Audited ·Last updated 29 Jul 2026·4 citations·Tier 2·0 uses

Angular Size Calculator

Angular diameter from size and distance, or either one back from the angle. Separate sphere and flat geometry, plus the small-angle error measured for you.

Angular Size Calculator

Solve for
Object geometry
True diameter, in ANY unit you like — just use the same unit for the distance. Default is the Moon: 3474.8 km, twice JPL's mean radius of 1737.4 km from ephemeris DE440.
Distance in the SAME unit as the size. Default is the conventional mean Earth–Moon distance of 384 400 km; the real distance swings between about 356 500 and 406 700 km each month.
In arcseconds: 1° = 3600″ and 1′ = 60″. The default is the Moon's mean angular diameter. Must be under 648000″ (180°) — nothing subtends half a turn from outside itself.
Angular size
1,864.5267
The exact angle subtended, in arcseconds, for the geometry you chose. Not the small-angle approximation.
Angular size (arcminutes)
31.0754′
Angular size (degrees)
0.5179°
Physical size
3,474.8
Distance
384,400
Small-angle shortcut
1,864.5394″
Shortcut error
0.0007 %
Size ÷ distance
0.009
Reading
1864.5267″ (31.0754′), computed with flat geometry (2·arctan, a disc or chord across the line of sight). The small-angle shortcut θ ≈ d⁄D is only 0.00068 % off here, so it is safe for this object.

Background.

Angular size is how big something looks rather than how big it is: the angle it spans as seen from where you stand. It is the quantity that makes the Moon and the Sun appear the same size despite one being four hundred times larger, and it is the only size an astronomer can measure directly. This calculator solves the relation in all three directions — angle from size and distance, size from angle and distance, and distance from angle and size — and it does two things most angular size calculators do not.

The first is that it lets you choose the geometry, because there are genuinely two relations and they are not the same. For a flat disc, or any chord drawn across the line of sight, the angle is twice the arctangent of half the size over the distance. For a sphere it is twice the arcsine, because what you actually see is the tangent limb rather than a diameter drawn through the centre, and the distance is measured to the centre. Almost every calculator online silently uses the arctangent for everything. For the Moon the difference is 0.019 arcseconds out of 1864 — one part in a hundred thousand, which is why nobody notices. Stand on the surface of a sphere and the difference is the entire answer: the sphere relation gives 180 degrees, which is correct, and the flat one gives 90 degrees, which is not.

The second is the unit policy. Size and distance are entered in whatever unit you like, as long as it is the same unit for both, because the angle depends only on their ratio. Kilometres for the Moon, millimetres for a coin, astronomical units for a planet, light-years for a galaxy — all work, and solving for a size returns it in whatever unit the distance was given in. This is not evasion. It removes an entire category of unit-mismatch error, and it makes a strong test possible: scale both inputs by a factor of a billion and every angle output must come back identical.

The small-angle shortcut is reported next to the exact answer along with its own error, rather than being described in words. The familiar approximation says the angle in arcseconds is roughly 206265 times the size divided by the distance. Its error is about the square of half the size-to-distance ratio, divided by three: it stays under a tenth of a percent out to a size-to-distance ratio of 0.1096, which is a subtended angle of about 6.27 degrees, and grows quadratically after that. For the Moon it is 0.00068 percent high. The shortcut always over-estimates, never under, because the tangent function grows faster than its argument.

Three situations are genuine singularities rather than merely awkward, and the calculator refuses them with a message naming the field. A size or distance of zero or less has no meaning. An angle of 648000 arcseconds is 180 degrees, and nothing subtends half a turn or more when you are outside it, so any angle at or above that is rejected. And in sphere geometry a size more than twice the distance would put you inside the body: the arcsine is undefined there and the question has no answer. A size exactly twice the distance — you standing on the surface — is accepted and correctly returns 180 degrees.

The defaults describe the Moon, and they are ordinary editable inputs rather than baked-in constants. The diameter of 3474.8 kilometres is twice JPL's mean radius of 1737.4 kilometres from ephemeris DE440; the distance of 384400 kilometres is the conventional mean, and the real Earth–Moon distance swings between roughly 356500 and 406700 kilometres over a month. That seven-percent monthly variation dwarfs every other uncertainty on this page, and it is the reason the Moon's apparent size visibly changes between perigee and apogee.

