Audited 27 Jul 2026·Last updated 28 Oct 2026·6 citations·Tier 1·0 uses

Latent Heat Calculator

Find the heat absorbed or released when a mass melts, freezes, boils, condenses or sublimes, using Q = mL with built-in values for water, ethanol and aluminium.

Latent Heat Calculator

Mass unit
Phase transition
Direction of transition
Substance
Heat energy
116,900
Heat absorbed (positive) or released (negative) as the mass changes phase, in joules.
Heat energy (kJ)
116.9
Heat energy (MJ)
0.1169
Specific latent heat used (J/kg)
334,000

Background.

Melting a kilogram of ice at 0 °C takes 334 kJ of heat, enough to warm the same kilogram of liquid water from 0 °C to almost 80 °C, yet a thermometer standing in the melting ice does not move. Boiling a kilogram of water away at 100 °C takes 2,257 kJ, more than five times the 418.6 kJ needed to bring it from freezing to the boil. That hidden energy, taken in or given out while a substance changes phase at a fixed temperature, is latent heat. It is why ice cools a drink so well, why a pan of boiling water sits at 100 °C with the burner on full, and why a steam burn is worse than a splash of boiling water.

The arithmetic is a single multiplication, Q = m × L: the mass that changes phase times the specific latent heat for that substance and transition. Water, ethanol, aluminium and nitrogen have built-in values at their normal transition temperatures under standard atmospheric pressure: 334 and 2,257 kJ/kg for water, 108 and 838 kJ/kg for ethanol, 397 kJ/kg for melting aluminium and 199.2 kJ/kg for boiling nitrogen. For anything else, including melting nitrogen, any sublimation or a material from a supplier's data sheet, you enter L yourself in kJ/kg. Say whether heat is absorbed (melting, boiling, sublimation) or released (freezing, condensation, deposition) and the answer carries a plus or minus sign to match.

What Q = mL leaves out is any change of temperature. Warming ice from freezer temperature up to 0 °C, or heating the meltwater afterwards, is sensible heat, worked out from the specific heat capacity, and a full heating or cooling load adds the two kinds together. For water the latent part is usually the bigger share, about 85% of the energy needed to turn ice at −10 °C into steam, which is why ice banks, steam plant and evaporative coolers are designed around it.

What is latent heat calculator?

Specific latent heat, L, is the energy needed to change the phase of one kilogram of a substance without changing its temperature, measured in joules per kilogram or, more conveniently, kilojoules per kilogram. The word latent comes from the Latin for hidden: Joseph Black, working in Glasgow in the 1760s, noticed that a mixture of ice and water stays at 0 °C while heat keeps flowing in, and gave the name to heat that vanishes into a change of state instead of showing on a thermometer. Each pair of phases has its own value: fusion between solid and liquid, vaporisation between liquid and gas, and sublimation straight from solid to gas. The same amount comes back out in the reverse direction, so freezing releases exactly what melting absorbed. At constant pressure, L is the same quantity chemistry tables list as the specific enthalpy of the transition.

How to use this calculator.

  1. Enter the Mass of substance and choose kilograms or grams under Mass unit. Count only the material that actually changes phase: if half of a 2 kg block melts, enter 1 kg.
  2. Pick the Phase transition: fusion for melting or freezing, vaporisation for boiling, evaporation or condensation, and sublimation for a solid turning straight into gas.
  3. Set the Direction of transition. Heat absorbed gives a positive result; heat released (freezing, condensation, deposition) gives the same size of answer with a minus sign.
  4. Choose the Substance. Water and ethanol have built-in fusion and vaporisation values, aluminium has a melting value and nitrogen a boiling value; Custom, any sublimation, melting nitrogen and boiling aluminium all need a number in the next field.
  5. Type a Custom specific latent heat in kJ/kg when you have one from a data sheet or steam table. Leave it at 0 to use the built-in figure; anything above zero replaces it, even for water.
  6. Read the heat in joules, kilojoules and megajoules, and check the specific latent heat used, shown in J/kg, to confirm which value went into the sum.

The formula.

