Escape Velocity Calculator
Calculate escape velocity for any planet or moon using mass and radius. Physics tool with step-by-step math, CODATA constants, and worked examples.
Escape Velocity Calculator
Background.
The escape velocity calculator determines the minimum speed an unpowered projectile must achieve at the surface of a celestial body to break free of its gravitational pull entirely. The concept is foundational to astrodynamics, rocket engineering, and planetary science. Every interplanetary mission, every satellite launch to deep space, and every discussion of atmospheric retention on exoplanets begins with the same simple inequality: is the object's kinetic energy sufficient to climb out of the gravitational well?
The derivation traces back to Newton's law of universal gravitation and the principle of conservation of mechanical energy. If a body of mass m is launched from the surface of a much more massive body M at distance r from its center, the total mechanical energy is the sum of kinetic energy ½mv² and gravitational potential energy −GMm/r. For the projectile to reach infinity with zero residual speed, its total energy must be at least zero. Setting ½mv² − GMm/r = 0 and solving for v yields v = √(2GM/r). Remarkably, the escaping mass m cancels out, meaning a hydrogen atom and a Saturn V rocket require the same initial speed to escape Earth, though the rocket needs vastly more energy because energy scales with mass.
Earth's escape velocity of approximately 11.2 kilometers per second is one of the most referenced numbers in spaceflight. It sets the performance requirements for launch vehicles. The Atlas V, Falcon 9, and Space Launch System all must deliver payloads to speeds approaching or exceeding this threshold to reach geosynchronous transfer orbit, lunar orbit, or interplanetary trajectories. Engineers do not need to reach the full 11.2 km/s at sea level because atmospheric drag and gravity losses are offset by staging and by the Oberth effect, but the escape velocity remains the theoretical benchmark against which propulsion systems are measured.
The concept also explains why the giant planets retain hydrogen and helium atmospheres while smaller bodies like Mars and Mercury have lost most of theirs. Thermal velocities of atmospheric molecules follow the Maxwell-Boltzmann distribution; if the high-energy tail of that distribution exceeds the escape velocity, molecules leak into space over geological time. Jupiter's escape velocity of 59.5 km/s is so high that even the lightest molecules are gravitationally bound. The Moon's escape velocity of 2.38 km/s is low enough that it cannot sustain any significant atmosphere. Exoplanet hunters use estimated escape velocities together with equilibrium temperatures to assess whether a detected world could plausibly hold onto an atmosphere capable of supporting liquid water.
The calculator has value beyond professional astrodynamics. Educators use it to illustrate the interplay of mass and radius: a white dwarf with solar mass but Earth-like radius has an escape velocity approaching 6,000 km/s, a fact that underlies the conditions for Type Ia supernovae. Science fiction writers use it to check the physical plausibility of fictional worlds. Amateur astronomers use it to understand why comets on parabolic orbits have exactly zero total energy. The same formula, with M and r adjusted, applies to any spherical gravitating body, from asteroids to galaxy clusters, making it one of the most universal tools in gravitational physics.
What is escape velocity calculator?
Escape velocity is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a massive body, reaching an infinite distance with zero residual velocity. It is a scalar quantity expressed in meters per second or kilometers per second. The value depends only on the mass and radius of the attracting body, not on the mass or composition of the escaping object.
The concept applies strictly to ballistic trajectories with no thrust after the initial impulse and no non-gravitational forces such as atmospheric drag. In practice, rockets burn fuel continuously and do not need to reach the full escape velocity at launch; they can climb gradually, converting chemical energy into gravitational potential energy over time. Nevertheless, the escape velocity remains a critical design parameter because it quantifies the depth of the gravitational well that must be overcome.
Escape velocity is related to but distinct from orbital velocity. For a circular orbit just above a body's surface, the orbital velocity is v = √(GM/r), which is smaller than the escape velocity by a factor of √2. This relationship means that if a spacecraft in low orbit increases its speed by about 41.4%, it will transition to a parabolic escape trajectory.
How to use this calculator.
- Enter the mass of the celestial body in kilograms.
- Enter the radius from the body's center to the launch point in meters.
- The calculator computes 2GM / r using the CODATA 2018 value of G.
- The calculator takes the square root to obtain escape velocity in m/s.
- The result is also displayed in km/s for readability.
- Compare the output to known values (Earth 11.2 km/s, Moon 2.38 km/s) as a sanity check.
The formula.
