Audited ·Last updated 27 Jul 2026·5 citations·Tier 1·0 uses

Momentum Calculator

Free momentum calculator using p = mv. Solve for momentum, mass, or velocity in kg, g, lb and m/s, km/h, mph — with kinetic energy and worked examples.

Momentum Calculator

Solve for
Mass of the object. Required when solving for momentum or velocity. Choose your unit on the right — internally we convert to kilograms using NIST SP 811 factors (1 lb = 0.45359237 kg exactly).
Mass unit
Speed of the object along the direction of motion. Required when solving for momentum or mass. Negative values are allowed and represent motion in the opposite direction.
Velocity unit
Linear momentum in kg·m/s. Required when solving for mass or velocity. Leave at zero (or any value) when solving for momentum — the field is ignored in that mode.
kg·m/s
Momentum (p)
30,000
Linear momentum p = m·v in SI base units. A vector along the direction of velocity — the sign reflects direction along your chosen axis.
Mass (m)
1,000 kg
Velocity (v)
30 m/s
Kinetic energy (KE)
450,000 J

Background.

This momentum calculator computes linear momentum p = m·v for any massive body, and will also rearrange the relation to solve for mass or velocity when you already know p. Momentum, the product of an object's mass and its velocity, is the single most useful book-keeping quantity in classical mechanics. Once you measure it for every object in a closed system, the total cannot change unless an external force acts — that is Newton's third law restated as conservation of momentum, and it is the principle that quietly governs car crashes, billiard breaks, rocket launches, recoiling rifles, neutron-star mergers and the deflection of a tennis ball off a racket. Force is the rate at which momentum changes; impulse is the accumulated change; energy is the squared cousin that gets dissipated as heat. Get momentum right and the rest of mechanics follows.

The calculator accepts mass in kilograms, grams or pounds and velocity in m/s, km/h or mph, converting everything internally to SI base units using exact NIST SP 811 factors before applying p = m·v. It also reports the kinetic energy KE = ½ m v² so you can see at a glance how the two quantities scale differently: doubling velocity doubles momentum but quadruples kinetic energy. That asymmetry is why a slow heavy truck and a fast light car can carry the same momentum yet deliver dramatically different damage in a collision, and why braking distance grows with the square of speed even though stopping force is linear in momentum.

Three solve modes are supported. In solve-for-momentum mode you supply mass and velocity and we return p, m, v and KE. In solve-for-mass mode you supply momentum and velocity and we invert m = p/v — useful for inferring the mass of a recoiling object from the measured momentum of what it ejected. In solve-for-velocity mode you supply momentum and mass and we return v = p/m — the standard trick when applying conservation of momentum to a one-dimensional collision.

Sign conventions matter: velocity (and therefore momentum) is a vector, so a negative entry means motion in the opposite direction along your chosen axis. For two-body collisions you can run the calculator once per object, add the signed momenta to get the system total, and check that the total is conserved before and after the event. The same workflow handles explosions, rocket stages, and Newton's-cradle ball strikes.

The intro to the page below the widget walks through a 1,000 kg car at 30 m/s — a deliberately classroom-friendly example — and the FAQ tackles the questions that come up most often when students first meet momentum: why it differs from force, how it relates to impulse, what conservation actually requires, the difference between elastic and inelastic collisions, and where relativistic corrections start to bite. Momentum is one of the few quantities physicists trust at every scale, from a 1 µg dust grain in low-earth orbit to a 10³⁰ kg neutron star. Use the calculator, then read the explainer if the result surprises you.

What is momentum calculator?

Linear momentum, written p, is the product of an object's mass m and its velocity v: p = m·v. It is a vector quantity — it has both a magnitude (kg·m/s) and a direction, the same direction as the velocity. Unlike kinetic energy, which is a scalar, momentum keeps track of direction, which is why it is the natural quantity to track through collisions and explosions where direction-of-motion changes matter. The defining feature of momentum is its conservation law: the total momentum of a closed system (no net external force) is constant in time. Newton himself stated his second law in terms of momentum rather than acceleration — F = dp/dt — and only the special case of constant mass collapses to the familiar F = m·a. Momentum is also what couples mass to gravitational and electromagnetic fields in modern physics, and the relativistic generalisation p = γm·v is one half of the four-momentum that conserves energy and momentum simultaneously under Lorentz transformations.

How to use this calculator.

  1. Choose what you want to solve for: momentum (default), mass, or velocity.
  2. Enter the mass of the object and pick its unit — kilograms, grams, or pounds.
  3. Enter the velocity and pick its unit — m/s, km/h, or mph. Use a negative sign for motion in the opposite direction along your chosen axis.
  4. If you are solving for mass or velocity, also enter the momentum in kg·m/s.
  5. Read the primary result (momentum, mass, or velocity) and the derived kinetic energy in the output panel.
  6. For two-body problems, run the calculator once per object and add the signed momenta to apply conservation.

