Audited ·Last updated 27 Jul 2026·5 citations·Tier 1·0 uses

Terminal Velocity Calculator

Calculate terminal velocity for objects falling through air or other fluids using drag coefficient, mass, and fluid density.

Terminal Velocity Calculator

Terminal velocity
41.418
Drag force at terminal velocity
735.4988

Background.

Terminal velocity is the constant speed reached by a freely falling object when the drag force exerted by the surrounding fluid equals the gravitational force pulling the object downward. At this equilibrium, acceleration drops to zero and the object ceases to speed up. A terminal velocity calculator computes this asymptotic speed from the object's mass, its aerodynamic drag coefficient, its cross-sectional area, and the density of the fluid through which it falls. The calculation is central to skydiving safety protocols, aerospace re-entry vehicle design, particle sedimentation analysis in chemical engineering, and the physics curricula of secondary schools and universities worldwide.

The practical importance of terminal velocity extends across multiple disciplines. In aerospace engineering, the descent phase of crewed capsules, planetary probes, and payload return vehicles must be designed so that terminal velocity in the lower atmosphere does not exceed the structural limits of the heat shield or parachute system. The Apollo command module, with a mass of approximately 5800 kg and a drag coefficient near 1.5, reached a terminal velocity of about 150 meters per second in the upper atmosphere before drogue chutes reduced this to survivable speeds. In forensic science, investigators reconstruct falls from height by estimating terminal velocity to determine impact speed and differentiate between accidental falls and other scenarios. In industrial separation processes, mineral particles settling in water or air classify by size precisely because terminal velocity scales with the square root of particle diameter for spherical particles in the turbulent regime.

The mathematical model underlying terminal velocity assumes that drag follows the quadratic drag law, which is valid for Reynolds numbers above approximately 1000. For small particles, pollen, or droplets in air, the linear Stokes drag law applies instead, producing a different formula. The quadratic law dominates for macroscopic objects such as humans, vehicles, and sports equipment. The drag coefficient C_d encapsulates shape dependence: a smooth sphere has C_d ≈ 0.47, a flat plate perpendicular to flow has C_d ≈ 1.28, and a human in a spread-eagle posture has C_d ≈ 1.0. Cross-sectional area is the frontal projected area, not the total surface area. These parameters are typically determined experimentally in wind tunnels or derived from computational fluid dynamics simulations.

The concept of a speed limit in free fall dates to Galileo's kinematic experiments, though the role of air resistance was not quantified until Newton's Principia Mathematica in 1687, where Newton proposed that fluid resistance scales with the square of velocity for high-speed motion. The modern drag equation was refined in the nineteenth and early twentieth centuries through wind tunnel experiments by Gustave Eiffel and subsequent aerodynamicists. Today, terminal velocity calculations are validated against standardized atmosphere models such as the U.S. Standard Atmosphere 1976, which specifies air density as a function of altitude. At sea level, air density is 1.225 kg/m³, but at 4000 meters it drops to approximately 0.819 kg/m³, increasing terminal velocity by roughly 22 percent for the same object. Accurate computation therefore requires either a sea-level assumption with explicit acknowledgment or an altitude-dependent density lookup.

What is terminal velocity calculator?

Terminal velocity is the maximum constant velocity attained by an object falling through a fluid when the drag force equals the gravitational force. The condition is one of dynamic equilibrium: the vector sum of forces is zero, so by Newton's first law the object moves at constant velocity. Terminal velocity is not a fixed property of the object alone; it depends on the fluid density, which varies with altitude, temperature, and composition. In vacuum, where fluid density is zero, terminal velocity does not exist and the object accelerates indefinitely under gravity.