What is angular size calculator?

The angular size, or angular diameter, of an object is the angle it subtends at the observer's eye. It is measured in degrees, arcminutes (1/60 of a degree) or arcseconds (1/3600 of a degree), and it depends on both the object's true size and its distance — never on either alone.

A useful set of reference points: the full Moon and the Sun are both close to half a degree, or about 31 to 32 arcminutes. The planet Jupiter at its best is about 50 arcseconds. A typical star is well under a thousandth of an arcsecond, which is why stars look like points in any telescope. At the other end, an outstretched fist at arm's length covers roughly 10 degrees and a thumb about 2.

For a sphere the correct relation involves the arcsine rather than the arctangent, because the visible edge of a sphere is where your line of sight is tangent to it, slightly closer than a diameter through the centre would suggest. The two forms converge for distant objects and diverge sharply for nearby ones.

How to use this calculator.

  1. Choose what you are solving for: the angle, the physical size, or the distance.
  2. Choose the geometry. Use 'sphere' for a planet, moon or star; use 'flat' for a disc, a crater, a building or anything measured across the line of sight.
  3. Enter the two quantities you know. Size and distance must be in the same unit — any unit at all, as long as it is the same one.
  4. If you are entering an angle, give it in arcseconds: multiply degrees by 3600 or arcminutes by 60.
  5. Read the answer in arcseconds, arcminutes and degrees together.
  6. Check the shortcut error before quoting the small-angle approximation. Under 0.1 % it is safe; above that, use the exact value.

The formula.

flat: θ = 2·arctan(d ⁄ 2D) sphere: θ = 2·arcsin(d ⁄ 2D) shortcut: θ ≈ 206264.806 · d ⁄ D

Drop a perpendicular from the observer to the object's centre line. For a flat object of diameter d at distance D, half the object subtends an angle whose tangent is (d/2)/D, so the full angle is twice the arctangent of d/2D. For a sphere the geometry is different: your line of sight touches the surface tangentially, forming a right angle with the radius at that point, so half the angle has sine (d/2)/D and the full angle is twice the arcsine. That is the entire derivation, and it is why the sphere always subtends the larger of the two angles.

Work through the default configuration. The Moon's diameter is 3474.8 km and its mean distance 384400 km, so d/2D = 0.0045197711. The arctangent series gives 0.0045197403, and doubling that gives 0.0090394806 radians. Multiplying by 206264.806247 arcseconds per radian gives 1864.5267124920 arcseconds — 31.0754452082 arcminutes, or 0.5179240868 degrees, which is the familiar 'just over half a degree'. The sphere relation on the same inputs gives 1864.5457571085 arcseconds, larger by 0.019 arcseconds. The small-angle shortcut gives 1864.5394088122 arcseconds, which is 0.0006809406 % high. Notice the ordering: arctangent below the shortcut, arcsine above it. That is forced by the series expansions and holds for every positive input.

ROUNDING STAGE. Nothing is rounded part-way through. All arithmetic runs at forty significant digits and rounding happens once, at the return boundary, to ten decimal places. The figures in the reading sentence are display roundings of the same unrounded values.

SIGNIFICANT FIGURES. Entirely governed by the inputs. Astronomical diameters and distances are usually known to four to six significant figures, and the Earth–Moon distance varies by seven percent over a month, so treat the trailing digits of a ten-decimal answer as display precision rather than accuracy.

APPROXIMATION REGIME, MEASURED. The small-angle form θ ≈ d/D is shown with its own error rather than assumed. That error is approximately (d/2D)²/3 and it crosses 0.1 % at a size-to-distance ratio of 0.109588322, corresponding to a subtended angle of 6.2726756 degrees. Doubling the ratio roughly quadruples the error. Below that line the shortcut is genuinely fine; above it, use the exact figure.

INVALID DOMAIN. A size or distance of zero or less is rejected. An angle at or above 648000 arcseconds — 180 degrees — is rejected, because nothing subtends half a turn or more when the observer is outside it. And in sphere geometry a size greater than twice the distance places the observer inside the body, where the arcsine has no value; that case is rejected with a message quoting the radius and the distance back. A size exactly twice the distance is accepted and correctly returns 180 degrees, the case of standing on the surface.

A worked example.

