Audited 29 Jul 2026·Last updated 28 Oct 2026·5 citations·Tier 2·0 uses

MOI Calculator (Multiplicity of Infection)

Find the virus stock volume for a target MOI, the MOI you achieved, or cells to seed, plus the Poisson share of cells hit zero, one or several times.

MOI Calculator

What do you want to find?
An average across the population, not a per-cell dose. At MOI 1 about 36.8% of cells still receive nothing.
Cells present in the well or flask at the moment of infection — count them at that point, not at seeding, if they have divided since.
INFECTIOUS units per mL — PFU, TU or IU. A TCID₅₀ titre is about 1.43× a PFU titre (multiply by 0.7 first). Genome copies are typically 100–1000× higher; do not use them here.
/mL
Used when solving for the MOI you achieved or for the cell number to seed.
µL
Virus volume
2.5
Microlitres of stock carrying the infectious units shown: the answer in volume mode, and your entered volume in the other two.
MOI
0.5
Infectious units delivered
250,000
Cells
500,000
Cells receiving ≥ 1 particle
39.35
Cells receiving nothing
60.65
Cells receiving ≥ 2 particles
9.02

Background.

Infect a well at an MOI of 1, one infectious particle for every cell, and the reporter will come up in roughly two cells out of three rather than all of them. Nothing went wrong. Particles land on cells at random, so some cells collect two or three while others collect none, and at an average of one per cell the share left empty is e^−1, or 36.79%.

Multiplicity of infection therefore has two sides. One is bookkeeping: how many infectious units go in, and how much stock that takes. Multiply the MOI by the number of cells present, divide by the titre, and you have the volume to pipette. The same relation runs backwards to give the MOI a known volume actually delivered, or the number of cells to plate so that a fixed volume gives the MOI you want. The other side is the spread. The Poisson distribution turns any MOI into three percentages: cells that receive nothing, cells that receive at least one particle, and cells that receive two or more. Those figures shape an experiment more than the average does. At an MOI of 3 about 5% of cells still escape, while 80% have been hit more than once.

Both inputs behind the arithmetic are easy to get wrong. The cell count should be taken when the virus goes on, not when the cells were plated, because a line that has doubled in between halves the real MOI. The titre must be in infectious units: plaque-forming units, transducing units or infectious units per millilitre. A TCID₅₀ titre needs multiplying by about 0.7 to approximate PFU, and a genome-copy titre, which counts every physical particle, is often hundreds of times higher than the infectious titre and does not belong here at all.

What is moi calculator?

Multiplicity of infection is the number of infectious units added per target cell present at the moment of infection. It is a population average with no unit, so an MOI of 0.5 means half as many infectious particles as cells, not half a particle in every cell. If particles attach independently and at random, the number reaching any one cell follows a Poisson distribution with mean m equal to the MOI: P(k) = e^−m·mᵏ ⁄ k!. Shabram and Aguilar-Cordova made the point in Molecular Therapy that MOI is a statistical probability, and that reading it as a uniform dose implies a homogeneous infected population that does not exist. Epidemiology and population genetics use the term differently, for instance for the number of distinct pathogen lineages in one host; the cell-culture ratio is the meaning here.

How to use this calculator.

  1. Pick the question: the volume of stock to add, the MOI a known volume achieved, or how many cells to plate for a set volume and MOI.
  2. Enter the titre in infectious units per mL and note which assay produced it. Multiply a TCID₅₀ titre by 0.7 before entering it, and bear in mind that a titre measured on one cell line may not hold on another.
  3. Enter the cells present at infection. Counting a spare well just before adding virus beats relying on the seeding number.
  4. Enter the MOI you want, or the volume you added, and read the three Poisson percentages. If too many cells stay empty, raise the MOI; if multiple hits would spoil the readout, lower it.
  5. If the volume comes out below about 1 µL, dilute the stock first and enter the diluted titre, since very small volumes are hard to pipette accurately.

The formula.

IU = MOI × N · V(µL) = IU ⁄ titre × 1000 · P(k) = e^(−m)·mᵏ ⁄ k!

The bookkeeping is one equation. Infectious units needed are IU = MOI × N, where N is the number of cells, and the volume is V = IU ÷ titre × 1000, the factor of 1000 turning a per-millilitre titre into microlitres. Solving the same relation for the MOI gives titre × V ÷ 1000 ÷ N, and solving for cells gives titre × V ÷ 1000 ÷ MOI. Doubling the cell count doubles the volume; doubling the titre halves it.

The percentages come from assuming every particle attaches independently and every cell is equally likely to receive it. With m particles per cell on average, the fraction of cells receiving exactly k is e^−m·mᵏ ⁄ k!, the form Figliozzi and colleagues used to back-calculate MOI from imaging data. Setting k = 0 gives the empty fraction, e^−m, and its complement 1 − e^−m is the infected fraction. Removing the single-hit term m·e^−m as well leaves the share hit two or more times, 1 − e^−m − m·e^−m. The empty fraction shrinks slowly: from 36.79% at MOI 1 it takes an MOI of 5 to get below 1% (0.67%).

The volume arithmetic holds however the virus spreads; the percentages do not. For a given average, equal susceptibility gives the largest possible infected fraction, so uneven receptor levels or edge effects in a monolayer leave more cells empty than predicted. Spinoculation, polybrene, or a target line different from the one used for titration change how many particles actually attach, which shifts the effective MOI itself.

A worked example.