The standard formula for terminal velocity in the turbulent drag regime is v_t = √((2mg)/(ρC_dA)), where m is mass, g is gravitational acceleration, ρ is fluid density, C_d is the dimensionless drag coefficient, and A is the cross-sectional area. All quantities must be in consistent SI units for the result to be in meters per second. The drag coefficient ranges from about 0.04 for a streamlined airfoil to 1.3 for a flat plate or irregular body. Cross-sectional area must be the frontal area as seen from upstream. The formula is accurate for Reynolds numbers Re > 1000; below this threshold, Stokes law applies and terminal velocity scales linearly with particle diameter squared rather than with the square root of the drag parameters.

How to use this calculator.

  1. Enter the mass of the falling object in kilograms.
  2. Enter the drag coefficient; use 0.47 for a sphere, 1.0 for a human in spread-eagle position, or a literature value for your specific shape.
  3. Enter the cross-sectional area in square meters, measured perpendicular to the direction of fall.
  4. Enter the fluid density in kilograms per cubic meter; 1.225 kg/m³ is standard for air at sea level and 15 °C.
  5. Enter gravitational acceleration; 9.80665 m/s² is the standard Earth value.
  6. Click Calculate to obtain the terminal velocity in meters per second and the corresponding drag force in newtons.

The formula.

v_t = √(2mg ⁄ (ρ·C_d·A))

The terminal velocity formula derives from Newton's second law applied to an object falling through a resistive fluid. Two forces act on the object: gravity directed downward and drag directed upward. Gravity is F_g = m × g. For turbulent flow at high Reynolds number, drag is modeled as F_d = ½ × ρ × v² × C_d × A, where the v² dependence reflects the kinetic energy flux impinging on the frontal area. When the object reaches terminal velocity, acceleration is zero, so F_g = F_d. Equating the two forces gives m × g = ½ × ρ × v_t² × C_d × A. Solving for v_t yields v_t = √((2 × m × g) / (ρ × C_d × A)).

The dependence on the square root of mass means that doubling the mass increases terminal velocity by a factor of √2 ≈ 1.414, assuming all other parameters remain constant. This explains why heavier skydivers fall faster than lighter ones at the same body position. The inverse square-root dependence on cross-sectional area means that reducing frontal area by tucking into a head-down position dramatically increases terminal velocity; experienced skydivers in a head-down dive can reach speeds exceeding 90 m/s compared to roughly 55 m/s in a stable belly-to-earth position. The drag coefficient is empirically determined and accounts for shape, surface roughness, and flow separation; it is not derivable from first principles for complex geometries and is instead measured in wind tunnels or computed via computational fluid dynamics.

The derivation assumes incompressible flow and neglects buoyancy, which is valid for objects much denser than the fluid. For objects with densities comparable to the fluid, such as balloons or bubbles, the buoyant force ρ_fluid × V × g must be subtracted from the gravitational force, modifying the numerator to 2 × (m − ρ_fluid × V) × g. The calculator implements the standard dense-object formula; users analyzing low-density bodies must apply the buoyancy correction manually. The formula also assumes that the drag coefficient is independent of velocity, which is approximately true over the velocity range typical of skydiving and most engineering applications but breaks down near the speed of sound, where compressibility effects cause C_d to rise sharply.

A worked example.

Example

A skydiver with a total mass of 75 kg jumps from an aircraft and assumes a stable belly-to-earth position. The instructor wants to know the terminal velocity at sea level. Using a drag coefficient of 1.0, typical for this posture, and a frontal cross-sectional area of 0.7 square meters, the calculator first computes the gravitational force: 75 kg multiplied by 9.80665 meters per second squared gives 735.50 newtons. The numerator of the terminal velocity formula is twice this force, or 1470.9975. The denominator is the product of air density, drag coefficient, and area: 1.225 times 1.0 times 0.7 equals 0.8575. Dividing numerator by denominator yields 1715.449. The square root of this value is 41.42 meters per second, which converts to approximately 149 kilometers per hour. At this speed, the upward drag force exactly balances the skydiver's weight, so no further acceleration occurs. The result is consistent with published measurements for recreational skydivers, who typically stabilize near 53 to 60 meters per second in a head-up position and 40 to 50 meters per second belly-to-earth.

gravity9.807
mass75
cross Sectional Area0.7
drag Coefficient1
fluid Density1.225

Frequently asked questions.