The formula.

p = m × v

The core relation is p = m·v, where p is linear momentum in kg·m/s, m is mass in kilograms, and v is velocity in metres per second. p, v and the equation itself are vector statements — write p⃗ = m·v⃗ when direction matters. Rearranged, m = p/v and v = p/m, which is how the calculator handles its two inverse modes. The kinetic energy of the same body is KE = ½ m v², which can be rewritten in terms of momentum as KE = p²/(2m). That second form makes the momentum-energy link explicit: at fixed momentum, lighter bodies carry more kinetic energy; at fixed velocity, heavier bodies carry more of both, but kinetic energy scales linearly with mass and quadratically with speed, while momentum scales linearly with each. Newton's second law in its general form is F⃗ = dp⃗/dt, so impulse J⃗ = ∫F⃗ dt = Δp⃗ — applying a force over a time interval changes momentum by exactly the force-time integral. For a system of n particles the total momentum is the vector sum P⃗ = Σᵢ mᵢ v⃗ᵢ, and conservation says dP⃗/dt = F⃗_external, so P⃗ is constant whenever the external force is zero. Relativistically, p = γm·v with γ = 1/√(1 − v²/c²); the Newtonian expression is the v ≪ c limit and is accurate to better than 1% for v < 0.14c.

A worked example.

Example

A 1,000 kg sedan travels east on a highway at 30 m/s (108 km/h, about 67 mph). Plugging into p = m·v gives p = 1000 × 30 = 30,000 kg·m/s due east. Its kinetic energy is KE = ½ × 1000 × 30² = 450,000 J = 450 kJ. To bring the car to rest, braking must absorb 450 kJ of energy and remove 30,000 kg·m/s of momentum. If the brakes apply a constant retarding force of 6,000 N, the stopping time is Δt = Δp/F = 30,000 / 6,000 = 5 seconds, and the stopping distance (using KE = F·d) is d = 450,000 / 6,000 = 75 metres. Notice the symmetry: momentum dictates how long stopping takes at a given force, kinetic energy dictates how far. If the same momentum (30,000 kg·m/s) were carried by a 100 kg motorcyclist instead, the rider would be moving at 300 m/s — and the kinetic energy would be 4.5 MJ, ten times the car's, because KE scales linearly with mass at fixed momentum (KE = p²/2m).

mass1,000
velocity30
velocity Unitmps
mass Unitkg
solve Formomentum
momentum0

Frequently asked questions.

