Audited 31 Jul 2026·Last updated 28 Oct 2026·4 citations·Tier 2·0 uses

Capacitive Reactance Calculator — Xc = 1 / (2πfC)

Find a capacitor's reactance in ohms from frequency and capacitance, or solve for the capacitance or frequency that gives a target reactance.

Capacitive Reactance Calculator

Solve for
The signal frequency. Reactance is inversely proportional to it: double the frequency and the reactance halves.
Frequency unit
Nominal marked value. Class-2 ceramics such as X7R and Y5V lose a large share of it under DC bias, which raises the real reactance above this figure.
Capacitance unit
Entered as a positive magnitude. The −90° phase of a capacitor is implied, not typed in. Used only when solving for capacitance or frequency.
Reactance unit
Capacitive reactance Xc
1,591.5494
Xc in ohms as a positive magnitude: the opposition the ideal capacitor presents at this frequency, with current leading voltage by 90°.
Capacitance
1.000 × 10⁻⁷ F
Frequency
1,000 Hz
Angular frequency ω
6,283.1853 rad/s
Susceptance B
6.283 × 10⁻⁴ S
Reading of the result
A 100 nF capacitor has a reactance of 1.5915 kΩ at 1 kHz, equivalent to a susceptance of 628.3185 µS. Reactance is shown as a positive magnitude: in complex form the impedance is −jX_C, so the current leads the voltage by exactly 90° and an ideal capacitor dissipates no average power. Reactance falls as frequency rises — double the frequency and this figure halves. Real capacitors stop obeying this above their self-resonant frequency, where lead and plate inductance takes over and the impedance starts rising with frequency instead. For the 100 nF entered here, an assumed 1 nH of series inductance (a typical figure for package, pads and vias; your part will differ) puts the self-resonant frequency near 15.9155 MHz, the point where the impedance stops falling.

Background.

Ask what resistance a 100 nF capacitor has and the answer depends on the signal. At 1 kHz it opposes current with about 1,592 ohms. At 100 kHz the same part offers about 16 ohms, and at DC it does not conduct at all. That frequency-dependent opposition is capacitive reactance, and it sits behind almost every job a capacitor does with a changing signal: passing audio from one stage to the next while blocking the DC bias, shunting high-frequency noise to ground beside a chip, setting the corner of a filter, tuning a radio circuit.

The relationship is Xc = 1/(2πfC). Doubling the frequency halves the reactance, and so does doubling the capacitance. You can run it three ways here: reactance from a frequency and a part value; the capacitance needed to reach a target reactance at a given frequency, which is how coupling and filter capacitors get sized; or the frequency at which a part you already have reaches a chosen reactance.

Reactance is measured in ohms, but it is not resistance. Voltage and current in an ideal capacitor are a quarter-cycle apart, with the current leading, so energy flows in during one part of the cycle and back out in the next and none of it becomes heat. A capacitor across a mains supply can carry a substantial current while consuming almost no real power; the slight warming of a real one comes from its small internal series resistance.

The equation describes an ideal component. Every real capacitor has some series inductance, and above its self-resonant frequency that inductance takes over, so the impedance stops falling and starts to climb.

What is capacitive reactance calculator?

Capacitive reactance, written Xc, is the ratio of the voltage amplitude across an ideal capacitor to the current amplitude through it when both are sine waves of one frequency. It is given in ohms as a positive magnitude. In complex notation the capacitor's impedance is −jXc, and that minus sign records that the current leads the voltage by 90°. The reciprocal, susceptance B = 1/Xc = ωC, is measured in siemens.

How to use this calculator.

  1. Choose what to solve for: reactance, capacitance or frequency. Only the two inputs that mode needs are read, so a value left in the third field is ignored.
  2. Enter each value with its unit. Use the marked capacitance, but bear in mind that class-2 ceramics such as X7R, X5R and Y5V can deliver much less under DC bias, which pushes the real reactance up; C0G/NP0 and film capacitors hold their value.
  3. When solving for capacitance or frequency, enter the reactance as a positive number of ohms, kilohms or megohms; the 90° phase is understood.
  4. To size a coupling capacitor, solve for capacitance at the lowest frequency that must pass, with a reactance of about a tenth of the load resistance.
  5. For capacitors in parallel, add their susceptances, which is the same as adding their capacitances; for capacitors in series, add their reactances.

The formula.

