Audited 29 Jul 2026·Last updated 31 Jul 2026·4 citations·Tier 2·0 uses

DC Wire Size Calculator (12V, 24V and 48V)

Size 12V, 24V, 36V, 48V or 120V DC wire for a voltage-drop budget, with the NEC Table 310.16 ampacity as a floor. Enter amps or watts and a one-way run.

DC Wire Size Calculator

DC system voltage
How do you know the load?
The steady current the circuit will actually draw. Ignored in watts mode. Inverters are the usual trap: a 2,000 W inverter at 12 V draws well over 170 A on the battery side once efficiency is allowed for, which is a busbar-and-lug problem rather than a wire-gauge one.
A
Ignored in amperes mode. Use the continuous rating rather than a peak or surge figure — surge is a separate problem that conductors mostly ride out but fuses and lugs do not.
W
Source to load, measured along the route the cable actually takes. The calculator doubles it for the return path. This is the number people get wrong most often, because ABYC's published tables are printed the other way round — their length column is source-to-device-and-back — so a figure copied across without halving or doubling is out by a factor of two.
ft
Conductor material
3% is the usual design target and matches NEC 210.19(A) Informational Note No. 4. ABYC E-11.14.2.6 uses the same 3% for circuits where drop must be kept to a minimum — main feeders, bilge blowers, electronics and navigation lights — and allows 10% for lighting and other circuits where drop is not critical.
%
Conductor insulation temperature rating
Conductor size to install
6 AWG copper — governed by voltage drop. That is 20 A over 15 ft one-way on a 12 V DC system, held to 3 % (0.36 V). Measure the run one-way; the calculator doubles it for the return path. This is a design aid — have a licensed electrician or a qualified installer confirm the conductor, the overcurrent protection and the terminations before anything is connected to a battery.
The larger of the voltage-drop answer and the ampacity floor. Voltage drop is computed from VD = 2·K·I·L/CM with the NEC Chapter 9 Table 8 constants; the ampacity floor comes from NEC Table 310.16 at its own basis of 30 °C ambient and not more than three current-carrying conductors. LOCAL AMENDMENTS GOVERN and adopted code editions vary by jurisdiction. Have a licensed electrician or qualified installer confirm the conductor, the overcurrent protection and the terminations before anything is connected to a battery — a battery bank is a fault-current source that does not trip out politely. BOATS ARE NOT COVERED: marine DC wiring is governed by ABYC E-11 and its own tables.
Minimum size on voltage drop
6 AWG copper — the smallest size with at least 21500 circular mils, which is what holds 3 % of 12 V (0.36 V) over this run. On a low-voltage DC system this is almost always the constraint that decides the answer.
Minimum size on ampacity
14 AWG copper — 25 A in the 90 °C column of NEC Table 310.16, which is enough for 20 A. This floor is taken at the table's own basis: 30 °C ambient, not more than three current-carrying conductors, no derating. Conductors running hot or bundled need the correction and adjustment factors, which the AC wire size calculator applies properly.
Circuit current
20 A
Circular mils required
21,500
Voltage drop on the run
0.295 V
Voltage drop as a percentage
2.46
Voltage at the load
11.705 V
Code basis and limits
Voltage drop from VD = 2·K·I·L/CM with the NFPA 70, 2023 edition Chapter 9 Table 8 constants (K = 12.9 for copper at 75 °C); ampacity floor from Table 310.16. The 3 % target is NEC 210.19(A) Informational Note No. 4, which is guidance rather than enforceable code — though several jurisdictions adopt it by amendment. LOCAL AMENDMENTS GOVERN and adopted editions vary by jurisdiction. A licensed electrician must sign off before work proceeds. BOATS ARE NOT COVERED HERE: marine DC wiring is governed by ABYC E-11, which uses its own ampacity table and its own voltage-drop Tables IX and X, and splits the budget 3 % for critical circuits and 10 % for non-critical ones. PV source and output circuits carry the extra 125 % stacking of NEC 690.8, and vehicle wiring is SAE territory rather than NEC.

Background.

