Audited 31 Jul 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Wheatstone Bridge Calculator

Find the unknown resistance that balances a Wheatstone bridge from the other three arms: Rx = R2 × R3 ÷ R1, with all resistances in ohms.

Wheatstone Bridge Calculator

Ω
Ω
Ω
Balanced unknown resistance
330
The resistance, in ohms, that the unknown arm Rx must have for the bridge to balance with zero detector current.
Model scope
Ideal zero-detector-current balance with the arm labeling shown; lead/contact resistance, source loading, detector sensitivity, self-heating, and uncertainty are outside it.

Background.

Measuring a resistance by passing a current through it and reading the voltage works, but the answer can be no better than the two meters involved. The Wheatstone bridge, popularised by Charles Wheatstone in 1843, sidesteps that problem. It compares the unknown resistor against known ones and looks for a single condition, zero current through a detector, which can be judged far more precisely than any absolute reading.

The circuit is two voltage dividers side by side, fed from the same source. One divider is made of R1 and R2; the other of R3 and the unknown Rx, with R1 and R3 joined to the same supply terminal. A sensitive detector, traditionally a galvanometer, bridges the two midpoints. When the ratio R1 : R2 matches the ratio R3 : Rx, the midpoints sit at the same voltage, no current flows through the detector, and the bridge is said to be balanced. At that point the unknown follows from simple proportion.

A useful property of the balance is that it does not depend on the supply voltage. A drifting battery shifts both dividers together, so the null stays where it is. That is why bridges remain at the heart of precision measurement and of sensors. Strain gauges, platinum resistance thermometers and load cells all change resistance slightly under strain, heat or weight, and a bridge turns those small changes into a measurable signal.

The arithmetic here is the ideal balance only. The resistance of leads and contacts, heating of the resistors by the measuring current, the detector's limited sensitivity and the tolerance of the known resistors all affect a real measurement and are not included.

What is wheatstone bridge calculator?

A Wheatstone bridge is a four-arm resistor network used to find an unknown resistance by balancing it against three known ones. The bridge is balanced when the voltage across the detector, and so the current through it, is zero. That happens when R1/R2 = R3/Rx, giving Rx = R2 × R3 ÷ R1. The value reported here is the resistance Rx must have for the bridge to be in balance with the three arms you enter.

How to use this calculator.

  1. Identify the arms. R1 and R2 are the pair in series on one side of the bridge; R3 is the arm on the other side that connects to the same supply terminal as R1, and Rx sits in series below it.
  2. Enter R1, R2 and R3 in ohms, converting kilohms or megohms first, so 2.2 kΩ becomes 2,200.
  3. If you balanced the bridge by adjusting R3, enter the setting at which the detector read zero.
  4. Read the balanced unknown resistance in ohms. If it looks implausible, check that R1 and R2 were not entered the wrong way round, which inverts their ratio.

The formula.

R_x = R_2R_3 / R_1

Rx = R2 × R3 ÷ R1. At balance the two midpoint voltages are equal, so each side divides the supply in the same proportion: R2/(R1 + R2) = Rx/(R3 + Rx). Cross-multiplying and cancelling the common term reduces this to R1 × Rx = R2 × R3. The ratio R2/R1 therefore acts as a multiplier on R3; with equal ratio arms, Rx simply equals R3. No constants or supply voltage appear in the result. Because Rx is a product and quotient of the three known resistances, their relative errors combine: three resistors each within 0.1% can leave Rx uncertain by as much as about 0.3% in the worst case. Labelling matters as much as precision, since swapping R1 and R2 gives an entirely different answer.

A worked example.

Example

In a bench bridge, the ratio arms are fixed at R1 = 100 Ω and R2 = 150 Ω. The adjustable arm R3 is turned until the galvanometer reads zero, which happens at 220 Ω. The ratio arms give a multiplier of 150 ÷ 100 = 1.5. Applying it to the adjustable arm, Rx = 150 × 220 ÷ 100 = 33,000 ÷ 100 = 330 Ω. Had the two ratio arms been wired the other way round, with 150 Ω as R1 and 100 Ω as R2, the same null at 220 Ω would mean an unknown of 100 × 220 ÷ 150 ≈ 146.667 Ω, which is why the arm labels matter as much as the readings.

resistance R1 Ohm100
resistance R2 Ohm150
resistance R3 Ohm220

Frequently asked questions.

Why does a balanced bridge not depend on the battery voltage?
Both sides of the bridge are voltage dividers fed from the same source. At balance they divide it in identical proportions, so if the supply rises or falls, both midpoints move together and stay equal. The supply affects only how sensitive the detector is near balance.
How is a Wheatstone bridge used with a strain gauge?
The gauge forms one arm of a bridge that is balanced at rest. When the part it is bonded to stretches or compresses, the gauge's resistance changes slightly and the bridge produces a small output voltage very nearly proportional to the strain. That output, rather than the balance resistance computed here, is what the instrument reads.
Why is the bridge not used for very small resistances?
Below about an ohm, the resistance of the connecting leads and contacts becomes comparable to the resistor being measured and is wrongly added to it. A Kelvin double bridge or a four-terminal measurement separates the current and voltage connections to remove that error.
What if I cannot get the detector to read exactly zero?
Use the setting with the smallest detector reading, and if R3 adjusts in steps, note the readings on either side of the null. The true balance lies between them, and the gap between the two Rx values they produce is a fair measure of your resolution.
How accurate is a resistance found this way?
No more accurate than the three known resistors and the detector's ability to see a null. With resistors each within 0.1%, the worst-case uncertainty in Rx is about 0.3%, plus any error from lead resistance or from resistors warming under the measuring current.

How this page was produced

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Quanta Calculator
Primary sources
3 cited below
Method
R_x = R_2R_3 / R_1
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