X_C = 1 ⁄ (2πfC) = 1 ⁄ (ωC) C = 1 ⁄ (2πf·X_C) f = 1 ⁄ (2πC·X_C) B = 1 ⁄ X_C = ωC

A capacitor's current is proportional to how fast the voltage across it changes, i = C·dv/dt. For a sine wave at frequency f, taking that rate of change brings in a factor of ω = 2πf, the angular frequency in radians per second, and shifts the waveform by a quarter cycle. The ratio of voltage amplitude to current amplitude is therefore Xc = 1/(ωC) = 1/(2πfC), the form OpenStax University Physics gives, with f in hertz, C in farads and Xc in ohms.

Rearranged, the same equation gives C = 1/(2πf·Xc) and f = 1/(2πC·Xc). The three are exact inverses, so solving forwards and feeding the answer back returns the value you started with. Alongside the main answer you also get ω and the susceptance B = ωC.

With voltage and current 90° apart, the power factor cos φ is zero, and so is the average power ½V₀I₀ cos φ. The capacitor trades energy back and forth with the circuit rather than consuming it.

At 0 Hz the reactance would be infinite, so a frequency of zero is refused. The equation also leaves out what makes a real part non-ideal: series resistance, series inductance, leakage, and the drift of capacitance with voltage, temperature and age. Series inductance L sets the self-resonant frequency, 1/(2π√(LC)). Assuming 1 nH, a 100 nF part resonates near 15.9 MHz, and above that it behaves as an inductor.

A worked example.

Example

Take a 100 nF capacitor at 1 kHz, the classic coupling-capacitor question. In base units that is 1,000 Hz and 1 × 10⁻⁷ F. The angular frequency is 2π × 1,000 = 6,283.1853 rad/s. Multiplying by the capacitance gives the susceptance, 6,283.1853 × 10⁻⁷ = 6.2832 × 10⁻⁴ S, or 628.3 µS. Its reciprocal is the reactance, 1,591.5494 Ω, or about 1.59 kΩ. Feeding a 10 kΩ input, that reactance is about a sixth of the load. Because the two combine at right angles rather than simply adding, the 1 kHz signal loses only 0.11 dB. At 20 Hz, though, the same capacitor's reactance is 79.6 kΩ and the bass arrives 18.08 dB down. The corner where reactance equals the load, 1/(2π × 10,000 × 100 nF), is 159.15 Hz, so this pairing suits something like a telephone-quality voice channel, which needs nothing below a few hundred hertz.

frequency UnitkHz
reactance1,591.549
capacitance100
reactance Unitohm
capacitance UnitnF
solve Forreactance
frequency1

Frequently asked questions.

How big should a coupling capacitor be?
Make its reactance at the lowest frequency you care about no more than about a tenth of the load it feeds, which keeps the loss there to about 0.04 dB. For 20 Hz into 10 kΩ that means 1 kΩ or less at 20 Hz, which works out to 7.96 µF. Rounding up to a common 10 µF part cuts the loss at 20 Hz to about 0.03 dB.
Does a capacitor across the mains use electricity?
It draws current but consumes almost no real power. A 10 µF capacitor on a 230 V, 50 Hz supply has a reactance of 318.3 Ω, so about 0.72 A flows, carrying roughly 166 var of reactive power. The energy goes in and comes back each cycle; only the small loss in its series resistance turns into heat.
Why do some textbooks give capacitive reactance a minus sign?
They fold the phase into the number. A capacitor's impedance is −jXc, and some authors define the reactance as the imaginary part, −1/(ωC), so it comes out negative while inductive reactance is positive. Here the magnitude is shown positive and the 90° lead of current over voltage is stated separately, as datasheets and bench meters usually do.
Why does my 100 nF decoupling capacitor stop working at 100 MHz?
It is past self-resonance and acting as an inductor. With an assumed 1 nH of series inductance from the package, pads and vias, the inductive reactance at 100 MHz is about 0.63 Ω, while the ideal equation would predict 0.016 Ω. That is why decoupling networks combine several smaller values placed very close to the pins.
How does capacitive reactance differ from inductive reactance?
They move in opposite directions. Inductive reactance, 2πfL, rises with frequency while capacitive reactance falls, and in a circuit containing both they partly cancel. At the resonant frequency, 1/(2π√(LC)), they are equal and cancel completely, which is the principle behind tuned circuits and the self-resonance of real capacitors.
What is the susceptance figure good for?
Combining capacitors in parallel. Susceptances add directly: two 100 nF parts at 1 kHz give 2 × 628.3 µS = 1,256.6 µS, and inverting once gives 795.8 Ω for the pair. Adding reactances in parallel would need the reciprocal formula used for resistors, so working in siemens is quicker and less error-prone.

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Method
X_C = 1 ⁄ (2πfC) = 1 ⁄ (ωC) C = 1 ⁄ (2πf·X_C) f = 1 ⁄ (2πC·X_C) B = 1 ⁄ X_C = ωC
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