Audited 29 Jul 2026·Last updated 28 Oct 2026·4 citations·Tier 2·0 uses

Angular Size Calculator

Find the angle an object spans from its size and distance, or size or distance from the angle, with sphere and flat geometry and the small-angle error.

Angular Size Calculator

Solve for
Object geometry
True diameter, in ANY unit you like — just use the same unit for the distance. Default is the Moon: 3474.8 km, twice JPL's mean radius of 1737.4 km from ephemeris DE440.
Distance in the SAME unit as the size. Default is the conventional mean Earth–Moon distance of 384 400 km; the real distance swings between about 356 500 and 406 700 km each month.
In arcseconds: 1° = 3600″ and 1′ = 60″. The default is the Moon's mean angular diameter. Must be under 648000″ (180°) — nothing subtends half a turn from outside itself.
″
Angular size
1,864.5267
The exact angle the object spans, in arcseconds, for the geometry you chose.
Angular size (arcminutes)
31.0754′
Angular size (degrees)
0.5179°
Physical size
3,474.8
Distance
384,400
Small-angle shortcut
1,864.5394″
Shortcut error
6.809 × 10⁻⁴ %
Size ÷ distance
0.009
Reading
1864.5267″ (31.0754′), computed with flat geometry (2·arctan, a disc or chord across the line of sight). The small-angle shortcut θ ≈ d⁄D is only 0.00068 % off here, so it is safe for this object.

Background.

Held 70 cm from the eye, roughly at arm's length, an object only 6.33 mm wide is enough to blot out the full Moon. Most people guess something far bigger, because what the eye actually judges is angular size, the angle an object spans as seen from where you stand, and the Moon's is only about half a degree. That angle depends on true size and distance together, which is how the Sun, about 400 times wider than the Moon but also about 390 times farther away, ends up looking almost the same.

Give the calculator any two of size, distance and angle and it returns the third. Size and distance can be in any unit, kilometres for a planet or millimetres for a coin, as long as both use the same one: the angle depends only on their ratio, and a size you solve for comes back in the distance's unit.

You also choose the geometry, because a flat object and a sphere are not seen the same way. Across a disc, a crater or the face of a building, the edges are the ends of a chord, and the angle is twice the arctangent of half the size over the distance. For a planet, moon or star your sight lines graze the limb of a sphere, the distance runs to its centre, and the angle becomes twice the arcsine. For the Moon the two differ by 0.019 arcseconds out of about 1,865, but standing on a sphere's surface the arcsine correctly gives 180 degrees while the arctangent gives 90.

Alongside the exact answer you get the familiar small-angle shortcut, angle in arcseconds ≈ 206,264.806 × size ÷ distance, and how far it is off for your numbers.

What is angular size calculator?

Angular size, or angular diameter, is the angle an object subtends at the observer, measured in degrees, arcminutes or arcseconds: one degree is 60 arcminutes (′) and one arcminute is 60 arcseconds (″), so a degree holds 3,600″. A radian, the natural unit of the trigonometry, is 648,000 ÷ π = 206,264.806″. For scale, the full Moon and the Sun each span a little over half a degree, about 31 to 32′, while a fist at arm's length covers roughly 10°. The Moon's own figure changes through each month, from about 29.4′ when it is farthest to 33.5′ when it is nearest.

How to use this calculator.

  1. Choose what to solve for: the angle from size and distance, the physical size from angle and distance, or the distance from angle and size.
  2. Choose the geometry. Sphere suits a planet, moon or star, with the distance measured to its centre; flat suits a disc, crater, building or any width measured across the line of sight.
  3. Enter size and distance in the same unit. An angle goes in as arcseconds: multiply degrees by 3,600 or arcminutes by 60.
  4. Read the result in arcseconds, arcminutes and degrees, and check the shortcut error before quoting the small-angle figure.
  5. For the Moon or a planet, use the distance on the date you care about; a mean distance gives only a mean answer.

The formula.

flat: θ = 2·arctan(d ⁄ 2D) sphere: θ = 2·arcsin(d ⁄ 2D) shortcut: θ ≈ 206264.806 · d ⁄ D

Draw a line from the eye to the centre of the object. For a flat object of width d at distance D, each half of the object makes a right triangle with that line, so tan(θ⁄2) = (d⁄2) ÷ D and θ = 2·arctan(d ⁄ 2D). For a sphere of diameter d with its centre at distance D, the sight line to the edge touches the surface at right angles to a radius, so sin(θ⁄2) = (d⁄2) ÷ D and θ = 2·arcsin(d ⁄ 2D). Solving for size or distance simply rearranges these: d = 2D·tan(θ⁄2) or D = d ⁄ (2·tan(θ⁄2)), with sine in place of tangent for a sphere. Multiplying radians by 206,264.806 gives arcseconds.