The escape velocity formula is derived from the conservation of mechanical energy in a conservative gravitational field. Consider a particle of mass m at distance r from the center of a spherically symmetric mass M. The Newtonian gravitational potential energy is U = −GMm/r, where the negative sign indicates a bound state. The particle's kinetic energy is K = ½mv². The total mechanical energy E = K + U must be greater than or equal to zero for the particle to reach infinity with non-negative kinetic energy.
Setting E = 0 for the minimum escape condition gives ½mv² = GMm/r. The mass of the escaping particle cancels, leaving v² = 2GM/r, and therefore v = √(2GM/r). This result was implicit in Newton's Principia and was later refined by Lagrange and others in the context of celestial mechanics. The square-root dependence on mass means that doubling the central mass increases the escape velocity by a factor of √2 ≈ 1.414. The inverse dependence on radius means that compressing a planet to half its radius while holding mass constant would increase the escape velocity by the same factor.
The formula assumes a spherically symmetric mass distribution and ignores relativistic effects, atmospheric drag, and the gravitational influence of other bodies. For Earth, these approximations are excellent: general-relativistic corrections to the escape velocity amount to less than one part per billion. Near extremely compact objects such as neutron stars, the Newtonian formula becomes inaccurate and must be replaced by the Schwarzschild solution of general relativity, where the event horizon defines an escape velocity equal to the speed of light.
The appearance of the gravitational constant G in the formula ties escape velocity to the fundamental strength of gravity. Because G is among the least precisely known fundamental constants—CODATA 2018 lists its relative standard uncertainty as 2.2 × 10⁻⁵—planetary escape velocities carry a corresponding uncertainty in their final digits. For most pedagogical and engineering purposes, however, the standard value yields results accurate to better than one meter per second for planets and moons.
A worked example.
To find Earth's escape velocity, begin with the planet's standard gravitational parameter. Using the CODATA 2018 gravitational constant G = 6.67430 × 10⁻¹¹ m³·kg⁻¹·s⁻² and Earth's mass of 5.972 × 10²⁴ kg, first compute the numerator 2GM. Multiplying 2 by 6.67430 × 10⁻¹¹ gives 1.33486 × 10⁻¹⁰; multiplying that by 5.972 × 10²⁴ gives 7.97178 × 10¹⁴ m³·s⁻². Divide this by Earth's mean radius of 6.371 × 10⁶ m to obtain 1.25126 × 10⁸ m²·s⁻². The square root of this quantity is 11,186 m/s, or approximately 11.2 km/s. This is the speed a projectile would need at sea level, ignoring air resistance, to coast indefinitely away from Earth. The Apollo lunar missions did not achieve this speed at launch; instead, the Saturn V performed a trans-lunar injection burn in low Earth orbit, leveraging the Oberth effect to reach escape energy with less total propellant than a direct ascent would require.
Frequently asked questions.
Does escape velocity depend on the mass of the escaping object?
Why do rockets not need to reach escape velocity at launch?
What is the escape velocity of the Moon?
How does escape velocity relate to black holes?
Can an object with less than escape velocity still leave a planet?
Is escape velocity the same everywhere on a planet?
What is the escape velocity from the solar system?
Does atmospheric drag affect escape velocity calculations?
Can escape velocity be negative?
How is escape velocity used in exoplanet research?
References& sources.
- [1]Newton, I. (1687). Philosophiæ Naturalis Principia Mathematica. London: Royal Society. Book I, Propositions LXX and LXXI.
- [2]Halliday, D., Resnick, R., and Walker, J. (2021). Fundamentals of Physics, 11th ed. Hoboken, NJ: Wiley. Chapter 13: Gravitation.
- [3]NASA (2024). Planetary Fact Sheet — Earth. NASA Goddard Space Flight Center.
- [4]NIST (2024). CODATA Recommended Values of the Fundamental Physical Constants: 2018.
- [5]Bate, R.R., Mueller, D.D., and White, J.E. (1971). Fundamentals of Astrodynamics. New York: Dover. Chapter 2: Kepler's Equation and Orbital Energy.
- [6]Carroll, B.W. and Ostlie, D.A. (2017). An Introduction to Modern Astrophysics, 2nd ed. Cambridge: Cambridge University Press. Chapter 2: Interaction of Radiation and Matter.
In this category
Embed
Quanta Pro
Paid features are coming later.
- All 313 calculators remain free
- No billing is enabled