbook number, because that is what the formula in every textbook gives, and states the correction rather than silently applying one particular refinement.

Everything here assumes the Schwarzschild solution: zero spin, zero charge. A rotating Kerr hole of the same mass is colder, because its surface gravity is lower, and its emission is anisotropic and spin-dependent in ways no closed-form single-line formula captures. Treat the answer as exact for a non-spinning hole and as an upper bound on temperature for a spinning one.

The constants carry named sources and revisions. ħ = 1.054571817 × 10⁻³⁴ J s and k_B = 1.380649 × 10⁻²³ J/K are exact under CODATA 2022, as is c. G = 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² carries a relative uncertainty of 2.2 × 10⁻⁵ and is the only real source of error in the temperature. The CMB temperature of 2.72548 ± 0.00057 K is Fixsen (2009); the 13.787-billion-year age of the universe used for the "already evaporated" flag is Planck 2018.

What is black hole temperature calculator?

Hawking temperature is the thermodynamic temperature of the radiation a distant observer sees emerging from a black hole horizon. For a Schwarzschild (non-rotating, uncharged) hole it is T_H = ħc³/(8πGMk_B), inversely proportional to mass. Nothing about the hole's composition or history enters; the mass alone fixes it.

The result comes from quantum field theory on a classical curved background — the semiclassical regime. Hawking's 1975 calculation showed that the vacuum state defined before collapse does not look like the vacuum afterwards, and the mismatch is exactly a Planck spectrum at κ/2π, where κ is the horizon's surface gravity. It is the same κ = c⁴/(4GM) that the Schwarzschild radius calculator reports.

Bekenstein–Hawking entropy is the companion result: S = k_B A c³/(4ħG), or equivalently S/k_B = A/(4ℓ_P²) — the horizon area measured in units of four Planck areas. It is a genuine thermodynamic entropy, satisfying a first law dM c² = T dS, and it is enormous. A single solar-mass black hole has S/k_B ≈ 1.05 × 10⁷⁷, which exceeds the entropy of all ordinary matter in the observable universe by a wide margin.

The evaporation time is not on the same footing. It comes from integrating a model of the radiated power, and the standard formula t = 5120πG²M³/(ħc⁴) assumes photon-only blackbody emission from area 4πr_s². It is the number in the textbooks and the number this page prints, but it is a model output, not a theorem, and the real answer depends on which particle species the hole is hot enough to emit.

How to use this calculator.

  1. Choose whether you are starting from a mass or from a temperature.
  2. Enter the mass in kilograms — the field hint lists the Sun, Sagittarius A*, M87*, the CMB-balance mass and the mass that evaporates in one age of the universe.
  3. Or enter a Hawking temperature in kelvin to find the mass that produces it.
  4. Read the Hawking temperature and the entropy first. Those two are exact semiclassical results.
  5. Read the power and evaporation time second, and read them as idealisations — the note beneath states the Page (1976) correction factor and whether the hole is a net CMB absorber.
  6. Check T_H ÷ T_CMB. If it is below 1, the hole is currently growing and the evaporation figure describes a hypothetical empty universe rather than ours.

The formula.

T_H = ħc³ ⁄ (8πGMk_B) · S = 4πk_B GM² ⁄ (ħc) = k_B A c³ ⁄ (4ħG) · P = ħc⁶ ⁄ (15360πG²M²) · t = 5120πG²M³ ⁄ (ħc⁴)

Start from the horizon's surface gravity, κ = c⁴/(4GM). Hawking's result, stated in the form Wald's review uses (units with G = c = ħ = k_B = 1), is simply T = κ/2π. Restoring SI units gives T = ħκ/(2πck_B), and substituting κ yields T_H = ħc³/(8πGMk_B). The same review states the entropy as S = A/4 in Planck units; restoring units gives S = k_B Ac³/(4ħG), and substituting A = 16πG²M²/c⁴ gives S = 4πk_B GM²/(ħc). Both restorations are asserted numerically in this page's test suite, which is how the formulas were verified against a source that states them in a completely different notation.

The power follows from treating the horizon as a blackbody: P = σAT⁴ with σ = π²k_B⁴/(60ħ³c²), A = 16πG²M²/c⁴ and T = T_H. The algebra collapses to P = ħc⁶/(15360πG²M²). Setting dM/dt = −P/c² and integrating M² dM gives t = 5120πG²M³/(ħc⁴). A useful check on those two together: P × t = Mc²/3 exactly, which the tests assert as a dimensional guard.

