Audited 29 Jul 2026·Last updated 31 Jul 2026·6 citations·Tier 1·0 uses

Series Resistor Calculator

Add up to 20 resistors in series. Get the total, the worst-case tolerance window, the volts and watts at your current, and the nearest stock value.

Series Resistor Calculator

Two to twenty values, separated by commas or spaces. Engineering suffixes work: 4.7k, 1M, 2.2G. Lower-case m is refused on purpose — it means milli in SI and mega in careless shorthand, and the difference is a factor of a billion.
The tolerance the whole chain is built from — 5 for a gold band, 1 for a brown band, 0 to switch the worst-case window off. Assumes every resistor in the chain shares it.
%
In amperes. 20 mA is 0.02. The same current flows through every resistor in a series chain, which is what makes the voltage and power figures below meaningful.
A
Total resistance
1,020
The sum of every resistor in the chain. This is the marked, nominal total — the real chain sits somewhere inside the worst-case window below.
Written as
1.02 kΩ
Resistors in the chain
3
Worst-case low
969 Ω
Worst-case high
1,071 Ω
Voltage across the chain
20.4 V
Power dissipated
0.408 W
Which resistor dominates
470 Ω is the largest resistor in the chain and carries 46.08 % of the total resistance, so it also takes 46.08 % of the voltage and dissipates 46.08 % of the power.
Could one resistor do it?
Nearest E24 (±5 % series) value: 1 kΩ (1.96 % below your total). Nearest E96 (±1 % series) value: 1.02 kΩ — an exact match, so a single resistor would do.

Background.

Resistors in series add. That single sentence is the whole arithmetic of this page, and it is genuinely that simple — but the reason people reach for a series resistor calculator is almost never the addition. It is one of three follow-up questions that the addition alone does not answer: whether the chain still hits its target once every part is at the wrong end of its tolerance, how much power the chain has to get rid of and which resistor gets the worst of it, and whether the whole exercise is unnecessary because a single stock resistor would land close enough anyway. This calculator answers all four at once.

Enter between two and twenty resistors, the tolerance they share, and the current you expect to push through them. Engineering shorthand works, so 4.7k and 1M are read the way you would say them out loud. The one shorthand deliberately refused is a lower-case m, because it means milli in SI and mega on a hastily drawn schematic, and silently choosing one of those over the other is a factor of a billion. Better to ask.

The physics is Kirchhoff's voltage law. A series chain has exactly one path for current, so the same current flows through every element in it. The voltage dropped across each resistor is that shared current times its own resistance, and the total voltage across the chain is the sum of those drops. Divide both sides by the shared current and the currents cancel, leaving the rule quoted in every circuits text: R_series equals R1 plus R2 plus R3, all the way to Rn. OpenStax states it in exactly that form in University Physics Volume 2, and it is the first reduction taught in MIT's 6.002.

One consequence of that shared current is worth pulling out of the maths, because it decides which part in your chain gets hot. Since every resistor carries the same current, the power each dissipates is I squared times its own resistance — so power splits in exactly the same proportion as resistance does. In a chain of 220 Ω, 330 Ω and 470 Ω, the 470 Ω resistor carries 46 % of the total resistance, drops 46 % of the total voltage and dissipates 46 % of the total heat. The calculator names that resistor and prints its share, because sizing the wattage of the whole chain from the total is a mistake: it is the dominant resistor that decides whether a quarter-watt part will do.

The tolerance result contains the page's most useful counter-intuitive fact. Adding three ±5 % resistors does not give you a ±15 % chain. If every resistor shares the same tolerance t, then the worst-case total is the sum of every value at (1 − t), which factorises straight back to (1 − t) times the nominal total. The percentage is unchanged. What does grow is the absolute window: ±5 % of 1,020 Ω is ±51 Ω where ±5 % of 220 Ω is only ±11 Ω. So a series chain does not degrade your accuracy in relative terms, which is a real reason to prefer it over other ways of hitting an awkward value. This holds only when the parts genuinely share a tolerance; mix a ±1 % part with a ±10 % part and the chain's window has to be worked out term by term.

Finally, the stock-value check exists because the honest answer to a lot of series-resistor questions is "do not bother". IEC 60063 defines the E24 series of twenty-four values per decade that ±5 % resistors are made in, and the E96 series of ninety-six values that ±1 % parts are made in. If your carefully summed 16.2 kΩ is within 1.2 % of a stock 16 kΩ, and you are using ±5 % parts, the chain is buying you nothing but two extra solder joints and two extra things to go wrong. The calculator tells you the nearest value in both series and the error each would introduce, so you can make that call with a number rather than a hunch.

