Audited 31 Jul 2026·Last updated 28 Oct 2026·4 citations·Tier 2·0 uses

Inductive Reactance Calculator — XL = 2πfL

Find an inductor's reactance in ohms from frequency and inductance, or solve back for the inductance or frequency, with angular frequency and susceptance.

Inductive Reactance Calculator

Solve for
The signal frequency. Reactance is directly proportional to it: double the frequency and the reactance doubles — the exact opposite of a capacitor.
Frequency unit
Nominal marked value. A ferrite-cored part loses inductance as its core approaches saturation, which is a current-dependent effect this page cannot see.
Inductance unit
Entered as a positive magnitude; the +90° phase of an inductor is implied, not typed in. Used only when solving for inductance or frequency.
Reactance unit
Inductive reactance XL
628.3185
Inductive reactance X_L in ohms, given as a positive magnitude; the impedance is +jX_L, with voltage leading current by 90°.
Inductance
0.1 H
Frequency
1,000 Hz
Angular frequency ω
6,283.1853 rad/s
Susceptance B
0.0016 S
Reading of the result
A 100 mH inductor has a reactance of 628.3185 Ω at 1 kHz, equivalent to a susceptance of 1.5915 mS. Reactance is shown as a positive magnitude: in complex form the impedance is +jX_L, so the voltage leads the current by exactly 90° — the mirror of a capacitor — and an ideal inductor dissipates no average power. Reactance rises in direct proportion to frequency: double the frequency and this figure doubles. Two limits a real coil imposes that this equation cannot see — above its self-resonant frequency the inter-winding capacitance takes over and the impedance starts falling again, and a core driven into saturation loses inductance at exactly the moment the current is highest.

Background.

Put a 100 mH coil in series with a 600 Ω audio line and the result is lopsided. At 50 Hz the coil presents 31.4 Ω and the line hardly notices it; at 1 kHz it presents 628.3 Ω and only 69% of the signal voltage reaches the load. Nothing about the coil has changed between the two cases. Its opposition to alternating current, its inductive reactance, simply grows in step with frequency.

The relationship is X_L = 2πfL: frequency in hertz times inductance in henries times 2π gives ohms. It is a straight line through zero, so a coil is effectively a short circuit to steady direct current and an increasingly stiff obstacle as the frequency climbs, the reverse of a capacitor. Only the product of frequency and inductance matters, which is why 100 mH at 1 kHz, 10 µH at 10 MHz and 100 nH at 1 GHz all come to the same 628.32 Ω.

Design work usually runs the equation backwards, so it can be solved three ways: the reactance of a known coil at a known frequency, the inductance needed to reach a target reactance, or the frequency at which a coil you already have reaches a given reactance. Each answer comes with the angular frequency and the susceptance, 1/X_L, the form that adds directly when parts sit in parallel.

All of this describes an ideal coil. A real one has resistance in its winding, capacitance between its turns and, often, a magnetic core that saturates under heavy current, and each of these sets a limit on where the straight line still holds.

What is inductive reactance calculator?

Inductive reactance is the opposition an ideal inductor offers to a sinusoidal current, measured in ohms like resistance but working differently: instead of turning energy into heat, the coil stores it in its magnetic field for part of each cycle and hands it back for the rest. In complex notation the inductor's impedance is +jX_L, meaning the voltage across it leads the current through it by exactly a quarter cycle, 90°.

How to use this calculator.

  1. Choose what to solve for: reactance from frequency and inductance, inductance from frequency and reactance, or frequency from inductance and reactance.
  2. Enter the frequency and pick its unit, from Hz to GHz. Mains hum is 50 Hz or 60 Hz depending on the country; for a switching supply use its switching frequency.
  3. Enter the inductance with its unit, nH to H, using the part's marked nominal value; most inductors carry a tolerance, so a 100 mH part may not measure exactly 100 mH.
  4. In the two inverse modes, enter the target reactance as a positive number in Ω, kΩ or MΩ. Whichever field the chosen mode does not need is ignored.
  5. For high frequencies or heavy currents, compare the answer with the datasheet's self-resonant frequency and saturation current before relying on it.

The formula.