Low-voltage DC wiring is not AC wiring with a smaller number in it. On a 240 V circuit a 3% voltage-drop budget is 7.2 V, which is a comfortable amount of room, and the conductor is usually decided by heat — by the ampacity tables an inspector enforces. On a 12 V circuit the same 3% is 0.36 V. Not seven volts: a third of one volt, for the whole out-and-back trip. That single difference is why voltage drop governs essentially every low-voltage DC run of any length, why the ampacity table barely participates, and why a 12 V circuit needs conductors that look absurd next to an AC circuit carrying the identical current.

The comparison is worth seeing concretely. Twenty amperes over fifteen feet on a 120 V AC branch circuit needs 12 AWG — an ordinary piece of house wire. The same twenty amperes over the same fifteen feet on a 12 V DC system needs 6 AWG, three trade sizes up, at roughly four times the copper. Nothing about the current changed. The only thing that changed is how many volts you can afford to lose.

That is the whole reason this page exists separately from the AC wire size calculator. Everything the NEC builds around ampacity — the 110.14(C) termination columns, the 240.4(D) small-conductor limits, the 125% continuous-load adjustment, the bundling derates — is most of that page and is close to irrelevant to a battery-to-inverter run. Here the arithmetic is one equation, and the interesting decisions are about system voltage, run length and how much drop the load will actually tolerate.

The system voltage field is the biggest lever on the page and is worth playing with before you buy cable. Because current falls as voltage rises and the allowable drop in volts rises at the same time, the copper needed for a given power over a given distance falls with the square of the voltage. The same 240 W load needs four times the circular mils at 12 V that it needs at 24 V, and sixteen times what it needs at 48 V. Anyone laying out an off-grid system with runs longer than a few metres is usually better off solving the problem with system voltage than with copper, and this calculator will show you the trade in one comparison.

Three scope limits, stated here rather than tucked into an FAQ. First, length is measured one-way and the calculator doubles it. ABYC's published tables are printed the other way round — their length column is source-to-device-and-back — so a number carried across from one to the other without halving or doubling is wrong by a factor of two, and that is the single most common mistake in DC wire sizing. Second, boats are not covered here at all. Marine DC wiring is governed by ABYC E-11, which has its own ampacity table, its own voltage-drop tables IX and X, its own resistance constant, and a 3%/10% split between critical and non-critical circuits. Its published tables are in places one trade size more conservative than any formula reproduces, so they must be read rather than calculated. Third, photovoltaic source and output circuits carry the extra 125% stacking of NEC 690.8 and energy-storage circuits fall under Article 706; this page sizes a conductor for a current you give it, and it does not compute that current for you.

And the limit that matters most: a battery bank is a fault-current source with no upstream breaker to save you. A shorted 12 V lithium pack will happily deliver thousands of amperes into a wrench. Conductor sizing is only one part of a safe DC installation, alongside correctly rated fusing at the source end, proper lugs, crimps and strain relief, and terminations that are actually listed for the conductor. Have a licensed electrician or a qualified installer sign off before anything is connected.

What is dc wire size calculator?

A DC wire size calculator answers the question of which conductor to run between a source and a load on a direct-current system, given the current, the distance, and how much voltage you are prepared to lose along the way.

The underlying physics is Ohm's law and nothing more. A conductor has resistance proportional to its length and inversely proportional to its area; current through that resistance produces a voltage drop; the drop is subtracted from what arrives at the load. On DC there is no reactance and no power factor, so unlike the AC case the calculation is exact rather than an approximation — the only modelling assumption is the temperature the resistance is quoted at, here 75 °C.

The trade form of the equation is VD = 2·K·I·L/CM. I is the current in amperes, L is the one-way length in feet, CM is the conductor's area in circular mils, and K is a resistance constant — 12.9 for copper and 21.2 for aluminium, both at 75 °C, both derived from NEC Chapter 9 Table 8. The 2 is there because the current has to come back: on DC there is no neutral doing anything clever, and the return conductor drops exactly as much as the supply conductor.

Ampacity still exists and still has to be checked. It is simply rarely the binding constraint down here: 14 AWG copper is good for 25 A on heat alone, and a 12 V circuit carrying 25 A over any useful distance will have been pushed to 6 AWG or larger by voltage drop long before heat becomes interesting. The calculator reports both so you can see which one decided the answer, because that tells you what to change — if drop governs, only more copper or a higher system voltage helps; if ampacity governs, the run is short and the current is large, and the real problem is probably at the terminations.

How to use this calculator.

