Audited ·Last updated 27 Jul 2026·6 citations·Tier 1·0 uses

Kinetic Energy Calculator

Free kinetic energy calculator using KE = ½mv². Compute joules and momentum from mass and velocity, with worked car-crash and relativistic examples.

Kinetic Energy Calculator

Mass of the moving object in kilograms. For grams divide by 1000 (e.g. a 145 g baseball = 0.145 kg); for tonnes multiply by 1000 (a 1.5 t car = 1500 kg).
kg
Speed of the object in metres per second. Convert km/h by dividing by 3.6 (100 km/h = 27.78 m/s) and mph by multiplying by 0.44704 (60 mph = 26.82 m/s).
m/s
Kinetic energy
125
Translational kinetic energy of the object, computed as ½ × m × v² and reported in joules (1 J = 1 kg·m²/s²).
Linear momentum
50 kg·m/s

Background.

This kinetic energy calculator returns the translational kinetic energy of a moving body from its mass and velocity using the classical formula KE = ½mv², and as a bonus it returns the linear momentum p = mv from the same two inputs. Enter mass in kilograms and velocity in metres per second; the tool replies in joules (J), the SI unit of energy, defined as 1 J = 1 kg·m²/s².

The reason kinetic energy is worth its own calculator — rather than being treated as just another textbook formula — is that the quadratic dependence on velocity is one of the most consequential and most misunderstood facts in everyday physics. Doubling a car's speed quadruples its kinetic energy, and therefore quadruples the distance it needs to stop on the same surface (energy must be dissipated as friction × distance), and quadruples the damage it can do in a crash (work-energy theorem: the kinetic energy must be absorbed by whatever it hits). The intuition people carry — that twice as fast is twice as dangerous — is wrong by a factor of two, and that factor is exactly why a 50 km/h impact is survivable in a modern car while a 100 km/h impact often is not.

The concept itself is older than its modern name. Gottfried Leibniz and Johann Bernoulli argued in the 1680s that the conserved quantity in motion was proportional to mv² rather than mv, calling it the vis viva or 'living force'. Émilie du Châtelet, working through Newton's Principia in the 1740s, was the first to publish a clean derivation tying the vis viva to a quantity proportional to mv² (modulo the factor of ½ that came later from the integration of force through distance). The name 'kinetic energy', from the Greek kinēsis meaning motion, was coined by William Thomson (Lord Kelvin) around 1849 once it was clear that vis viva and heat were two faces of the same conserved quantity, energy — the foundational insight of nineteenth-century thermodynamics.

Below the widget you will find the work-energy derivation that produces the factor of ½, a detailed treatment of why car-crash forces scale with v² and not v, a careful contrast of kinetic energy against gravitational potential energy with conservation-of-energy worked examples (pendulum, dropped ball, roller coaster), the relativistic correction (γ − 1)mc² that takes over once v becomes a non-trivial fraction of the speed of light, the rotational analogue KE_rot = ½Iω² for spinning bodies, and an honest list of where the simple formula breaks down — air resistance, internal deformation, rotation, relativity, and quantum-mechanical regimes where 'velocity' itself stops being a well-defined classical observable. The formula is dispatched at kineticEnergy.calculate inside the Quanta engine and is covered by 5 unit tests against the canonical worked examples (10 kg at 5 m/s = 125 J, baseball at 40 m/s, bullet at 400 m/s, and the two zero-input edge cases) so the number the widget returns is the same number used everywhere else in the toolset.

What is kinetic energy calculator?