Example

A well holds 500,000 cells when the virus goes on, the stock is titred at 1 × 10⁸ PFU/mL, and the protocol asks for an MOI of 0.5. The infectious units needed are 0.5 × 500,000 = 250,000. Dividing by the titre gives 250,000 ÷ 100,000,000 = 0.0025 mL, and multiplying by 1000 gives 2.5 µL of stock. For the spread, e^−0.5 = 0.6065, so 60.65% of cells receive nothing and 39.35% receive at least one particle. The single-hit share is 0.5 × 0.6065 = 30.33%, which leaves 39.35 − 30.33 = 9.02% of cells with two or more. Among the cells that were infected at all, 9.02 ÷ 39.35 ≈ 0.23, so nearly one in four carries more than one particle at a dose of half a particle per cell.

virus Volume Ul2.5
viral Titre100,000,000
cell Count500,000
target Moi0.5
solve ForvirusVolume

Frequently asked questions.

Why are only about 63% of my cells infected at MOI 1?
Because random arrival leaves e^−1 = 36.79% of cells with no particle, so at most 63.21% can be infected. Pushing the empty share down costs a lot of virus: MOI 3 still leaves 4.98% uninfected and MOI 5 leaves 0.67%, by which point 95.96% of all cells have received two or more particles.
How do I convert a TCID₅₀ titre to PFU?
Multiply by about 0.7. ATCC derives the factor from the same Poisson model: at the TCID₅₀ endpoint half the wells are negative, so e^−m = 0.5 and m = −ln 0.5 ≈ 0.7, though ATCC recommends measuring PFU directly. Skip the step with a 1 × 10⁸ TCID₅₀/mL stock and 2.5 µL delivers an MOI of 0.35, not 0.5; the correct volume is 3.5714 µL.
Can I use a genome-copy titre from qPCR?
No. Genome copies count every physical particle, including those that cannot infect, and typically run 100 to 1,000 times higher than an infectious titre. Entering one would overstate the MOI by that factor. Use a functional titre instead, ideally transducing units measured on the same cell line you plan to infect.
What if I used the seeding count and the cells had doubled?
Then your real MOI is half what you planned. Virus calculated for 500,000 cells at MOI 0.5 but added to 1,000,000 cells gives an MOI of 0.25, and the infected share drops from 39.35% to 22.12%. For a fast-growing line, a day or two between plating and infection is enough for this to happen.
What MOI keeps most infected cells to a single particle?
A low one, at the cost of efficiency. Pooled CRISPR screens commonly transduce at around MOI 0.3: 25.92% of cells receive a particle and 3.69% receive two or more, so about one transduced cell in seven carries extra copies. At MOI 0.1 that falls to about one in twenty, but only 9.52% of cells are transduced, so a selection step is usually needed afterwards.
My measured infection rate does not match the prediction. Which number is wrong?
Often neither: the Poisson figures assume equal access and equal susceptibility. You can work backwards from what you measured with m = −ln(1 − infected fraction), the inverse Poisson used by Figliozzi and colleagues; 30% infected corresponds to an effective MOI of 0.3567. A 2022 review on viral vectors argues for reporting measured transduction efficiency alongside MOI for this reason.

References& sources.

  1. [1]Figliozzi RW, Chen F, Chi A, Hsia SV (2016). "Using the inverse Poisson distribution to calculate multiplicity of infection and viral replication by a high-throughput fluorescent imaging system." Virologica Sinica. States the distribution used here: "P{n}=m^n e^-m/n!" where m is the MOI, and "P{0}=e^-m"; inverted as m = −ln(1 − P{n>0}). Retrieved 2026-07-29.
  2. [2]ATCC, Virology Culture Guide. Independent second authority. Defines MOI as "The ratio of agents (eg, viruses, bacteriophages, bacteria) to infection targets (eg, propagation host)", and derives the TCID₅₀-to-PFU factor from the same Poisson model: "For any titer expressed as TCID50, P(o)=0.5. Thus, e(-m)=0.5 and m= -ln 0.5, which is ≈0.7." Adds that "ATCC recommends that the actual number of PFUs be determined empirically." Retrieved 2026-07-29.
  3. [3]Shabram P, Aguilar-Cordova E (2000). "Multiplicity of Infection/Multiplicity of Confusion." Molecular Therapy 2(5):420–421. Commentary: MOI "is misleading because it implies a homogeneous infected cell population, yet it is a statistical probability with a Poisson distribution." Publisher PDF returned HTTP 403 to automated retrieval; abstract and quoted text confirmed via the publisher's indexed record, 2026-07-29.
  4. [4]"The many definitions of multiplicity of infection" (2022). Frontiers in Epidemiology. Independent third field: writes the same Poisson kernel as κₘ = e^−λλᵐ/m!, and states that "MOI is not universally defined. Competing definitions vary from verbal ones to those based on concise statistical frameworks." Retrieved 2026-07-29.
  5. [5]"Lost in transduction: Critical considerations when using viral vectors" (2022). Frontiers in Cell and Developmental Biology. "The relationship between lentiviral dose, transduction efficiencies, and multiple viral integrations is explained by the Poisson distribution." Argues MOI is problematic for heterogeneous cell populations and that transduction efficiency should be reported. Retrieved 2026-07-29.

How this page was produced

Published by
Quanta Calculator
Primary sources
5 cited below
Method
IU = MOI × N · V(µL) = IU ⁄ titre × 1000 · P(k) = e^(−m)·mᵏ ⁄ k!
Published
Last verified

Built with AI assistance and verified by automated tests against the cited sources — every worked example on this page is computed by the same code that runs the calculator. How we build and check calculators.

In this category

Embed

Quanta Pro

Paid features are coming later.

  • All 1560 calculators remain free
  • No billing is enabled
Coming soon