Q = mL

Q = m × L, with m in kilograms and L in joules per kilogram, gives Q in joules. A mass entered in grams is divided by 1,000 first, and a custom L typed in kJ/kg is multiplied by 1,000. The sign records the direction of flow: positive when the substance takes heat in (melting, boiling, sublimation), negative when it gives heat out (freezing, condensation, deposition). The size is the same either way, because at the transition temperature the change can run in both directions with the same energy.

The relationship is a straight proportion, so doubling the mass doubles the heat, and the choice of L sets the scale. Vaporisation values dwarf fusion values because boiling has to pull molecules completely apart and also push the surrounding atmosphere back as the vapour expands. At 100 °C a kilogram of steam fills about 1.672 m³, against roughly 0.001 m³ as liquid, a 1,600-fold expansion. Pushing back 101,325 Pa through that volume accounts for about 169 kJ of water's 2,257 kJ/kg; the remaining 2,088 kJ goes into separating the molecules.

The built-in figures assume a pure substance changing phase at its normal transition temperature under one standard atmosphere, with the whole mass changing phase. Vaporisation is the value most sensitive to conditions: for water it is 2,501 kJ/kg at 0 °C, 2,257 kJ/kg at 100 °C, and it falls to zero at the critical point, 373.9 °C and 22.064 MPa, where liquid and vapour can no longer be told apart. Solutions such as brine or syrup freeze gradually over a range of temperatures as the remaining liquid grows more concentrated, so a single L only approximates them.

A worked example.

Example

Take 350 g of ice at 0 °C, a generous handful of cubes, and ask how much heat it must absorb to melt. Enter 0.35 kg, fusion, heat absorbed and water, and the calculator applies L = 334,000 J/kg. Q = 0.35 × 334,000 = 116,900 J, which is 116.9 kJ or 0.1169 MJ. It is positive because melting draws heat in. In a drink, that heat comes out of the liquid around the ice. Dividing 116,900 J by water's specific heat of about 4,186 J/(kg·K) and a 25 K drop shows that, through melting alone, the ice could in principle bring about 1.12 kg of water from 25 °C down to 0 °C. Cubes straight from a freezer at −18 °C do a little more: warming 0.35 kg of ice through 18 K at about 2.1 kJ/(kg·K) soaks up another 13.23 kJ before any melting starts, roughly 11% on top of the latent figure.

custom Latent Heat0
mass0.35
substancewater
mass Unitkg
transitionfusion
directionabsorbing

Frequently asked questions.