What is the difference between momentum and force?
Momentum p = m·v is a property of a moving object at one instant — how much 'oomph' it carries. Force F is what changes momentum over time: F = dp/dt. Force has units of newtons (kg·m/s²), momentum has units of kg·m/s. You can apply a force without changing momentum (if it is balanced by another force, like gravity vs the normal force on a stationary book), and an object can carry enormous momentum with zero net force on it (a satellite coasting in space). The shortcut: momentum is the state, force is the rate of change.
What does conservation of momentum actually require?
Total momentum of a system is conserved when the net external force on the system is zero. Internal forces — two billiard balls pushing on each other during a collision, a rocket pushing on its exhaust gas — do not count, because Newton's third law guarantees they come in equal-and-opposite pairs that cancel inside the system. You can therefore apply conservation to any 'closed' system, however briefly, as long as during the interval of interest external forces (gravity, friction, air drag) are either zero, negligible, or perpendicular to the motion. That is why collision problems work even on Earth: the collision is so fast that gravity has no time to change momentum measurably.
What is the difference between elastic and inelastic collisions?
Both conserve momentum — momentum is conserved in every collision where no external force acts. What distinguishes them is kinetic energy. An elastic collision conserves total kinetic energy (billiard balls, hard steel spheres, molecules in an ideal gas — approximately). An inelastic collision dissipates some kinetic energy as heat, sound, or deformation (car crashes, putty hitting a wall). A perfectly inelastic collision is the limiting case where the two objects stick together afterwards; momentum is still conserved, but kinetic energy loss is maximised subject to that constraint. Solving an elastic 1D collision needs two equations (momentum + energy); a perfectly inelastic one needs only one (momentum).
Why can a heavy slow object and a light fast object have the same momentum?
Because momentum is the product m·v. A 20,000 kg truck at 1 m/s has the same p = 20,000 kg·m/s as a 1 kg ball at 20,000 m/s. They are equivalent for momentum book-keeping — a perfectly inelastic collision between either of them and a stationary target would produce the same recoil momentum. They are not equivalent for kinetic energy: KE = p²/(2m), so the light fast object carries 20,000× more energy and will do dramatically more damage. This is why bullets, which have small mass but enormous velocity, are far more dangerous than slow heavy objects of equal momentum.
What is impulse and how does it relate to momentum?
Impulse J is the time-integral of force: J = ∫F dt. The impulse-momentum theorem says J = Δp — the change in an object's momentum equals the impulse delivered to it. For a constant force, J = F·Δt, so to change momentum by a given amount you can use a large force over a short time (a hammer blow) or a small force over a long time (gentle braking). Airbags, crumple zones, and boxing gloves all exploit this: they extend the collision time Δt so that, for the same Δp, the peak force F is reduced. Impulse units are N·s, identical to kg·m/s — the same units as momentum, which is no accident.
When do I need relativistic momentum instead of p = mv?
Use the relativistic expression p = γm·v, where γ = 1/√(1 − v²/c²), whenever v is a significant fraction of the speed of light c = 2.998 × 10⁸ m/s. The Newtonian p = m·v is accurate to better than 1% for v < 0.14c (about 42,000 km/s), better than 5% for v < 0.31c, and breaks down badly above ~0.5c. For everyday speeds — cars, aircraft, even satellites — Newtonian momentum is exact to many decimal places. You only need γ for particles in accelerators, cosmic rays, and the immediate vicinity of compact astrophysical objects. Our calculator uses the Newtonian form; for relativistic problems multiply the result by γ.
Is momentum a vector or a scalar?
Momentum is a vector — it has both magnitude and direction, and the direction is always the same as the velocity vector. In one dimension we represent direction with a sign: +30 kg·m/s east and −30 kg·m/s west are different momenta even though they share the same magnitude. In two or three dimensions you decompose momentum into components (pₓ, p_y, p_z) and conservation applies to each component independently. That is why glancing collisions in 2D yield two equations (one per momentum component) plus, if elastic, a third for energy. Always pick an axis convention before plugging numbers in.
Why is momentum, not velocity, the quantity that is conserved?
Because conservation laws come from symmetries of the laws of physics, not from intuition. Noether's theorem (Emmy Noether, 1918) proves that for every continuous symmetry there is a conserved quantity: time-translation symmetry gives energy conservation, spatial-translation symmetry gives momentum conservation, rotational symmetry gives angular momentum conservation. Momentum p = m·v is the quantity whose total stays constant under spatial translation; velocity alone is not, because adding mass to the system changes total velocity even when no force acts. The deep answer is geometric — momentum is the right combination of m and v for the universe's symmetries to constrain.
How do I use this calculator for a two-body collision?
Pick a positive direction (say, east). Compute the signed momentum of each object before the collision — run the calculator once per object, attaching a minus sign to any westward velocity. Add the two signed momenta to get the total system momentum P_before. After the collision, the total momentum must equal P_before (conservation). If the collision is perfectly inelastic the two objects move together at v_after = P_before / (m₁ + m₂); plug P_before and total mass into our solve-for-velocity mode to get it. For an elastic 1D collision you also need conservation of kinetic energy, which gives the standard pair of post-collision velocities — the calculator's KE output helps you check that energy was indeed conserved.
What units does the calculator use internally?
All computations are done in SI base units: kilograms for mass, metres per second for velocity, and kilogram-metres per second (kg·m/s) for momentum. Energy is reported in joules (J = kg·m²/s²). The mass and velocity unit pickers convert your input to SI before the formula runs, using the exact NIST SP 811 conversion factors: 1 lb = 0.45359237 kg, 1 mph = 0.44704 m/s, 1 km/h = 1/3.6 m/s, 1 g = 0.001 kg. These factors are themselves defined, not measured, so unit conversion contributes zero rounding error. Any output you copy is in SI and ready to feed into another physics equation without further conversion.

References& sources.

  1. [1]Newton, I. (1687). Philosophiæ Naturalis Principia Mathematica. Book I, Definition II (quantitas motus, the quantity of motion) and Law II (mutationem motus proportionalem esse vi motrici impressae) — the original statement of F = dp/dt and the definition of momentum as the product of mass and velocity.
  2. [2]Halliday, D., Resnick, R., & Walker, J. (2014). Fundamentals of Physics (11th ed.), Chapter 9 'Center of Mass and Linear Momentum'. Wiley. The standard undergraduate treatment of p = m·v, impulse-momentum theorem, and conservation in 1D and 2D collisions.
  3. [3]Thompson, A., & Taylor, B. N. (2008). NIST Special Publication 811: Guide for the Use of the International System of Units (SI). National Institute of Standards and Technology. Tables B.6 and B.8 give the exact conversion factors used by this calculator (1 lb = 0.45359237 kg; 1 mph = 0.44704 m/s).
  4. [4]Feynman, R. P., Leighton, R. B., & Sands, M. (1963). The Feynman Lectures on Physics, Volume I, Chapter 10 'Conservation of Momentum'. Caltech / Addison-Wesley. Feynman's derivation of momentum conservation from Newton's third law and his treatment of recoil and rocket propulsion.
  5. [5]Goldstein, H., Poole, C., & Safko, J. (2002). Classical Mechanics (3rd ed.), Chapter 1 'Survey of the Elementary Principles'. Addison-Wesley. Derives linear and angular momentum conservation from Noether's theorem and the translational symmetry of the Lagrangian — the modern, symmetry-based justification of why momentum is the right conserved quantity.

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