One scope limit, stated up front: this is a DC and low-frequency model. It ignores the lead inductance and end-to-end capacitance that make a long chain of resistors behave differently at radio frequencies, and it ignores the way each resistor's value drifts with its own temperature once it is dissipating power.

What is series resistor calculator?

A series connection is one in which components are joined end to end so that there is exactly one path for current. Every element in the chain therefore carries the identical current — not a similar current, the same one — and that constraint is what produces every result on this page.

Because the current is shared, Ohm's law gives the voltage across each resistor as V_i = I x R_i. Kirchhoff's voltage law says the drops around the loop must sum to the applied voltage, so V_total = I x R1 + I x R2 + … + I x Rn = I x (R1 + R2 + … + Rn). Comparing that with V_total = I x R_series identifies the equivalent resistance of the chain as the plain sum of its parts.

That result has three practical corollaries. The total is always larger than the largest single resistor in the chain, which is why series connection is the way to make a bigger value out of smaller ones. The voltage divides in proportion to resistance, which is the basis of the voltage divider. And the power divides in the same proportion, because P_i = I² x R_i with I common to all of them.

Series chains are used to reach a value that is not manufactured, to spread heat across several physically small parts instead of one large one, and to raise the voltage a string can withstand — three 200 V-rated resistors in series share the applied voltage and can stand roughly three times as much across the chain as one alone. They are not a way to improve precision: the relative tolerance of the chain is the relative tolerance of the parts.

How to use this calculator.

  1. Type the resistors into the list, separated by commas. Use the values printed on the parts, not the values you measured — the tolerance window below is what turns nominal values into a real range.
  2. Use engineering shorthand if it is quicker: 4.7k, 10K, 1M and 2.2G are all read correctly. Write 0.001 rather than 1m; a lower-case m is refused rather than guessed at.
  3. Set the tolerance to the one your parts share — 5 for a gold band, 1 for brown, 2 for red. If your chain mixes tolerances, run it once at the loosest value to get a conservative window.
  4. Enter the current you expect through the chain, in amperes. Twenty milliamps is 0.02. If you do not know it yet, leave it at the default and come back once the rest of the circuit is settled — the resistance results do not depend on it.
  5. Read the total, then immediately read the worst-case low and high beside it. If your circuit only works between two limits, those are the two numbers that have to fit, not the nominal total.
  6. Check which resistor dominates. In series it takes the largest share of voltage and heat, so it is the one whose power rating you have to size first.
  7. Read the stock-value line before you build anything. If a single E24 or E96 resistor lands inside your tolerance, use it — fewer parts, fewer joints, less to go wrong.
  8. If the power figure is more than about half of your resistors' combined rating, size up. Rated dissipation on a resistor datasheet is quoted at an ambient temperature — commonly 70 °C — and falls away above it.

The formula.

R_series = R₁ + R₂ + … + Rₙ V = I·R_series P = I²·R_series

The series rule follows from one constraint and one law. The constraint is that a series path has no branches, so the current I is identical in every element. The law is Kirchhoff's voltage law: around any closed loop, the sum of the voltage drops equals the sum of the sources.

Apply Ohm's law to each resistor: V₁ = I·R₁, V₂ = I·R₂, and so on. Sum them: V_total = I·R₁ + I·R₂ + … + I·Rₙ. Factor out the common current: V_total = I·(R₁ + R₂ + … + Rₙ). Since by definition V_total = I·R_series, the equivalent resistance is R_series = R₁ + R₂ + … + Rₙ. Nothing is approximated and no ordering matters, which is why shuffling the chain changes nothing.

The dissipation results come from the same shared current. Total power is P = I²·R_series, and each resistor's own share is P_i = I²·R_i, so P_i / P = R_i / R_series. Power divides in exactly the same ratio as resistance. That is why this page names the largest resistor and prints one percentage that simultaneously describes its share of the resistance, of the voltage and of the heat.

The tolerance window assumes every resistor carries the same fractional tolerance t. The worst-case low total is Σ Rᵢ(1 − t), which factorises to (1 − t)·Σ Rᵢ, and the worst-case high is (1 + t)·Σ Rᵢ. The relative window is therefore exactly t, unchanged by the number of resistors — the chain is no less accurate, in percentage terms, than a single part would be. This is a statement about the worst case, not a statistical one; if the parts are independently distributed the realistic spread is narrower still, but that is a manufacturing-distribution argument the datasheet does not guarantee.

