Audited 27 Jul 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Stress-Strain Calculator (from a Known Modulus)

Predict axial stress, strain and stretch for a bar of known Young's modulus: enter force in newtons, area in m², length in metres and E in GPa.

Stress-Strain Calculator

Force applied along the member's axis. Positive for tension (pulling), negative for compression.
Cross-sectional area perpendicular to the applied force, in square metres. 0.0005 m² = 500 mm².
Unloaded length of the member before force is applied.
Known material stiffness, e.g. steel ≈ 200, aluminum ≈ 69, wood (along grain) ≈ 11, concrete ≈ 25. Look this up in a materials table rather than measuring it here — use the youngs-modulus calculator if you need to derive it from test data instead.
Stress (σ)
100,000,000
Axial stress in pascals, force divided by area; negative for compression.
Stress (σ)
100 MPa
Strain (ε)
5.000 × 10⁻⁴
Deformation (ΔL)
0.0015 m

Background.

Hang 50 kN from a 3-metre steel rod with a 500 mm² cross-section and it gets longer by one and a half millimetres. You will not see that, but a designer setting a turnbuckle's adjustment range, checking that a shaft still clears its housing under load, or deciding whether a cable will sag too far needs exactly that number, along with how hard the steel is working to carry the load.

Three linked quantities give both answers. Stress is force divided by the area resisting it, measured in pascals or, more usefully, megapascals. Strain is the fractional change in length, a pure ratio. Within the elastic range the two are tied together by the material's Young's modulus, E, so if you know E you can go from load to stress to strain to an actual change in length in three short steps.

That is the direction worked here: force, area, length and a modulus looked up from a materials table go in; stress, strain and the change in length come out. The reverse problem, measuring a specimen's stretch to find E, belongs to the Young's modulus calculator.

The straight-line relationship only holds while the material stays elastic, meaning it springs back fully once unloaded. Mild structural steel stops doing that at about 250 MPa. Nothing here knows your material's yield strength, so it will compute a tidy-looking stretch for a stress that would in reality bend the bar permanently. Comparing the stress result with a published yield strength for your exact grade is the check that makes the deformation figure worth using.

What is stress-strain calculator?

Axial stress, σ, is the internal force per unit area in a member loaded along its length: σ = F/A, in pascals (N/m²). Strain, ε, is the change in length divided by the original length, a dimensionless ratio often quoted as a percentage or in microstrain. Young's modulus, E, is a material's stiffness in tension and compression, the ratio σ/ε in the elastic region, and is tabulated in gigapascals. Deformation, ΔL, is the actual change in length, positive for stretching and negative for shortening.

How to use this calculator.

  1. Enter the axial force in newtons: positive for tension, negative for compression. A load given as a mass in kilograms is converted by multiplying by 9.81, so a 5,100 kg hanging load is about 50,000 N.
  2. Enter the cross-sectional area in square metres, perpendicular to the force. Divide square millimetres by 1,000,000, so 500 mm² is 0.0005 m²; for a round bar of diameter d in mm, the area in mm² is π × d² ÷ 4.
  3. Enter the unloaded length in metres. The change in length comes back in metres too, so 0.0015 means 1.5 mm.
  4. Enter Young's modulus in GPa from a materials table: about 200 for steel, 69 for aluminium, 11 for wood along the grain and 25 for concrete. Use the value for your actual alloy or grade where you can find it.
  5. Compare the stress in MPa with the yield strength of your material and grade before relying on the strain and deformation figures.

The formula.

σ = F ⁄ A, ε = σ ⁄ E, ΔL = ε × L₀

Three equations are applied in order. Stress: σ = F ÷ A. Strain: ε = σ ÷ E, with E converted from gigapascals to pascals by multiplying by 10⁹. Deformation: ΔL = ε × L₀. Substituting the first two into the third gives the familiar single form ΔL = F·L₀ ÷ (A·E), which shows at a glance what controls the stretch: it grows in proportion to load and length and shrinks in proportion to area and stiffness. Swap a steel member (200 GPa) for an aluminium one (69 GPa) of the same size and the stretch goes up by a factor of 200 ÷ 69, about 2.9.