Units and dimensions. Mass in kilograms, temperature in kelvin (thermodynamic, never Celsius), entropy in J/K and also as the dimensionless S/k_B, power in watts, lifetime in seconds and Julian years of exactly 31 557 600 s. The dimensional guard the test suite runs is that S/k_B computed as 4πGM²/(ħc) equals the horizon area divided by four Planck areas, ℓ_P² = ħG/c³ — and that √(ℓ_P²) reproduces the PDG's published Planck length of 1.616255 × 10⁻³⁵ m.

Rounding stage. No intermediate rounding. Forty significant digits throughout, rounded once at the return boundary to twelve significant digits. Decimal-place rounding was rejected deliberately: these outputs span about 180 orders of magnitude — a supermassive hole radiates around 10⁻⁴⁸ W — and ten-decimal-place rounding would report that as exactly zero, a wrong answer disguised as a rounded one.

Significant figures. Quote at most five. The temperature, entropy, power and lifetime all inherit G's 2.2 × 10⁻⁵ relative uncertainty; the lifetime inherits it cubed through M³ if you supply the mass in kilograms rather than as a GM product. Beyond that, the power and lifetime carry a modelling uncertainty of roughly an order of magnitude, which dwarfs anything the constants contribute.

Invalid-domain behaviour. Zero or negative mass raises a field error rather than returning an infinite temperature: T_H diverges as M → 0, and the entropy, power and lifetime all become 0/0 or division by zero. Zero or negative temperature raises the same kind of error, since T = 0 would require infinite mass. Two thresholds attach notes rather than errors: T_H below 2.72548 K flags the hole as a net CMB absorber, and an idealised lifetime below 13.787 billion years flags it as something that would already have evaporated.

A worked example.

Example

The most informative question this calculator answers is not "how cold is a black hole" but "how small must a black hole be before it is warmer than the sky". Set the Hawking temperature to 2.72548 K — the cosmic microwave background monopole measured by Fixsen (2009) — and solve for the mass. M = ħc³/(8πGk_BT) = (1.054571817 × 10⁻³⁴ × 2.6944002 × 10²⁵) / (8π × 6.67430 × 10⁻¹¹ × 1.380649 × 10⁻²³ × 2.72548) = 4.50159 × 10²² kg. That is about 0.61% of the Moon's mass, packed into an event horizon of r_s = 2GM/c² = 66.859 micrometres — smaller than the width of a human hair. Its Bekenstein–Hawking entropy is S/k_B = 5.3759 × 10⁶¹, its idealised radiated power is 1.7576 × 10⁻¹³ W, and its idealised evaporation time is 2.4315 × 10⁴⁴ years. The point of the number is the boundary it draws. Anything heavier than 4.5 × 10²² kg is colder than the CMB, so it gains more energy from the microwave background than it loses to Hawking radiation and is growing today. Anything lighter is warmer than the sky and is genuinely losing mass. Every black hole ever observed — the lightest stellar-mass candidates are a few solar masses, twenty orders of magnitude heavier — falls on the growing side. Run the same engine forwards on the Sun for contrast. M = 1.98841 × 10³⁰ kg gives T_H = 6.17026 × 10⁻⁸ K, exactly the 6.17 × 10⁻⁸ K quoted in the standard references, with r_s = 2953.25 m, S/k_B = 1.04889 × 10⁷⁷, an idealised power of 9.0082 × 10⁻²⁹ W and an idealised lifetime of 2.0955 × 10⁶⁷ years. The ratio T_H/T_CMB is 2.2639 × 10⁻⁸, so the Sun-as-black-hole would be 44 million times colder than the sky, and the result carries the growing-not-evaporating warning. One more calibration, in the opposite direction. The mass whose idealised lifetime equals the 13.787-billion-year age of the universe is 1.72942 × 10¹¹ kg — about the mass of a small mountain, in a horizon 2.57 × 10⁻¹⁶ m across, at a temperature of 709 billion kelvin. Page (1976) put the equivalent figure at (5 ± 1) × 10¹⁴ g = (5 ± 1) × 10¹¹ kg, roughly three times larger, precisely because his calculation included greybody factors and the neutrino and electron–positron channels that the textbook photon-only formula omits. Both numbers are recorded here; the page prints the textbook one and names the discrepancy rather than resolving it silently.

hawking Temperature K2.725
mass Kg1,988,410,000,000,000,000,000,000,000,000
solve ForfromTemperature

Frequently asked questions.