Does terminal velocity depend on the height from which an object falls?
The value of terminal velocity itself does not depend on drop height, but the distance required to reach it does. An object dropped from a very low altitude may strike the ground before attaining terminal velocity. The distance needed to reach 99 percent of terminal velocity is approximately s = v_t² / (2g) × ln(100), which for a typical skydiver is roughly 450 meters. Skydivers exiting at 3000 meters therefore have ample distance to reach terminal velocity, whereas an object dropped from a second-story balcony will not. Air density decreases with altitude, so the terminal velocity of a falling object actually increases as it descends through the atmosphere, meaning the asymptotic speed is not strictly constant during a long fall from high altitude.
Why does a heavier object have a higher terminal velocity?
Terminal velocity scales with the square root of mass because gravitational force increases linearly with mass while drag force depends on velocity squared but not on mass. A heavier object experiences a larger downward force, requiring a higher speed to generate the equal and opposite drag force. If two skydivers of different mass use identical suits and identical body positions, the heavier one falls faster. This principle is also why large hailstones fall faster than small raindrops. In the Stokes regime for very small particles, where drag is linear in velocity, terminal velocity is directly proportional to mass, but for macroscopic objects in air the quadratic drag law applies and the square-root relationship holds.
Can terminal velocity exceed the speed of sound?
In principle, yes, for very dense or streamlined objects falling through low-density atmospheres. Meteors entering Earth's atmosphere can reach hypersonic speeds before atmospheric drag becomes significant. However, for humans and most engineered objects falling through Earth's lower atmosphere, terminal velocity is well below the speed of sound, which is approximately 343 meters per second at sea level. As an object approaches the speed of sound, compressibility effects increase the drag coefficient substantially, creating an additional barrier. Military ordnance such as bunker-buster bombs is designed with high density and small cross-sectional area specifically to achieve supersonic terminal velocities and penetrate hardened targets before decelerating.
What is the difference between terminal velocity and settling velocity?
Terminal velocity is the general term for the constant speed reached by any object falling through a fluid under gravity. Settling velocity is the specific term used in chemistry, environmental engineering, and geology for particles sedimenting in a liquid, usually water. The physics is identical, but settling velocity calculations often use the Stokes drag law rather than the Newtonian drag law because particle Reynolds numbers are low. Stokes settling velocity is v = (2/9) × (ρ_p − ρ_f) × g × r² / η, where ρ_p is particle density, ρ_f is fluid density, r is particle radius, and η is dynamic viscosity. The calculator implements the Newtonian high-Reynolds-number formula appropriate for objects falling through air.
Why do skydivers use a parachute if they already reach terminal velocity?
A parachute dramatically increases the drag coefficient and cross-sectional area, thereby reducing terminal velocity to a survivable impact speed. Without a parachute, a human's terminal velocity of roughly 50 meters per second produces a fatal impact. A ram-air parachute increases the effective area to approximately 25 square meters and raises the drag coefficient, lowering terminal velocity to about 5 meters per second. The kinetic energy at impact scales with velocity squared, so reducing speed by a factor of 10 reduces impact energy by a factor of 100. Parachute design involves trade-offs between descent rate, maneuverability, and opening shock, all of which are analyzed using the same drag physics that governs free-fall terminal velocity.
Does shape affect terminal velocity more than mass?