The model behind these lines is Hooke's law applied to a prismatic bar: a uniform cross-section along the whole length, a force acting through the centroid along the axis, a homogeneous material, and stresses below the proportional limit. The area used is the original one, the engineering-stress convention found in mechanics-of-materials texts; the slight narrowing of a bar under tension is ignored, which is accurate at elastic strains. Bending, self-weight, temperature change and stress concentrations at holes or shoulders are all outside it. A bar with steps in its section can still be handled by running each length separately and adding the deformations.

A worked example.

Example

A 3-metre steel tie rod carries a 50,000 N tensile load, roughly the weight of 5.1 tonnes. Its cross-section is 0.0005 m², or 500 mm², which is a round bar a little over 25 mm in diameter, and the steel's modulus is taken as 200 GPa. Stress is 50,000 ÷ 0.0005 = 100,000,000 Pa, or 100 MPa. Strain is that stress over the modulus: 100,000,000 ÷ 200,000,000,000 = 0.0005, a stretch of 0.05%. The change in length is 0.0005 × 3 = 0.0015 m, so the rod lengthens by 1.5 mm. At 100 MPa the rod is working at 40% of the 250 MPa yield strength of ordinary mild structural steel, so the elastic assumption holds and the 1.5 mm will disappear when the load comes off. The same rod would reach 250 MPa at 125,000 N; past that, the stretch would no longer follow the straight-line prediction.

area0.001
original Length3
force50,000
youngs Modulus G Pa200

Frequently asked questions.

What does a strain of 0.0005 actually mean?
It means every metre of the member gets 0.0005 m, half a millimetre, longer. Engineers often write this as 500 microstrain or 0.05%. Elastic strains in metals are small: mild steel at 250 MPa yield and 200 GPa modulus reaches a strain of only 0.00125 before it starts to deform permanently.
How do I find the area of a round bar or a tube?
For a solid round bar of diameter d, the area is π × d² ÷ 4; a 25 mm bar has about 490.9 mm². For a tube, subtract the inner circle from the outer one. Work in millimetres if that is easier, then divide by 1,000,000 to enter square metres. Always use the net area at the narrowest section.
Is a compression result reliable for a long, slender column?
Only if the column does not buckle. A long, thin member in compression can bow sideways and fail at a stress far below the material's yield strength, and these equations know nothing about that. The shortening they predict applies to short, stocky members, or to slender ones checked separately for buckling.
Why does my answer not match a tensile test past the yield point?
Beyond yield, the material no longer follows a straight line: strain grows much faster than stress and part of it becomes permanent. The equations here keep extrapolating the elastic slope, so for any stress above yield they underestimate the real stretch, sometimes by a wide margin.
Which Young's modulus should I use for steel or aluminium?
About 200 GPa covers most carbon and alloy steels, and about 69 GPa covers common aluminium alloys. Stiffness varies far less between grades than strength does, so a high-strength steel stretches about as much as mild steel under the same stress. Wood and concrete vary much more, so use a figure for the actual species, grade or mix.
Does a stronger material stretch less?
Not necessarily. Strength and stiffness are different properties. A high-strength aluminium alloy can carry more stress before yielding than mild steel, yet at the same stress it stretches about 2.9 times as much, because its modulus is about 69 GPa against steel's 200 GPa. Stretch depends on modulus; how much load it survives depends on strength.

References& sources.

  1. [1]OpenStax. University Physics Volume 1, Section 12.3 'Stress, Strain, and Elastic Modulus' — defines stress σ = F/A, strain ε = ΔL/L₀, and Young's modulus E = σ/ε, rearranged here to predict σ, ε, and ΔL from a known E.
  2. [2]National Institute of Standards and Technology (NIST). SI unit definitions — the pascal (Pa = N/m²) as the SI-derived unit of stress.
  3. [3]Gere, J. M., & Goodno, B. J. (2013). Mechanics of Materials, 8th edition, Chapter 1 (Tension, Compression, and Shear) — the elastic-range stress-strain-deformation relationship and the engineering-stress convention. Cengage Learning.

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σ = F ⁄ A, ε = σ ⁄ E, ΔL = ε × L₀
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