Audited 31 Jul 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Dipole Moment Calculator

Find the electric dipole moment p = qd of two equal and opposite point charges from the charge in coulombs and their separation in metres, in C·m.

Dipole Moment Calculator

C
m
Electric dipole moment
6.000 × 10⁻⁸
The magnitude of the electric dipole moment, charge times separation, in coulomb-metres (C·m).
Model scope
Magnitude for an ideal two-point-charge dipole; vector direction, distributed charge, and multipole terms are outside this model.

Background.

Put a positive and a negative charge of equal size close together and, seen from far away, they almost cancel: the net charge is zero. Almost is the interesting part. The pair still produces an electric field, still twists when placed in an external field, and still tugs on nearby charges, and the single quantity that governs all of that at a distance is the electric dipole moment — the size of either charge multiplied by the distance between them.

In SI units the moment is in coulomb-metres. The default pair here, ±2 µC held 3 cm apart, has a moment of 6 × 10⁻⁸ C·m. Chemistry works in a far smaller unit, the debye, worth about 3.336 × 10⁻³⁰ C·m, because molecular dipoles involve fractions of an electron's charge across fractions of a nanometre; a water molecule's moment is about 1.85 D.

Why the product, rather than the charges alone? Because, seen from a distance, doubling the separation has exactly the same effect as doubling the charge. The far field of a dipole is proportional to p and falls off with the cube of distance, the torque in a uniform field E is pE sin θ, and the potential energy there is −pE cos θ. In every case q and d enter only through their product, which makes p the natural figure for comparing one dipole with another.

The page computes the magnitude for the idealised case of two equal and opposite point charges. The direction of the moment, a spread-out charge distribution and its higher multipole terms are left out. Charges below 2 × 10⁻¹⁸ C, about 12.5 electron charges, are outside the accepted range, so single-electron molecular cases have to be worked by hand.

What is dipole moment calculator?

The electric dipole moment of two equal and opposite point charges, +q and −q, is a vector of magnitude p = q·d, where d is the distance between them, pointing from the negative charge toward the positive one. It measures how strongly the pair behaves as a dipole: the field it produces at a distance, the torque it feels in an external field, and its energy there. The SI unit is the coulomb-metre, written C·m.

How to use this calculator.

  1. Enter the magnitude of one of the two charges in coulombs — not their sum, and without a sign. A charge of 2 µC is entered as 0.000002.
  2. Enter the distance between the two charge centres in metres: 3 cm is 0.03 and 5 mm is 0.005.
  3. Read the dipole moment in coulomb-metres. To express it in debye, divide by 3.336 × 10⁻³⁰.
  4. Keep the scope note in mind: the result is a magnitude for two point charges, so direction and the detail of a spread-out charge are not included.

The formula.

p = qd

p = q × d, where q is the magnitude of each charge in coulombs and d the separation in metres, giving p in coulomb-metres. The formula is exact for two point charges. For a continuous distribution the moment is the sum, or integral, of each bit of charge times its position vector, and for a neutral distribution that sum does not depend on where the origin is placed. The two inputs act symmetrically: doubling either one doubles the moment, and halving the charge while doubling the gap leaves it unchanged. What the moment then controls follows from standard results — far from the dipole the field on its axis is E = 2kp/r³, with k = 8.988 × 10⁹ N·m²/C²; the torque in a uniform field is pE sin θ; the potential energy is −pE cos θ. A zero charge or zero gap gives no dipole at all, so both entries must be greater than zero.

A worked example.

Example

The default dipole is a pair of charges of ±2 µC held 3 cm apart. In SI units that is q = 2 × 10⁻⁶ C and d = 0.03 m, so p = 2 × 10⁻⁶ × 0.03 = 6.00 × 10⁻⁸ C·m — about 1.80 × 10²² debye, a reminder of how small molecular dipoles are by comparison. In a uniform field of 1,000 N/C this dipole feels a torque of at most 6 × 10⁻⁸ × 1,000 = 6.00 × 10⁻⁵ N·m, when it lies at right angles to the field. One metre away along its axis, the far-field formula gives 2 × 8.988 × 10⁹ × 6 × 10⁻⁸ ÷ 1³ = 1,078.5 N/C, within 0.05% of the 1,079.0 N/C found by adding the two charges' fields exactly.

charge Magnitude C0
separation M0.03

Frequently asked questions.

How do I convert coulomb-metres to debye?
Divide by 3.336 × 10⁻³⁰, the size of one debye in coulomb-metres. The debye comes from the older CGS system and suits molecules: water's moment of about 1.85 D is 6.17 × 10⁻³⁰ C·m. Laboratory-scale dipoles like the default example run to around 10²² D.
Can I work out a molecule's dipole moment here?
Not directly, because molecular charges are fractions of an electron charge, below the smallest charge this page accepts. By hand, one electron charge across 1 ångström is 1.602 × 10⁻²⁹ C·m, or 4.80 D. Real molecules come out lower, since the charge shift along a bond is only partial.
Which way does the dipole moment vector point?
In physics, where p is defined as the sum of each charge times its position, it points from the negative charge to the positive one. Chemistry diagrams often use a crossed arrow pointing the other way, toward the more electronegative atom, so check the convention before combining results. This page reports only the magnitude, which is the same either way.
Why does a dipole's field fall off faster than a single charge's?
Far away, the fields of the two opposite charges nearly cancel, leaving a remainder that shrinks as 1/r³ instead of 1/r². Doubling the distance therefore cuts a dipole's field to one-eighth, where a lone charge's field would fall only to one-quarter.
What happens to a dipole placed in a uniform electric field?
The forces on its two charges are equal and opposite, so there is no net push, only a twist of pE sin θ that turns it to line up with the field. Turning the default dipole from aligned to reversed in a 1,000 N/C field takes 2pE = 1.2 × 10⁻⁴ J of work.
What if the two charges are not equal in size?
Then the pair has a net charge, and its dipole moment depends on where you put the origin, so p = qd no longer gives a unique answer. This page assumes equal and opposite charges; an unequal pair needs the full sum of each charge times its position.

How this page was produced

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Method
p = qd
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