Shape affects terminal velocity through both the drag coefficient and the cross-sectional area, and its influence can be comparable to or greater than that of mass. Consider two objects of identical mass: a compact sphere and a flat sheet. The sphere has a small cross-sectional area and a moderate drag coefficient, while the sheet has a large area and a high drag coefficient. The sheet's terminal velocity may be an order of magnitude lower. A feather and a bowling ball dropped in vacuum fall at the same rate, but in air the feather's large area-to-mass ratio gives it a very low terminal velocity. For skydivers, changing body position alters cross-sectional area by a factor of three or more, producing terminal velocities ranging from 40 to 90 meters per second without any change in mass.
What happens to terminal velocity on other planets?
Terminal velocity depends on gravitational acceleration and atmospheric density, both of which vary among planets. On Mars, where gravity is 3.72 m/s² and surface atmospheric density is about 0.020 kg/m³, a human would have a terminal velocity of approximately 200 meters per second if falling through the lower atmosphere, though the thin air provides little braking at high altitude. On Venus, with gravity of 8.87 m/s² and a dense carbon dioxide atmosphere at 65 kg/m³ near the surface, terminal velocity for the same human would be roughly 1.5 meters per second. On the Moon, which lacks a significant atmosphere, terminal velocity does not exist and objects accelerate until impact. The calculator uses Earth-standard values by default but accepts arbitrary g and ρ for extraterrestrial or laboratory applications.
Is the drag coefficient constant at all speeds?
No. The drag coefficient is approximately constant only in the turbulent incompressible regime, typically for Reynolds numbers between 1000 and about 200,000 for streamlined bodies, and up to lower limits for blunt bodies. At very low speeds, where viscous forces dominate, C_d rises as Reynolds number decreases. Near the speed of sound, compressibility causes C_d to increase sharply, a phenomenon known as the drag divergence. For a sphere, C_d drops from about 0.5 to 0.1 in the drag crisis regime near Re = 3 × 10⁵ due to laminar-turbulent boundary layer transition. The calculator assumes a constant user-supplied drag coefficient and is most accurate for subsonic speeds in the turbulent regime.
How does air temperature affect terminal velocity?
Air temperature affects terminal velocity by changing air density. At higher temperatures, air expands and density decreases, which increases terminal velocity because the drag force at a given speed is proportional to density. At sea level, air density at 30 °C is approximately 1.165 kg/m³ compared to 1.225 kg/m³ at 15 °C. For a skydiver with a terminal velocity of 50 m/s at 15 °C, the same posture at 30 °C yields a terminal velocity of about 51.3 m/s, an increase of roughly 2.6 percent. Humidity also has a minor effect because water vapor is less dense than dry air; saturated air at 20 °C is about 1 percent less dense than dry air at the same temperature and pressure. The calculator accepts a user-specified density to account for these variations.
Can an object have different terminal velocities in different orientations?
Yes. Terminal velocity depends on the product of drag coefficient and cross-sectional area, both of which are strong functions of orientation. A human skydiver in a stable belly-to-earth position has a larger frontal area and lower terminal velocity than the same person in a head-down dive. A box or irregular object may tumble, causing the effective C_dA to oscillate and producing an average terminal velocity that differs from any single orientation. Some objects, such as cones or badminton shuttlecocks, are designed to be aerodynamically stable in a specific orientation, ensuring a predictable terminal velocity. The calculator computes terminal velocity for a single user-specified C_d and A; analyzing tumbling objects requires time-dependent simulation or average values.

References& sources.

  1. [1]White, F.M. (2016). Fluid Mechanics, 8th ed. McGraw-Hill. ISBN 978-1259696534.
  2. [2]CODATA (2018). Newtonian constant of gravitation and recommended values. NIST Physical Measurement Laboratory.
  3. [3]U.S. Standard Atmosphere (1976). NASA-TM-X-74335. NOAA/NASA/USAF.
  4. [4]Anderson, J.D. (2016). Fundamentals of Aerodynamics, 6th ed. McGraw-Hill. ISBN 978-1259129919.
  5. [5]Halliday, D., Resnick, R., and Walker, J. (2013). Fundamentals of Physics, 10th ed. Wiley. ISBN 978-1118230718.

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