Why does a pan of boiling water stay at 100 °C with the burner on full?
Once water reaches its boiling point, extra heat goes into turning liquid into vapour instead of raising the temperature. The numbers show how lopsided this is. If a 2 kW element delivered all its output to 1 kg of water, heating it from 20 °C to 100 °C would take about 2.8 minutes (334.9 kJ), while boiling the whole kilogram away would need another 2,257 kJ, close to 19 minutes. Real pans lose heat to the air, so both times run longer in practice.
Why is the latent heat of vaporisation so much larger than that of fusion?
Melting only loosens a solid's structure: molecules in the liquid still touch and attract one another. Boiling separates them completely and, at atmospheric pressure, also does work pushing the air aside as the vapour expands. Water's vaporisation value is about 6.8 times its fusion value (2,257 against 334 kJ/kg) and ethanol's about 7.8 times (838 against 108). Hydrogen bonding makes both of water's values unusually large, one reason water is such an effective coolant.
Why does choosing sublimation, or melting nitrogen, ask me for a value?
The built-in table holds fusion and vaporisation values for water and ethanol, a fusion value for aluminium and a vaporisation value for nitrogen, nothing more. The Custom option, every sublimation, melting nitrogen and boiling aluminium therefore need a figure in the custom field, in kJ/kg. Nitrogen boiling at −195.8 °C uses the built-in 199.2 kJ/kg, taken from the NIST WebBook's saturated-liquid and vapour enthalpies at one atmosphere, so boiling off 10 kg absorbs about 1,992 kJ. For ice subliming at 0 °C, add the fusion and vaporisation values at that temperature: 334 + 2,501 = about 2,835 kJ/kg.
Does the latent heat of vaporisation change with temperature?
Yes, by more than many people expect. Water's value is 2,501 kJ/kg at 0 °C, 2,257 kJ/kg at its normal boiling point and zero at the critical point near 374 °C. The built-in figure is the 100 °C one, so for evaporation at lower temperatures, from a lake, a cooling tower or your skin, enter a steam-table value instead. Near 35 °C it is about 2,420 kJ/kg, roughly 7% above the built-in number, which is why a litre of sweat evaporated in an hour removes heat at around 670 watts.
How much heat turns 1 kg of ice at −10 °C into steam at 100 °C?
Add four steps, two sensible and two latent. Warming the ice to 0 °C takes about 2.1 kJ/(kg·K) × 10 K = 21 kJ; melting it takes 334 kJ; heating the water to 100 °C takes about 4.186 × 100 = 418.6 kJ; boiling it takes 2,257 kJ. The total is about 3,030.6 kJ, and the two latent steps covered here make up about 85% of it. The two temperature-change steps come from the specific heat formula, Q = m × c × ΔT.
How much cooling does a block of ice actually store?
Melting 5,000 kg of ice absorbs 5,000 × 334,000 = 1.67 × 10⁹ J, which is 1,670 MJ or about 463.9 kWh of cooling; ice-storage air conditioning freezes water like this at night and melts it during the day. The same physics sits behind the refrigeration ton used to rate air conditioners: originally the cooling given by melting one short ton (907 kg) of ice over 24 hours, which works out at about 3.5 kW.
Why do growers spray water on crops on a frosty night?
Because freezing water gives up its latent heat. While water keeps freezing on a bud or flower, the film of ice and water is held at 0 °C, and every kilogram that freezes releases 334 kJ to the plant and the air around it, which can keep tissue from falling to the temperature that damages it. Select heat released to see the sign: freezing 1 kg of water returns −334,000 J. The protection lasts only as long as the spraying continues.
Can I use it for salt water, syrup or other mixtures?
Only approximately. The built-in values describe pure substances with a single, sharp transition temperature. Dissolved salt or sugar lowers the freezing point, and as pure ice forms the remaining liquid becomes more concentrated, so freezing happens gradually over a range of temperatures instead of all at once. For a mixture, enter a measured latent heat from a data sheet or a calorimetry test and read the answer as an estimate.
How do I turn a molar enthalpy from a chemistry table into the value used here?
Divide by the molar mass in kilograms per mole. Water's enthalpy of fusion, about 6.01 kJ/mol, divided by 0.018015 kg/mol gives about 334 kJ/kg; its enthalpy of vaporisation at 100 °C, about 40.66 kJ/mol, gives 2,257 kJ/kg. At constant pressure the tabulated enthalpy and the specific latent heat describe the same energy, one per mole and the other per kilogram, so the converted number can go straight into the custom field.
Why does supercooled water freeze only partly when it finally freezes?
Very still, clean water can stay liquid below 0 °C. When it does begin to freeze, the latent heat released warms the remaining liquid back to 0 °C, and freezing stops once it gets there. From −10 °C, the fraction that can freeze is the sensible heat available divided by the latent heat, 4.19 × 10 ÷ 334 ≈ 0.125, so roughly an eighth of the water turns to slush at once and the rest must lose heat to its surroundings before it follows.

References& sources.

  1. [1]Black, J. (1803). Lectures on the Elements of Chemistry, delivered in the University of Edinburgh. Robison, J. (ed.). Edinburgh: Mundell and Son.
  2. [2]NIST Chemistry WebBook. Water. National Institute of Standards and Technology.
  3. [3]NIST Chemistry WebBook. Nitrogen, fluid saturation properties at 1 atm. National Institute of Standards and Technology.
  4. [4]Halliday, D., Resnick, R., and Walker, J. (2013). Fundamentals of Physics, 10th ed. John Wiley & Sons. ISBN 978-1-118-23072-5
  5. [5]Callen, H.B. (1985). Thermodynamics and an Introduction to Thermostatistics, 2nd ed. John Wiley & Sons. ISBN 978-0-471-86256-7
  6. [6]ASHRAE (2021). ASHRAE Handbook-Fundamentals, Chapter 1: Psychrometrics. American Society of Heating, Refrigerating and Air-Conditioning Engineers.

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