Kinetic energy is the energy that an object possesses by virtue of being in motion. For a point mass — or for the centre of mass of an extended rigid body that is translating without rotating — the kinetic energy is KE = ½mv², where m is the inertial mass (in kilograms) and v is the speed of the centre of mass (in metres per second). The result is in joules. Three properties define kinetic energy and separate it from related quantities such as momentum. First, it is a scalar: kinetic energy has a magnitude but no direction, which means kinetic energies of objects in a system simply add as numbers (unlike momenta, which add as vectors). Second, it is frame-dependent: a passenger sitting still on a train at 100 km/h has zero kinetic energy in the train's frame and a large kinetic energy in the ground frame, because v depends on the observer. Third, it is the work-equivalent of the motion: the work-energy theorem states that the net work done on an object equals the change in its kinetic energy, W = ΔKE, which is why a moving body can do work on something it hits (a hammer on a nail, a car on a wall, a falling stone on a pile of clay) up to a total exactly equal to its KE before impact. Kinetic energy sits opposite gravitational potential energy U = mgh in conservation-of-energy problems near the Earth's surface: a body falling freely from rest converts U into KE as it descends, and the sum KE + U remains constant in the absence of friction. This calculator handles only the translational form ½mv²; for a rotating body you must add the rotational term ½Iω² (I = moment of inertia, ω = angular velocity), and for a non-rigid system (a spinning gymnast, a deforming car) you must in principle integrate ½v² dm over the mass distribution.

How to use this calculator.

  1. Enter the object's mass in kilograms. Convert grams to kilograms by dividing by 1000 (145 g baseball = 0.145 kg); convert tonnes by multiplying by 1000 (1.5 t car = 1500 kg); convert pounds by multiplying by 0.453592 (200 lb sprinter ≈ 90.7 kg).
  2. Enter the object's velocity in metres per second. Convert km/h by dividing by 3.6 (100 km/h = 27.78 m/s); convert mph by multiplying by 0.44704 (60 mph = 26.82 m/s); convert knots by multiplying by 0.5144.
  3. Read the primary result — kinetic energy in joules. For perspective: 1 J is roughly the energy of an apple falling 1 m, 1000 J (1 kJ) is the muzzle energy of a 9 mm pistol round, 100 kJ is a small car at 50 km/h, and 1 megajoule (1 MJ) is a small car at 160 km/h.
  4. Read the secondary result — linear momentum in kg·m/s — to verify that two objects with the same KE can carry very different momenta. A 10 g bullet at 400 m/s has the same kinetic energy as a 1 kg book moving at 40 m/s, but very different momenta (4 vs 40 kg·m/s), which is why one penetrates and the other knocks you over.
  5. For a 'how much energy is in a crash?' question, enter the vehicle mass and impact speed; the joules figure is the energy that must be dissipated by crumple zones, friction, and (worst case) the occupants' bodies during the collision.
  6. For a relativistic problem at v > ~0.1c (3 × 10⁷ m/s and up), do not trust the calculator's classical answer — switch to the relativistic correction (γ − 1)mc² discussed below, which this widget does not implement.

The formula.

KE = ½mv²

The core formula is:

KE = ½ × m × v²

with KE in joules when m is in kilograms and v is in metres per second. The secondary output is momentum:

p = m × v

in kg·m/s. The factor of ½ is not arbitrary — it falls out of the work-energy theorem when you integrate Newton's second law F = ma over distance. Starting from a body at rest and applying a constant net force F that produces acceleration a = F/m over a distance d, the body reaches velocity v² = 2ad (kinematics). The work done by the force is W = Fd = mad, and substituting d = v²/(2a) gives W = ma × v²/(2a) = ½mv². Because the body started at rest, all of that work has gone into kinetic energy: KE = ½mv². Three observations follow. First, KE scales as v² and not v, which is the source of every counter-intuitive consequence in the rest of this page — drop heights for the same impact speed, stopping distances for the same brake force, crash energies for the same vehicle. Second, KE is always non-negative because v² ≥ 0; an object at rest has zero kinetic energy, never negative. Third, KE is frame-dependent through v, while invariants like the rest mass m and the energy-momentum four-vector magnitude E² − (pc)² = (mc²)² are not — a fact that becomes essential in the relativistic generalisation. The classical formula is the low-velocity limit of the relativistic kinetic energy KE_rel = (γ − 1)mc², where γ = 1/√(1 − v²/c²). Expanding γ as a Taylor series in v/c gives γ ≈ 1 + ½(v/c)² + ⅜(v/c)⁴ + …, so (γ − 1)mc² ≈ ½mv² + ⅜mv⁴/c² + …, and the leading correction is ⅜v²/c² times the classical answer. At v = 0.1c the error from using ½mv² is about 0.4%; at v = 0.5c it is about 19%; at v = 0.9c the classical formula underestimates the true KE by more than a factor of two and you must use the relativistic form. The calculator does not switch automatically — it always returns the classical ½mv², which is correct to part-per-million precision for all everyday speeds and even for orbital and interplanetary spacecraft (the ISS at 7.66 km/s sits at v/c ≈ 2.6 × 10⁻⁵).