  1. Pick the system voltage. If you are still choosing one, run the same load at 12 V and again at 24 V before you buy anything — the copper needed falls with the square of the voltage, and on long runs that decision is worth more than any other.
  2. Say whether you know the load in amperes or in watts, and fill in that field. The other one is ignored.
  3. Measure the run one-way, source to load, along the route the cable actually takes rather than straight-line. The calculator doubles it for the return path.
  4. Set the drop budget. 3% is the normal design target. 10% is defensible for cabin lighting and other loads that genuinely do not care, and is what ABYC E-11 permits for non-critical circuits — but check that your load really is one of those before you spend the allowance.
  5. Read which constraint governed. If it says voltage drop, the only fixes are more copper, a shorter run or a higher system voltage. If it says ampacity, the run is short and the current is high, and your attention belongs on fusing, lugs and crimps rather than on gauge.
  6. Check the ampacity floor's assumptions against your install. It is taken at 30 °C ambient with no more than three conductors together — an engine bay, a roof space or a bundle through a conduit is none of those, and needs the derating factors the AC wire size calculator applies.
  7. Size the fuse or breaker separately, at the source end of the run, and have the whole installation signed off by a licensed electrician or qualified installer before it is connected to a battery.

The formula.

CM = 2 · K · I · L / (V × d%) · VD = 2 · K · I · L / CM

Start from resistance. A conductor's resistance is its resistivity times its length divided by its area. Expressing area in circular mils folds the awkward constants into a single number K, defined as the DC resistance of a 1,000-circular-mil conductor 1,000 feet long: 12.9 ohms for copper and 21.2 for aluminium, both quoted at 75 °C in NEC Chapter 9 Table 8. That gives resistance per foot as K/CM, and Ohm's law gives the drop.

The factor of 2 is the round trip. On a DC circuit the current leaves through one conductor and returns through the other, both of them the same size, so the drop is twice what a single length would give. Getting this wrong is the classic DC wire-sizing error, and it is made easier by the fact that ABYC prints its own tables against the round-trip length rather than the one-way length. This page asks for one-way and doubles it, and says so beside the answer.

Rearranged to size a conductor, CM = 2·K·I·L / VD_allowed, where VD_allowed is the system voltage times the drop budget. The calculator computes that area, then takes the smallest standard conductor whose circular-mil area reaches it — compared unrounded, so a requirement a hair above a size steps up rather than rounding onto it. The worked example is 2 × 12.9 × 20 × 15 / 0.36 = 21,500 circular mils, which 6 AWG's 26,240 covers and 8 AWG's 16,510 does not.

The ampacity floor is a separate lookup rather than a calculation: the smallest conductor whose NEC Table 310.16 figure, in the column matching your insulation rating, reaches the circuit current. It is taken at the table's own basis of 30 °C ambient and no more than three current-carrying conductors, with no correction or adjustment applied — a deliberate simplification, stated beside the result, because on a low-voltage DC system the drop constraint is normally several sizes above it anyway. Where it is not — a very high current over a very short run, which is exactly what a battery-to-inverter cable is — the floor takes over and the page says so.

The answer is the larger of the two, because a conductor has to satisfy both at once. Every comparison is made on the unrounded value and rounding to ten decimal places happens once, at the return boundary.

One relationship is worth having in your head, because it is the most useful thing on the page. For a fixed power and a fixed distance, the copper required falls with the square of the system voltage. Doubling the voltage halves the current and doubles the volts you can afford to lose, and those two effects multiply. The worked example's 240 W load needs 21,500 circular mils at 12 V and 5,375 at 24 V — a quarter as much, and the difference between 6 AWG and 12 AWG.

A worked example.

