Audited 05 Aug 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Continuous Compound Calculator

Grow a sum at a continuously compounded rate with A = Pe^(rt): enter principal, annual rate and years to see the final value and total growth.

Continuous Compound Calculator

$
%
years
Continuously compounded value
16,487.21
Balance at the end of the term, in dollars, with interest compounded continuously at the rate entered.
Growth over principal
6,487.21

Background.

Compound interest pays interest on earlier interest, and the more often that happens the faster a balance grows. Annual compounding credits it once a year, monthly twelve times, daily 365 times. Continuous compounding is the end of that sequence: interest added at every instant, so the balance never pauses between credits.

The limit is finite, and it brings in the constant e, about 2.71828. As the number of compounding periods n rises, (1 + r/n)^(nt) closes in on e^(rt), which is why the formula here is A = P × e^(rt). Nothing more can be squeezed out by compounding more often, so the continuous figure is a ceiling on what a given nominal rate can earn.

That ceiling is closer than most people expect. $10,000 at 5% for ten years grows to $16,288.95 with annual compounding, $16,470.09 compounded monthly and $16,486.65 compounded daily; continuous compounding adds only 56 cents beyond daily. Frequency matters most when the rate is high or the term is long.

Few savings accounts compound continuously. The formula earns its place elsewhere: option pricing models such as Black–Scholes, bond and derivatives maths, and any process that grows or shrinks smoothly rather than in steps, which is why the same exponential describes radioactive decay.

The rate you enter is treated as a continuously compounded annual rate, held constant for the whole term. Negative rates are accepted and produce smooth decline. There are no deposits, withdrawals, fees or taxes, so the result is the path of one lump sum left untouched.

What is continuous compound calculator?

Continuous compounding is the limiting case of compound interest in which the compounding interval shrinks to zero. A balance P growing at a nominal continuous rate r reaches P × e^(rt) after t years, where e is Euler's number. The equivalent effective annual rate is e^r − 1, so a 5% continuous rate matches 5.127% compounded once a year. The growth figure is the future value minus the principal: all the interest earned, with nothing withdrawn along the way.

How to use this calculator.

  1. Enter the starting amount as Principal, in dollars. It is treated as a single lump sum; regular contributions are not modelled.
  2. Enter the Annual rate as a percentage, for example 5 for 5%. If you have an APY or effective yield instead, convert it first with ln(1 + APY): a 5% APY corresponds to about 4.879% continuous.
  3. Enter the Time in years. Fractions work, so 18 months is 1.5.
  4. Read the continuously compounded value and, beneath it, the growth over principal. A negative rate is allowed and shows how much of the principal survives steady decay.

The formula.

A=P*e^(rt)

A = P × e^(r × t). P is the principal, r the annual rate written as a decimal (5% becomes 0.05), t the time in years and e ≈ 2.71828 the base of natural logarithms. The growth figure is A − P.

The formula comes from the ordinary compound-interest expression P × (1 + r/n)^(n × t), where n is the number of compounding periods per year. Letting n grow without bound sends (1 + r/n)^n to e^r, and the continuous version follows.

Only the product r × t matters. Five per cent for ten years and ten per cent for five years both give an exponent of 0.5 and the same $16,487.21 on $10,000. Because time sits in the exponent, its effect accelerates: at 5% money doubles every ln 2 ÷ 0.05 ≈ 13.86 years, so 30 years multiplies it about 4.48 times rather than three. Over long horizons the rate is the input that moves the answer most, since each extra percentage point compounds through the entire term.

A worked example.

Example

$10,000 is left to grow at a continuously compounded 5% a year for 10 years. First the exponent: r × t = 0.05 × 10 = 0.5. Next, e^0.5 ≈ 1.6487213, the factor by which the balance grows. Multiplying, 10,000 × 1.6487213 gives $16,487.21, of which $6,487.21 is growth over the principal. Compounded once a year at the same 5%, the money would reach $16,288.95, about $198 less. Compounded daily it would come to $16,486.65, just 56 cents behind. Continuous compounding is the upper bound, and daily compounding already gets almost all the way there.

principal10,000
annual Rate Percent5
years10

Frequently asked questions.

How much more does continuous compounding earn than daily compounding?
Very little at ordinary rates. On $10,000 at 5% for ten years, daily compounding reaches $16,486.65 and continuous $16,487.21, a difference of 56 cents. Monthly compounding falls about $17 short and annual about $198, so the meaningful step is from annual to monthly, not from daily to continuous.
What effective annual rate does a continuous rate correspond to?
It is e^r − 1. A 5% continuous rate yields 5.127% over a year, the kind of figure a bank would advertise as APY. Going the other way, the continuous rate equivalent to an effective yield is ln(1 + yield), so a 5% effective yield corresponds to about 4.879% continuous.
Why does the number e appear in the formula?
Because e is what compounding approaches when it is done infinitely often. At 100% interest for one year, compounding twice gives a growth factor of 2.25, monthly about 2.613 and daily about 2.7146, and the limit is e, about 2.71828. Any other rate r scales that same limit to e^r.
How long does it take money to double with continuous compounding?
The doubling time is ln 2 ÷ r, roughly 0.693 divided by the rate as a decimal. At 5% that is about 13.86 years, and at 7% about 9.9 years. This is the origin of the rule of 69, the continuous-compounding cousin of the better-known rule of 72.
Where is continuous compounding actually used?
Mostly in finance theory and markets rather than retail banking. Option pricing models such as Black–Scholes discount with a continuously compounded risk-free rate, and analysts favour continuous returns because they add across periods: a year at 4% followed by a year at 6% ends exactly where two years at 5% would.
What happens if I enter a negative rate?
The balance shrinks smoothly instead of growing. At −5% for ten years, $10,000 falls to $6,065.31, and it never reaches zero however long the term runs, because e raised to any power stays positive. That suits modelling steady erosion at a constant continuous rate, such as depreciation.

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A=P*e^(rt)
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