What is the Hawking temperature formula?
T_H = ħc³/(8πGMk_B) for a non-rotating, uncharged black hole of mass M. Equivalently T_H = ħκ/(2πck_B), where κ = c⁴/(4GM) is the horizon's surface gravity — this is the form Hawking's result naturally takes, and the form Wald's Living Reviews article states as T = κ/2π in units with G = c = ħ = k_B = 1. Because T_H is inversely proportional to M, doubling the mass halves the temperature, and the relation inverts to M = ħc³/(8πGk_BT).
How cold is a solar-mass black hole?
6.17026 × 10⁻⁸ K — about sixty-two nanokelvin. That is roughly 44 million times colder than the 2.72548 K cosmic microwave background, and about a hundred million times colder than the coldest large-scale laboratory refrigerators reach. Supermassive holes are colder still: Sagittarius A* at 4.297 million solar masses is at 1.436 × 10⁻¹⁴ K, and M87* at 6.5 billion solar masses is at 9.493 × 10⁻¹⁸ K.
Are black holes actually evaporating right now?
None of the ones we can see. A black hole colder than the 2.72548 K microwave background absorbs more energy from that background than it radiates away, so its mass increases. The crossover is at 4.5016 × 10²² kg — about 0.61% of the Moon's mass, with a 67-micrometre horizon. Every observed black hole is at least twenty orders of magnitude heavier than that, so every one of them is currently growing. Real evaporation only begins once the universe has expanded and cooled enough that the CMB drops below the hole's Hawking temperature, which for a stellar-mass hole is very far in the future. The calculator flags this on any result where it applies.
How accurate is the evaporation time?
Treat it as an order-of-magnitude figure, not a number. Two things limit it. First, the formula t = 5120πG²M³/(ħc⁴) assumes the hole is a perfect blackbody of area 4πr_s² emitting photons and nothing else. Page (1976) computed the actual emission including greybody factors and other massless species and found roughly 2 × 10⁻⁴ ħc⁶G⁻²M⁻² of power for a hole hot enough to evaporate — about 9.7 times the naive value, of which 81% is neutrinos, 17% photons and 2% gravitons — which makes the true lifetime roughly ten times shorter. Second, the formula ignores CMB absorption entirely, which for any observed hole reverses the sign of the mass change. This page prints the textbook number and states both corrections rather than quietly applying one.
What is Bekenstein–Hawking entropy, and why is it so large?
S = k_B A c³/(4ħG), or equivalently S/k_B = A/(4ℓ_P²) — the horizon area measured in units of four Planck areas, where ℓ_P = 1.616255 × 10⁻³⁵ m. Bekenstein argued in 1973 that a black hole must carry entropy proportional to its horizon area or the second law of thermodynamics would fail; Hawking's temperature calculation fixed the coefficient at 1/4. The numbers are enormous because the Planck area is so small: one solar mass gives S/k_B = 1.0489 × 10⁷⁷, more than the entropy of all the ordinary matter in the observable universe. It is a genuine thermodynamic entropy — it satisfies a first law, dMc² = T dS — and explaining what microstates it counts is one of the central problems of quantum gravity.
Does spin change the temperature?
Yes. Everything on this page uses the Schwarzschild solution, which assumes zero spin and zero charge. A rotating Kerr black hole of the same mass has lower surface gravity and is therefore colder, reaching zero temperature in the extremal limit of maximal spin. Its emission is also anisotropic and strongly spin-dependent, with rotational superradiance adding channels that a single-line formula cannot express. Real astrophysical black holes spin, sometimes near the maximum, so read this page's temperature as the value for a non-spinning hole and as an upper bound for a spinning one of the same mass.
Why does a smaller black hole get hotter?
Because T_H ∝ 1/M, and that gives black-hole radiation the unusual property of negative heat capacity: losing energy makes it hotter, which makes it lose energy faster. The power scales as 1/M², so the evaporation accelerates without limit as the mass falls — the final stage of the process is a burst, not a fade. This is also why the arithmetic runs away at M → 0 and the calculator raises an error rather than returning an infinite temperature. In practice the semiclassical treatment stops being trustworthy well before that, once the hole approaches the Planck mass of about 2.18 × 10⁻⁸ kg, where an unknown theory of quantum gravity takes over.
How does this differ from the Schwarzschild radius calculator?
That page is classical geometry: given a mass, how big is the horizon, where is the photon sphere, where is the innermost stable circular orbit, what is the surface gravity. All of it is exact general relativity with no quantum input. This page starts from that same surface gravity κ = c⁴/(4GM) and adds quantum mechanics — ħ appears in every formula here and in none of them there. The two are deliberately split because their epistemic status is different: the geometry is exact and uncontested, whereas the power and lifetime here depend on modelling assumptions with an order-of-magnitude spread.
Has Hawking radiation ever been detected?
Not from an astrophysical black hole, and on these numbers it is hard to see how it could be: a solar-mass hole radiates about 9 × 10⁻²⁹ watts, while absorbing vastly more than that from the microwave background. Laboratory analogues — Bose–Einstein condensates and optical systems engineered to have sonic or optical horizons — have reported thermal spectra consistent with the analogous prediction, and those results are taken seriously as tests of the underlying kinematics. They are not observations of a gravitational black hole, and nothing on this page should be read as claiming otherwise.