Example

A 20 A DC load — a decent-sized fridge compressor, a water pump, a run of accessory sockets — sits 15 ft from the battery on a 12 V system, wired in copper, held to a 3% drop. The budget first. 3% of 12 V is 0.36 V. That is the entire allowance for the trip out and the trip back, and it is the number that makes low-voltage DC hard. Now the area. CM = 2 × 12.9 × 20 × 15 / 0.36. The numerator is 7,740, and dividing by 0.36 gives 21,500 circular mils. Checking the ladder: 8 AWG is 16,510, which is short; 6 AWG is 26,240, which clears it. So voltage drop wants 6 AWG copper. The ampacity floor barely registers. Twenty amperes in the 90 °C copper column of NEC Table 310.16 is met by 14 AWG, which is rated 25 A. That is three trade sizes below what the drop budget demanded, which is the normal state of affairs down here. The answer is therefore 6 AWG copper, governed by voltage drop. On that conductor the actual drop is 7,740 / 26,240 = 0.29 V, which is 2.46% of 12 V, leaving 11.71 V at the load. Comfortably inside budget, and the margin is real rather than notional — a battery under load will already have sagged below 12 V at the source, and that sag comes off the figure at the load on top of the drop calculated here. For contrast, take the identical current and the identical distance and put it on a 120 V circuit. The budget becomes 3.6 V, the required area becomes 2,150 circular mils, and 14 AWG covers it. Four trade sizes apart, from nothing but the voltage. And for the other contrast, take the same 240 W of load to 24 V. The current halves to 10 A and the allowance doubles to 0.72 V, so the required area falls by a factor of four to 5,375 circular mils — 12 AWG. That is the argument for a 24 V or 48 V system in one line, and it is why the system-voltage field is worth experimenting with before any cable is bought.

conductor Materialcopper
insulation Rating90
one Way Length Ft15
max Voltage Drop Percent3
load Watts240
load Basisamps
load Amps20
system Voltage12

Frequently asked questions.

What size wire do I need for a 12V system?
It depends far more on the distance than on the current, which is the thing that surprises people coming from AC work. At 12 V a 3% budget is 0.36 V total, so the area you need is 2 × 12.9 × amps × one-way-feet / 0.36 circular mils. A 20 A load 5 ft away needs about 7,167 circular mils — 10 AWG. The same 20 A load 15 ft away needs 21,500 — 6 AWG. At 30 ft it is 43,000, which is 3 AWG. The current never changed; the distance tripled, then doubled, and the copper roughly followed. If the answer is coming out silly, the real fix is usually a 24 V system, a shorter run, or moving the source rather than more copper.
Is 12V and 24V wire sizing really the same calculation?
Yes, and that is why this page has a voltage selector rather than a separate page per voltage. The equation is identical; only two numbers move, and they move in the same direction. Going from 12 V to 24 V halves the current for a given power and doubles the volts a given percentage buys you, so the required area falls by a factor of four. Going to 48 V drops it by sixteen. There is nothing special about 12 V or 24 V beyond the arithmetic — 36 V and 120 V DC behave exactly the same way, which is why they are options here too.
Should I use 3% or 10% voltage drop?
3% is the normal design target and matches NEC 210.19(A) Informational Note No. 4. ABYC E-11.14.2.6 draws the line by criticality rather than by preference: 3% maximum for panelboard and switchboard main feeders, bilge blowers, electronic equipment, navigation lights and anything else where drop must be kept to a minimum, and 10% for lighting other than navigation lights and other circuits where drop is not critical. The honest test is what the load does when it browns out. LED lighting dims and generally survives. A motor draws more current, makes less torque and runs hotter — a pump or compressor at 10% low is a pump or compressor that will fail early. Inverters and electronics often have low-voltage cutouts that will simply shut down, which on a 12 V system already sagging under load can happen a lot sooner than you expect.
Do I measure the run one-way or there and back?
Enter it one-way, source to load. The calculator doubles it internally, because on DC the return conductor drops exactly as much as the supply conductor. This trips people up constantly, and the reason is that ABYC's published wire tables are printed the other way round — their column header reads 'Length of Conductor from Source of Current to Device and Back to Source'. Carry a number between the two without halving or doubling it and you will be out by a factor of two, which on a 12 V circuit is a whole trade size or more. Measure along the route the cable actually takes, not straight-line, and be generous about bends and drops.
Can I use this for a boat?
No. Marine DC wiring is governed by ABYC E-11, not the NEC, and the differences are not cosmetic. E-11 has its own conductor ampacity table, its own resistance constant, its own voltage-drop tables IX and X, and requires the larger of the ampacity and voltage-drop answers under E-11.14.2.7. It also mandates stranded, usually tinned, conductors — solid building wire work-hardens and fails in a vibrating environment — and has its own rules about routing, support and protection from chafe. Working E-11's own tables by hand shows they cannot be reproduced from any single constant: in places they are one trade size more conservative than either the NEC constant or ABYC's own gives. They have to be read, not calculated. Use them.
Does this cover solar panels and battery banks?
It sizes a conductor for a current you give it, which is the last step. It does not compute that current, and for PV that step has its own rules. NEC 690.8 stacks factors on the short-circuit current of a PV source circuit before you get to a conductor at all, and battery and energy-storage circuits fall under Article 706. The battery side of an inverter is its own category of problem: a 2,000 W inverter on a 12 V bank draws over 170 A continuously and several times that on surge, which is a busbar, lug and fusing question more than a wire-gauge one. Size it properly, fuse it at the battery end, and get it inspected — a battery bank is a fault-current source with nothing upstream to protect you.
Why is the ampacity answer so much smaller than the voltage-drop answer?
Because they are answering different questions and only one of them scales with distance. Ampacity asks how much current a conductor can carry before its insulation cooks, and the answer does not care whether the run is one foot or a hundred. Voltage drop asks how much voltage is lost getting there, and that is directly proportional to length. At 240 V the drop budget is large enough that heat usually decides; at 12 V the budget is twenty times smaller and drop wins almost immediately. Seeing a three- or four-size gap between the two answers on this page is normal and is the point. It reverses only when the current is very high and the run is very short — the battery-to-inverter cable being the standard example — and the page tells you when that has happened.
What does the calculator not do?
It does not size fuses or breakers, which on a DC system have to be rated for DC interrupting duty and placed at the source end of the run. It does not apply temperature correction or bundling derates to the ampacity floor — that floor is taken at NEC Table 310.16's own basis of 30 °C and no more than three conductors, and an engine bay or a bundled conduit is neither. It does not cover boats, PV circuit-current stacking, vehicle wiring under SAE rules, terminations, lugs, crimps or strain relief. And it has not seen your installation. Take the number to a licensed electrician or a qualified installer.