Rounding happens once, at the end. Every intermediate step is exact decimal arithmetic at forty significant digits, so 0.1 + 0.2 comes back as 0.3 rather than 0.30000000000000004, and the returned numbers are rounded to ten decimal places only as they cross the boundary out of the calculator. The stock-value comparison is made against the unrounded total, using exact integer mantissas from the E24 and E96 tables, so it cannot be thrown off at a boundary by floating-point error.

A worked example.

Example

You need 16.2 kΩ for a feedback network and the parts drawer has 10 k, 4.7 k and 1.5 k ±1 % resistors. In series they add: 10,000 + 4,700 + 1,500 = 16,200 Ω, displayed as 16.2 kΩ. The tolerance window is the total scaled by 1 ∓ 0.01, giving 16,038 Ω to 16,362 Ω. Note what did not happen: three ±1 % parts did not become a ±3 % chain. The window is ±1 % of the total, exactly as it would be for a single ±1 % resistor — it is the absolute width, ±162 Ω, that grew. At the 0.5 mA the circuit runs, the chain drops V = 0.0005 x 16,200 = 8.1 V and dissipates P = 0.0005² x 16,200 = 0.00405 W, about four milliwatts. That is nothing for any real resistor, but the split still matters in principle: the 10 kΩ part carries 10,000 / 16,200 = 61.73 % of the resistance, so it drops 61.73 % of the 8.1 V and takes 61.73 % of the heat. Then the stock check. The nearest E24 value to 16,200 Ω is 16 kΩ, which is 1.23 % below the target; the nearest E96 value is 16.2 kΩ exactly, because 162 is one of the ninety-six E96 mantissas. So if the design can live with 1.23 %, a single 16 kΩ resistor replaces the whole chain — and if it cannot, a single 16.2 kΩ ±1 % part exists and is a better answer than three parts in a row. That is the check worth running before reaching for the soldering iron.

current0.001
tolerance Percent1
resistances10000, 4700, 1500

Frequently asked questions.

Do resistor tolerances add up when you put resistors in series?
Not as a percentage, provided every resistor shares the same tolerance. Three ±5 % resistors in series give a ±5 % chain, not a ±15 % one. The reason is algebraic: the worst-case low total is R₁(1−t) + R₂(1−t) + R₃(1−t), and the (1−t) factors straight out, leaving (1−t) times the nominal total. What does grow is the absolute window in ohms — ±5 % of 1,020 Ω is ±51 Ω, where ±5 % of a single 220 Ω part is only ±11 Ω. If your chain mixes tolerances, the factorisation no longer works and you have to sum the worst cases term by term; running this calculator at the loosest tolerance in the chain gives you a safe over-estimate.
Which resistor in a series chain gets hottest?
The largest-value one, and by an exactly predictable margin. Every resistor in a series chain carries the same current, so each dissipates P = I² × its own resistance. Power therefore splits in the same ratio as resistance: a 470 Ω resistor in a 1,020 Ω chain takes 46 % of the total heat. This page names that resistor and prints its share. It matters because sizing the whole chain from the total power under-rates the dominant part — a chain dissipating 0.4 W across three resistors does not put 0.13 W into each of them.
How do I make a value that is not sold, like 16.2 kΩ?
Series addition is the usual way: pick stock values that sum to your target, ideally with one large resistor doing most of the work and smaller ones trimming. But check the stock line on this page first, because 16.2 kΩ is a real E96 value and does not need making at all. In general, ±1 % E96 parts cover ninety-six values per decade, which is dense enough that a single resistor is usually within 0.5 % of anything you want. Series combinations earn their place when you need a value between E96 points, when you want to raise the voltage rating of the string, or when you only have a limited kit of parts to hand.
Does the order of the resistors matter?
Not for the total, the tolerance window or the power. Addition is commutative and the current is identical everywhere in the chain, so any ordering gives the same electrical result — and this calculator returns the same numbers whichever way you type them. Order can matter physically: if one resistor runs much hotter than the rest, spacing it away from temperature-sensitive parts is worth doing, and on a printed circuit board a long chain's layout affects stray capacitance at high frequencies.
Why is the total always bigger than the biggest resistor?
Because every resistor adds another obstacle to the same single current path, and none of them can subtract. That is the structural difference from a parallel connection, where adding another resistor gives the current an extra route and always lowers the equivalent resistance below the smallest branch. Series raises, parallel lowers. If you need a value smaller than any part you have, you need the parallel calculator, not this one.
How much power will my series chain dissipate?
P = I² × R_total, which this page computes from the current you enter. If you know the voltage across the chain instead of the current, the equivalent forms are P = V²/R_total and P = V × I. Once you have the number, compare it against the parts you plan to use — but do so knowing that a resistor's rated dissipation is quoted at a stated ambient temperature, commonly 70 °C on a datasheet, and falls off linearly above it toward the maximum permissible film temperature. Vishay's leaded metal-film parts, for instance, are rated 0.4 W and 0.6 W at 70 °C with a 155 °C film limit. The companion resistor wattage page works that derating out and recommends a rating.
Can I put resistors in series to handle more voltage?
Yes, and it is a legitimate technique. Every resistor has a maximum operating voltage in its datasheet independent of its power rating — 200 V for a Vishay MRS16, 350 V for an MRS25, 500 V for a 2512 chip — and on high-value resistors that voltage limit binds long before the power limit does. Three identical resistors in series share the applied voltage equally, so the string withstands roughly three times what one part can. The catch is that the sharing is only equal if the resistors are well matched; tolerance spread and differing leakage make one part take more than its share, so high-voltage divider strings are built from tight-tolerance parts and generously derated.
What does the E24 and E96 line mean?
It is a reality check on whether the chain is worth building. IEC 60063 defines the preferred value series that resistors are actually manufactured in: E24 has twenty-four values per decade and pairs with ±5 % parts, E96 has ninety-six and pairs with ±1 % parts. This calculator finds the closest value in each series to your total and reports the percentage error you would accept by using a single part instead. If the E24 error is smaller than the tolerance of the parts you are using, the chain is not buying you accuracy — it is just adding solder joints.
Why does the calculator refuse a lower-case m in the resistor list?
Because it genuinely means two different things and both are common. In SI, m is milli, so 1m is a milliohm. On hand-drawn schematics and in a lot of hobbyist writing, m is used for mega, so 1m means a megohm. Those two readings differ by a factor of a billion, and quietly picking one would produce a confident, plausible, catastrophically wrong answer. Write 0.001 for a milliohm and a capital M for a megohm, and the ambiguity disappears.
Does this work for anything other than resistors?
The same addition rule holds for inductors in series, and for the real part of any impedance. It does not hold for capacitors: capacitors in series combine like resistors in parallel, with reciprocals adding, which is one of the most-confused pairs of rules in electronics. It also stops being the whole story at high frequency, where lead inductance and stray capacitance mean a long chain of resistors is no longer a pure resistance. Treat these results as a DC and low-frequency model.