X_L = 2πfL = ωL L = X_L ⁄ (2πf) f = X_L ⁄ (2πL) B = 1 ⁄ X_L

The equation follows from Faraday's law, which makes the voltage across a coil equal to L times the rate of change of its current, v = L·di/dt. Drive it with i = I₀ sin(ωt) and the voltage is v = ωL·I₀ cos(ωt): its amplitude is ωL times the current amplitude, and the cosine runs a quarter cycle ahead of the sine, which is the 90° lead. The ratio ωL is the reactance, written X_L = ωL in physics texts and X_L = 2πfL in engineering, since ω = 2πf. The other two modes are rearrangements, L = X_L ÷ (2πf) and f = X_L ÷ (2πL), and susceptance is B = 1 ÷ X_L in siemens. Because voltage and current are 90° apart, the average power ½I₀V₀cos φ is zero for an ideal inductor. Every input must be positive: at 0 Hz the reactance is zero and the inverse modes would divide by nothing. Not modelled are winding resistance, core loss, skin effect, self-resonance and core saturation.

A worked example.

Example

In the example, a 100 mH inductor runs at 1 kHz. In base units that is f = 1,000 Hz and L = 0.1 H. The angular frequency is ω = 2π × 1,000 = 6,283.1853 rad/s, and the reactance is ω × L = 6,283.1853 × 0.1 = 628.3185 Ω. Its reciprocal, the susceptance, is 0.0015915 S, or 1.5915 mS. To see what 628 Ω does in a circuit, put it in series with a 600 Ω load: reactance and resistance combine at right angles, √(600² + 628.32²) = 868.8 Ω, so the load receives 600 ÷ 868.8 = 69% of the voltage, a loss of 3.2 dB. Switching to frequency mode with 600 Ω and 100 mH returns 954.93 Hz, the corner where this coil and load begin to cut the signal by more than 3 dB.

frequency UnitkHz
reactance628.319
inductance100
inductance UnitmH
reactance Unitohm
solve Forreactance
frequency1

Frequently asked questions.

How much reactance does a choke need to block an unwanted signal?
Far more than the impedance it works against. With reactance equal to a resistive load the signal drops only about 3 dB. To cut the voltage reaching the load to a tenth, a 20 dB reduction, the reactance must be about 9.95 times the load resistance at the frequency you want to block, so size the choke from that ratio.
Why does a coil's reactance rise with frequency when a resistor's value does not?
A coil opposes changes in current, not current itself. At higher frequency the current reverses more often, so it changes faster, and by Faraday's law the opposing voltage grows in proportion. A resistor responds only to how much current flows, so its value is the same at any frequency.
How does an inductor behave differently from a capacitor in an AC circuit?
They are mirror images. An inductor's reactance rises with frequency and its voltage leads its current; a capacitor's falls with frequency and its current leads. Their opposite signs cancel at resonance, f₀ = 1/(2π√LC): a 100 mH coil paired with about 253.3 nF resonates at 1 kHz.
Does an inductor waste power as heat?
Its reactance does not, because energy stored in the field during one quarter cycle is returned in the next, and the average power over a cycle is zero. The heat a real inductor gives off comes from the resistance of its winding and from losses in its core, which rise with frequency and flux.
What happens above an inductor's self-resonant frequency?
The capacitance between the turns resonates with the inductance, the impedance peaks, and above that frequency the part behaves like a capacitor, with impedance falling as frequency rises. X_L = 2πfL then describes a component you no longer have. Datasheets list the self-resonant frequency, and it should sit well above the frequency you care about.
Why does my ferrite-cored inductor filter less than predicted at high current?
Its core is saturating. As the current, and with it the magnetic flux, approaches the core's limit, the inductance falls, so the reactance falls exactly when the current is highest. There is no current input here to warn you; check that the part's rated saturation current is comfortably above your peak current.
How do I combine inductors in parallel using susceptance?
Add their susceptances, then take the reciprocal. Two 100 mH coils in parallel at 1 kHz have 1.5915 mS each, 3.1831 mS together, giving a combined reactance of 314.1593 Ω, the same as a single 50 mH coil. This assumes the coils are not magnetically coupled to each other.

How this page was produced

Published by
Quanta Calculator
Primary sources
4 cited below
Method
X_L = 2πfL = ωL L = X_L ⁄ (2πf) f = X_L ⁄ (2πL) B = 1 ⁄ X_L
Published
Last verified

Built with AI assistance and verified by automated tests against the cited sources — every worked example on this page is computed by the same code that runs the calculator. How we build and check calculators.

In this category

Embed

Quanta Pro

Paid features are coming later.

  • All 1560 calculators remain free
  • No billing is enabled
Coming soon