References& sources.

  1. [1]Hawking, S. W. (1975), "Particle Creation by Black Holes", Communications in Mathematical Physics 43, 199–220. The original derivation of the thermal spectrum at temperature ħκ/(2πk_B). Peer-reviewed; the journal copy is paywalled at Project Euclid/Springer — cited here as the origin of the result, with the formulas themselves verified against the open-access Wald review below. Retrieved (metadata) 2026-07-29.
  2. [2]Wald, R. M. (2001), "The Thermodynamics of Black Holes", Living Reviews in Relativity 4, 6; open-access full text retrieved 2026-07-29 via PubMed Central. States, in units with G = c = ħ = k = 1, that a black hole "radiates to infinity all species of particles with a perfect black body spectrum, at temperature" T = κ/(2π), and that the entropy is S_bh = A/4 in Planck units. This is the second, independent authority: restoring SI units from those two statements alone reproduces this engine's T_H and S exactly, and the tests assert it numerically.
  3. [3]Page, D. N. (1976), "Particle emission rates from a black hole: Massless particles from an uncharged, nonrotating hole", Physical Review D 13, 198. Finds that a hole of mass M ≫ 10¹⁷ g emits a total power of 2 × 10⁻⁴ ħc⁶G⁻²M⁻², of which 81% is neutrinos, 17% photons and 2% gravitons, and that primordial black holes would have decayed within the present age of the universe if and only if their initial mass was below (5 ± 1) × 10¹⁴ g. This is the source of the ~9.7× correction stated beside the power and lifetime outputs. Peer-reviewed; paywalled at APS, abstract freely visible.
  4. [4]Bekenstein, J. D. (1973), "Black Holes and Entropy", Physical Review D 7, 2333. The argument that a black hole must carry entropy proportional to horizon area. Peer-reviewed; paywalled at APS. Bibliographic reference — no number is taken from it that is not independently in Wald.
  5. [5]Fixsen, D. J. (2009), "The Temperature of the Cosmic Microwave Background", Astrophysical Journal 707, 916; arXiv:0911.1955, retrieved 2026-07-29. Gives T_CMB = 2.72548 ± 0.00057 K, the value this page compares every Hawking temperature against. The Particle Data Group independently prints 2.7255(6) K. Peer-reviewed; open-access preprint.
  6. [6]NIST/CODATA 2022 fundamental constants, retrieved 2026-07-29: reduced Planck constant ħ = 1.054 571 817 × 10⁻³⁴ J s (exact), Boltzmann constant k_B = 1.380 649 × 10⁻²³ J K⁻¹ (exact), speed of light c = 299 792 458 m s⁻¹ (exact), Newtonian constant of gravitation G = 6.674 30(15) × 10⁻¹¹ m³ kg⁻¹ s⁻² (u_r = 2.2 × 10⁻⁵). Standards body; open access.
  7. [7]Particle Data Group (Workman et al.), Review of Particle Physics, "Astrophysical Constants and Parameters", Table 2.1, revised August 2023; 2024 PDF retrieved 2026-07-29. Source of M☉ = 1.98841(4) × 10³⁰ kg and of the Planck length ℓ_P = 1.616255(18) × 10⁻³⁵ m, which the entropy area-law test reproduces from ħ, G and c. Also prints T_CMB = 2.7255(6) K, agreeing with Fixsen. Open access.
  8. [8]Planck Collaboration (2020), "Planck 2018 results. VI. Cosmological parameters", Astronomy & Astrophysics 641, A6. Source of the 13.787 ± 0.020 Gyr age of the universe used only to decide when to flag a hole as one that would already have evaporated. Peer-reviewed; open access.

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