References& sources.

  1. [1]National Fire Protection Association, NFPA 70 — National Electrical Code, 2023 edition. Chapter 9 Table 8 (Conductor Properties — circular-mil areas and DC resistance at 75 °C), Table 310.16 (allowable ampacities, used here as a floor), and 210.19(A) Informational Note No. 4 (the 3% branch-circuit recommendation, which is guidance and not enforceable code). The code text is gated behind NFPA's free-access registration and was not opened directly; the values used here were transcribed from reproductions and cross-checked. Retrieved 2026-07-29.
  2. [2]American Boat and Yacht Council, Standard E-11, "AC and DC Electrical Systems on Boats", excerpts published by Paneltronics. Read directly from the PDF on 2026-07-29. E-11.14.2.6 requires a maximum 3 percent drop on panelboard and switchboard main feeders, bilge blowers, electronic equipment and navigation lights, and 10 percent on lighting and other circuits where drop is not critical; E-11.14.2.7 sizes conductors from Table VI and checks them against Tables IX and X, requiring the larger conductor where the two conflict. Cited as the scope boundary for this page: marine wiring must be sized from ABYC's tables, not from the NEC-based method used here. The tables also print their length column as source-to-device-and-back, which is the origin of the one-way/round-trip confusion this page warns about.
  3. [3]Mike Holt Enterprises, "Voltage Drop Calculations". Retrieved 2026-07-29. Source of the K constants used here — 12.9 ohm-circular-mils per foot for copper and 21.2 for aluminium, defined as the DC resistance of a 1,000-circular-mil conductor 1,000 ft long at 75 °C and derived from NEC Chapter 9 Table 8 — and of the VD = 2·K·I·L/CM form. The constants were checked arithmetically against Chapter 9 Table 8: 12.9 ÷ 105,600 circular mils gives 0.1222 Ω per 1,000 ft against the table's 0.122 for 1/0 copper, and 21.2 ÷ 211,600 gives 0.1002 against 0.100 for 4/0 aluminium.
  4. [4]NECA/IBEW Electricians, reproduction of NEC Table 310.15(B)(16) (renumbered Table 310.16 from the 2020 edition onward), "Allowable Ampacities of Insulated Conductors Rated Up to and Including 2000 Volts, 60 °C Through 90 °C". Read directly from the PDF on 2026-07-29. Source of the ampacity floor and of the circular-mil areas, shared with the AC wire size calculator so the two pages can never disagree about a table value.

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