A worked example.

Example

A mid-size sedan with a mass of 1500 kg travelling at 100 km/h (= 27.78 m/s) has kinetic energy KE = ½ × 1500 × 27.78² = ½ × 1500 × 771.6 = 578,704 J ≈ 579 kJ, and momentum p = 1500 × 27.78 = 41,667 kg·m/s. To make the v² dependence concrete: at 50 km/h (13.89 m/s) the same car has KE = ½ × 1500 × 193 = 144,676 J ≈ 145 kJ — exactly one-quarter of the 100 km/h figure, because halving v quarters v². To stop the car from 100 km/h, the brakes must do 579 kJ of negative work, which on a typical dry asphalt road with a coefficient of friction μ ≈ 0.8 (peak braking) requires a stopping distance d = KE / (μmg) = 578,704 / (0.8 × 1500 × 9.81) ≈ 49 m. From 50 km/h the same calculation gives d ≈ 12 m — four times shorter, again because of the v² scaling. The crash-energy interpretation is even starker: hit an immovable wall at 100 km/h and 579 kJ of energy must be absorbed by the crumple zone in roughly 0.1 s and 0.7 m of crush distance, requiring an average decelerating force of about 830 kN — roughly 56 g sustained on the vehicle and a survivability boundary that modern restraint systems are designed exactly around. At 50 km/h the energy is one-quarter, the crush distance can be longer relative to the energy, and survivability is high in any car built since the 1990s. This single example — same car, same brake, only the speed changes — captures why speed limits are set where they are.

mass1,500
velocity27.78

Frequently asked questions.