Example

Here is the classic demonstration that the Moon is smaller than people think. How far from your eye must you hold a 25 mm coin for it to exactly cover the full Moon? The Moon's mean angular diameter is 1864.526712492 arcseconds. Solving the flat relation for distance, D = d ⁄ (2·tan(θ⁄2)), with d = 25 mm gives 2765.6267986647 mm — about 2.77 metres, which is roughly three long paces. A coin at arm's length, about 70 cm, is nearly four times too big; that is why the Moon always looks smaller in a photograph than it felt at the time. The answer can be checked without touching a trigonometric function at all. Because the angle is fixed, the ratio of distance to size is fixed too, so the coin's distance must be 25 × 384400 ⁄ 3474.8 = 2765.6267986647 mm — identical to ten decimal places. The calculator's test suite asserts exactly this as an independent route to the same number. One caveat that matters for the demonstration: the Moon's distance varies by about seven percent over each month, from roughly 356500 km at perigee to 406700 km at apogee. Its angular diameter therefore swings from about 33.5 arcminutes down to about 29.4, a 14 percent range in apparent width. At perigee the coin needs to be about 2.6 metres away; at apogee about 3.0 metres. Everything else on this page is exact to ten digits, and this single input is the reason you should not trust more than three.

physical Size25
distance384,400
geometryflat
known Angle Arcsec1,864.527
solve Fordistance

Frequently asked questions.

Should I use the sphere setting or the flat setting?
Use sphere for anything that genuinely is one — a planet, a moon, the Sun, a star — because what you see is the tangent limb rather than a diameter drawn through the centre, and the distance is measured to the centre. Use flat for a disc, a ring, a crater floor, a building, or any dimension measured across the line of sight rather than through the body. For distant objects the choice makes no practical difference: for the Moon it changes the answer by one part in a hundred thousand. For nearby ones it changes everything: an observer on the surface of a sphere sees 180 degrees on the correct relation and 90 on the wrong one.
What unit should I enter the size and distance in?
Any unit, as long as it is the same for both. The angle depends only on the ratio, so kilometres and kilometres works, millimetres and millimetres works, astronomical units and astronomical units works. If you solve for the physical size, the answer comes back in whatever unit you gave the distance in, and vice versa. Mixing units — a size in kilometres and a distance in astronomical units — will give a confidently wrong answer, which is the one mistake this design cannot protect you from, so check before you read.
When can I use the small-angle approximation?
Up to about six degrees, if a tenth of a percent is good enough. The shortcut says the angle in arcseconds is 206265 times the size divided by the distance, and its error is roughly the square of half the size-to-distance ratio divided by three. That crosses 0.1 % at a ratio of 0.1096, which is a subtended angle of 6.27 degrees. The calculator shows the shortcut and its error next to the exact answer so you never have to guess. The error is always positive: the shortcut over-estimates, because the tangent grows faster than its argument.
Why does the Moon look bigger near the horizon?
It does not. Its angular size near the horizon is actually very slightly smaller, because you are further from it by roughly one Earth radius. The apparent enlargement is the Moon illusion, a perceptual effect that has been argued about since Ptolemy and is still not fully settled. You can demonstrate it with this calculator plus a coin: work out the distance at which a coin exactly covers the Moon, then try it at the horizon and again overhead. The coin covers it both times.
Why do the Sun and Moon look the same size?
Coincidence, and a temporary one. The Sun's diameter is about 400 times the Moon's and it is about 400 times further away, so the two ratios nearly cancel. Feeding the IAU's exact nominal solar radius of 6.957 × 10⁸ m and the exact astronomical unit into this calculator gives a solar diameter of 1918.46 arcseconds against the Moon's 1864.55 — a ratio of 1.0289. That near-match is what makes total solar eclipses possible, and it will not last: the Moon recedes by about 3.8 cm a year, so in the far future only annular eclipses will remain.
How precise is the answer?
The arithmetic runs at forty significant digits and is rounded once at the end, so it contributes nothing. All the uncertainty is in what you type. JPL's lunar mean radius is 1737.4 ± 0.1 km, five significant figures; but the Earth–Moon distance varies by seven percent over a month, so a 'mean' distance is only meaningful to about two. As a rule, count the significant figures in your least certain input and trust that many in the answer, no matter how many digits appear.

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