References& sources.

  1. [1]OpenStax (Rice University), "University Physics Volume 2", §10.2 "Resistors in Series and Parallel". Equation 10.2 states the series rule as R_S = R1 + R2 + R3 + … + R(N−1) + R_N = Σ Ri, derived from the common current and Kirchhoff's voltage law; the same section gives the per-resistor power split and notes that total dissipated power is the sum of the individual dissipations. Retrieved and read 2026-07-29.
  2. [2]"Series and parallel circuits", reference article, retrieved and read 2026-07-29. The independent second statement of the rule used to check this page: R = Σ Ri = R1 + R2 + R3 + ⋯ + Rn for a series connection, against the reciprocal-sum form for a parallel one. Agrees with OpenStax Equation 10.2 term for term.
  3. [3]IEC 60063:2015, "Preferred number series for resistors and capacitors", third edition, 27 March 2015. Defines the E24 (±5 %) and E96 (±1 %) value sets this page's nearest-stock-value check tests against, and the tolerance each series pairs with. Retrieved 2026-07-29 via the reference summary of the series values and their standard tolerances.
  4. [4]Vishay Draloric / Beyschlag / BCcomponents, "Resistor Color Card", document VMN-MS6212-1501 (2015). Prints the full E24, E96 and E192 tables under the heading "According to IEC 60063"; the ninety-six E96 mantissas used by this calculator were transcribed from it directly on 2026-07-29.
  5. [5]Vishay BCcomponents, "MRS16, MRS25 Professional Thin Film Leaded Resistors", document 28724, revision 07-Mar-16. Source of the voltage- and power-rating figures quoted on this page: rated dissipation P70 of 0.4 W (MRS16) and 0.6 W (MRS25) — that is, rated at 70 °C ambient — maximum operating voltage 200 V and 350 V respectively, and a peak permissible film temperature of 155 °C. Retrieved and read 2026-07-29.
  6. [6]Vishay, "D/CRCW e3 Standard Thick Film Chip Resistors", document 20035, revision 14-Apr-2026. Confirms the same rating convention on surface-mount parts — rated dissipation quoted as P70, permissible film temperature 155 °C, maximum operating voltage rising from 75 V on an 0402 to 500 V on a 2512 — which is the basis for the voltage-sharing answer in the FAQ. Retrieved and read 2026-07-29.

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