What is the formula for kinetic energy?
Kinetic energy is KE = ½ × m × v², where m is mass in kilograms and v is speed in metres per second. The result is in joules (J), where 1 J = 1 kg·m²/s². The factor of ½ comes from integrating Newton's second law over distance — the work needed to accelerate a body from rest to speed v works out to exactly ½mv², so by the work-energy theorem that is also the kinetic energy the body now carries. The formula applies to the translational motion of a point mass or the centre of mass of a rigid body; rotation about the centre of mass adds a separate ½Iω² term.
Why does kinetic energy depend on velocity squared instead of just velocity?
Because the work needed to reach a given speed scales as the square of that speed. From rest, accelerating to v requires distance d = v² / (2a) at constant acceleration a, and the work done is force × distance = ma × v²/(2a) = ½mv². Equivalently, energy is the time-integral of power P = F·v, and as v increases linearly the instantaneous power increases linearly too, so the total energy delivered grows quadratically in v. Momentum p = mv scales linearly with v — that is the conserved quantity in collisions — but the energy associated with the motion scales quadratically. This is why doubling a car's speed quadruples its crash energy and its stopping distance, even though the momentum 'only' doubles.
How is kinetic energy different from potential energy?
Kinetic energy is the energy of motion; potential energy is the energy of position in a force field. A ball at rest at the top of a 10 m drop has gravitational potential energy U = mgh = m × 9.81 × 10 ≈ 98m joules and zero kinetic energy. Just before it hits the ground (ignoring air resistance) it has zero potential energy (taking the ground as h = 0) and kinetic energy ½mv² equal to the 98m joules it started with — energy has been converted from potential to kinetic but the total KE + U is conserved. Solving ½mv² = mgh gives the impact speed v = √(2gh) ≈ 14 m/s from 10 m, independent of mass. The kinetic-potential conversion runs both ways: a pendulum swings up converting KE to U, then back down converting U to KE, indefinitely in the absence of friction. Quanta has a separate gravitational potential energy calculator for the U = mgh side of the equation.
What is the relativistic correction to kinetic energy?
Classical KE = ½mv² is the low-velocity limit of the relativistic kinetic energy KE_rel = (γ − 1)mc², where γ = 1/√(1 − v²/c²) is the Lorentz factor and c = 299,792,458 m/s is the speed of light. As v → c the Lorentz factor diverges and KE_rel → ∞, which is the energy-side statement of the fact that no massive particle can reach the speed of light. The classical formula is the leading term in a Taylor expansion in v/c: KE_rel ≈ ½mv² × (1 + ¾(v/c)² + …). The fractional error from using ½mv² is approximately ¾(v/c)². At v = 0.1c (about 30,000 km/s — well beyond any chemical or fission propulsion) the error is about 0.75%. At v = 0.5c it is about 19%. At v = 0.9c the classical formula underestimates by a factor of more than two. For everyday objects — cars, bullets, satellites, even particles in a low-energy cyclotron — v/c is so small that ½mv² is accurate to many decimal places, and this calculator does not apply the correction. Use the relativistic form when v exceeds ~10% of c, which in practice means particle physics, cosmic rays, and high-energy astrophysics.
How much kinetic energy does a car have in a crash?
For a 1500 kg car at 50 km/h (13.89 m/s) it is ½ × 1500 × 13.89² ≈ 145 kJ. At 100 km/h the same car carries ≈ 579 kJ — four times the energy for double the speed, because of the v² dependence. At 150 km/h it is ≈ 1300 kJ, nine times the 50 km/h figure. In a head-on collision with an immovable barrier, all of that energy must be dissipated as deformation of the car's crumple zones and (if the occupant compartment is breached) of the occupants' bodies, on a timescale of ~100 ms. Modern passenger cars are designed so that crumple zones absorb the energy of a 50–60 km/h frontal impact while keeping cabin intrusion small enough for restraint systems to protect occupants. Above that speed, the survivability drops sharply — not linearly with speed, but quadratically with kinetic energy. This v² scaling is also why heavy vehicles are disproportionately dangerous: doubling mass at constant speed doubles KE, but doubling speed at constant mass quadruples it.
What is the difference between kinetic energy and momentum?
Kinetic energy KE = ½mv² is a scalar (no direction) with units of joules; momentum p = mv is a vector (carries direction) with units of kg·m/s. Two objects with the same kinetic energy can have very different momenta, and vice versa. A 10 g bullet at 400 m/s has KE = ½ × 0.01 × 400² = 800 J and p = 0.01 × 400 = 4 kg·m/s. A 1 kg book moving at 40 m/s has the same KE (½ × 1 × 40² = 800 J) but ten times the momentum (40 kg·m/s). In a collision, momentum is conserved (vector sum before = vector sum after) regardless of whether kinetic energy is conserved. Kinetic energy is conserved only in elastic collisions; in inelastic collisions some KE is converted to heat, sound, and deformation, while momentum is still conserved. This is why momentum determines what 'knocks you over' (impulse Δp = F Δt is what your muscles must resist) and energy determines what 'penetrates' (work F·d is what is needed to break tissue or material).
Does kinetic energy depend on the reference frame?
Yes — kinetic energy depends on the observer's frame of reference because velocity does. A passenger in a train moving at 100 km/h has zero kinetic energy in the train's reference frame (she is at rest relative to the train) and a kinetic energy of ½ × 70 × 27.78² ≈ 27 kJ in the ground frame (for a 70 kg passenger). Neither answer is wrong — they are answers to different physical questions. Frame dependence does not break conservation of energy: within any single inertial frame, total energy is conserved; you simply cannot compare KE values across frames as if they were the same quantity. The total energy E² = (pc)² + (mc²)² is closer to a frame-independent quantity at the relativistic level, but the rest mass m is the only truly Lorentz-invariant scalar. Choose a frame that simplifies the problem (usually the ground frame for everyday mechanics, the centre-of-mass frame for collision analysis) and stay in it consistently.
Does this calculator include rotational kinetic energy?
No — this calculator handles only translational kinetic energy of the centre of mass, ½mv². A rotating rigid body has an additional rotational kinetic energy KE_rot = ½Iω², where I is the moment of inertia about the rotation axis and ω is the angular velocity in rad/s. For a rolling ball or wheel the total kinetic energy is the sum KE_total = ½mv² + ½Iω², and the rolling-without-slipping constraint v = ωr links the two. For a solid uniform sphere (I = ⅖mr²) rolling without slipping, KE_rot is ⅖ × ½mv² = (2/10)mv², so total KE is ½mv² × (1 + 2/5) = (7/10)mv² — meaning a rolling sphere has 40% more kinetic energy than a sliding sphere at the same v. If your problem involves rotation, compute the rotational term separately and add it. Quanta has separate calculators for moment of inertia and rotational kinematics.
What are the units of kinetic energy?
The SI unit of energy, including kinetic energy, is the joule (J), defined as 1 J = 1 kg·m²/s² = 1 N·m = 1 W·s. Common multiples are the kilojoule (kJ = 10³ J) for food calorimetry and small-scale mechanics, the megajoule (MJ = 10⁶ J) for vehicle and industrial energy, and the gigajoule (GJ = 10⁹ J) for grid-scale electricity. Older and discipline-specific units include the calorie (1 cal ≈ 4.184 J) for thermodynamics and nutrition, the foot-pound (1 ft·lb ≈ 1.356 J) for imperial engineering, the kilowatt-hour (1 kWh = 3.6 MJ) for electric bills, and the electronvolt (1 eV ≈ 1.602 × 10⁻¹⁹ J) for particle physics. This calculator always returns joules; convert at the end of your calculation rather than mid-formula to avoid unit-conversion errors.
Why does the calculator return momentum alongside kinetic energy?
Because the two quantities together fully describe the motion of a classical point mass in a given direction, and pairs of physics problems frequently want both. Momentum p = mv tells you the impulse needed to stop the object (Δp = F Δt), which sets the timescale and force of a collision; kinetic energy KE = ½mv² tells you the work needed to stop the object (W = F d), which sets the distance and total damage potential. The two are linked by KE = p² / (2m), so given any two of {m, v, p, KE} you can reconstruct the other two. Returning both saves a step in any problem that needs to reason about both impact force (momentum-driven) and penetration / deformation (energy-driven) — which covers most collision, ballistics, and crash-safety questions you would use this calculator for.