The small-angle shortcut drops the trigonometry: θ ≈ d ⁄ D radians. Against the flat relation it always reads slightly high, by about (d⁄2D)² ÷ 3; against the sphere it reads slightly low, by about half that. The flat error reaches 0.1% at a size-to-distance ratio of 0.1096, an angle of 6.2727°, and the sphere error at a ratio of 0.1548, or 8.8776°. Below those angles the shortcut is fine for most purposes.

Some inputs have no answer and are refused: a size or distance of zero or less; an angle of 648,000″ (180°) or more, since nothing outside you subtends half a turn; and, for a sphere, a size more than twice the distance, which would place you inside it. A size exactly twice the distance is allowed and returns 180°, the view from the surface.

A worked example.

Example

How far away must a 25 mm coin be to cover the full Moon exactly? The Moon's mean angular diameter, using flat geometry for a 3,474.8 km Moon at 384,400 km, is 1864.5267 arcseconds, or 31.0754 arcminutes. Solving for distance: half the angle is 932.2634″, which divided by 206,264.806 is 0.0045197 radians, and its tangent is 0.0045197711. Then D = 25 ÷ (2 × 0.0045197711) = 2765.6268 mm, about 2.77 m. The same figure follows with no trigonometry at all, because a fixed angle means a fixed ratio of size to distance: 25 × 384,400 ÷ 3,474.8 = 2765.6268 mm. That is roughly four times arm's length. Held at 70 cm, the same coin spans 2.0461°, almost four Moons across, which is why the Moon in a photograph so often looks smaller than it felt at the time.

physical Size25
distance384,400
geometryflat
known Angle Arcsec1,864.527
solve Fordistance

Frequently asked questions.

Should I choose the sphere or the flat setting?
Sphere for anything that is one, such as a planet, the Moon, the Sun or a star, with the distance measured to its centre. Flat for a disc, a crater floor, a building or any width measured across the line of sight. For distant objects the choice barely matters: for the Moon it shifts the answer by 0.019″. It matters a great deal up close.
Why does the Moon look bigger near the horizon?
Its angle is actually slightly smaller there. Overhead you are nearly one Earth radius, about 6,378 km, closer to it than when it sits on the horizon, so the overhead Moon spans about 31.6′ against 31.08′ at the horizon, some 1.7% more. The horizon enlargement is a perceptual effect known as the Moon illusion; a coin held at a fixed distance reveals no enlargement at the horizon at all.
Why do the Sun and Moon look almost the same size?
The Sun is about 400 times the Moon's diameter and, at one astronomical unit, about 389 times its mean distance. Using the IAU's nominal solar radius of 6.957 × 10⁸ m gives the Sun 1918.46″ against the Moon's 1864.55″ as a sphere, a ratio of 1.0289. That near-match makes total eclipses possible, and because the Moon is slowly receding, by about 3.8 cm a year, it will not last forever.
How much does the Moon's apparent size change over a month?
Its distance swings between about 356,500 km and 406,700 km, so its angular diameter ranges from about 33.51′ at its nearest to 29.37′ at its farthest, a ratio of 1.1408. The coin that covers it would need to sit 2.565 m away at the near point and 2.926 m away at the far point.
When is the small-angle approximation good enough?
For flat geometry it stays within 0.1% up to about 6.27°, and for a sphere up to about 8.88°. Almost everything seen in the sky is far below that; the Moon's shortcut error is 0.00068% with flat geometry. The shortcut fails for nearby objects that fill a large part of your view, such as a building you are standing beside.
Can I work out how big a distant object is from its angle?
Yes: solve for physical size with flat geometry. A tower that spans exactly 1°, which is 3,600″, from 2 km away is 2 × 2,000 × tan(0.5°) = 34.907 m tall. The answer comes back in the distance's unit, so entering 2 for kilometres would give 0.0349 km instead.

How this page was produced

Published by
Quanta Calculator
Primary sources
4 cited below
Method
flat: θ = 2·arctan(d ⁄ 2D) sphere: θ = 2·arcsin(d ⁄ 2D) shortcut: θ ≈ 206264.806 · d ⁄ D
Published
Last verified

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