References& sources.

  1. [1]Feynman, R. P., Leighton, R. B. & Sands, M. (1964). The Feynman Lectures on Physics, Volume I, Chapter 13 'Work and Potential Energy (A)' and Chapter 14 'Work and Potential Energy (Conclusion)'. Caltech / Addison-Wesley. The clearest first-principles derivation of why kinetic energy is ½mv² from the work integral ∫F·dx, and the original treatment of the work-energy theorem that this calculator implements.
  2. [2]Halliday, D., Resnick, R. & Walker, J. (2014). Fundamentals of Physics, 10th ed., Chapter 7 'Kinetic Energy and Work' and Chapter 8 'Potential Energy and Conservation of Energy'. Wiley. Standard university-physics treatment of the translational kinetic energy ½mv², the work-energy theorem, conservation of mechanical energy, and worked examples for collisions, springs, and gravity.
  3. [3]NIST Reference on Constants, Units, and Uncertainty — definition of the joule (J = kg·m²/s²) under the 2019 SI redefinition of base units in terms of fundamental constants (h, e, k, N_A). National Institute of Standards and Technology.
  4. [4]Einstein, A. (1905). 'Zur Elektrodynamik bewegter Körper' (On the Electrodynamics of Moving Bodies). Annalen der Physik, 17(10), 891–921. The foundational paper of special relativity, in which the relativistic kinetic energy (γ − 1)mc² and its low-velocity limit ½mv² are derived.
  5. [5]Evans, L. (2004). 'Traffic Safety'. Science Serving Society, Bloomfield Hills MI. Peer-reviewed monograph aggregating crash-test and epidemiological evidence on how vehicle kinetic energy (½mv²) maps to injury risk and fatality probability — the empirical basis for the v² scaling discussed in the car-crash example.
  6. [6]Iliffe, R. & Smith, G. E. (eds., 2016). The Cambridge Companion to Newton, 2nd ed., Cambridge University Press. Chapter on the vis viva controversy (Leibniz, Bernoulli, du Châtelet, Newtonians) tracing how mv² emerged as the conserved quantity of motion and how the factor of ½ was finalised through the work-distance integral.

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