Audited ·Last updated 29 Jul 2026·4 citations·Tier 2·0 uses

Telescope Field of View Calculator

True field of view from an eyepiece field stop or apparent field, in degrees and arcminutes, plus star drift time and whether your focuser barrel clips it.

Telescope Field of View Calculator

Method
Objective or primary-mirror focal length. A longer focal length gives a smaller true field with the same eyepiece.
mm
Engraved on the eyepiece barrel. Used for the magnification, and for the shortcut method.
mm
Published in the eyepiece's specifications. Typical for a 25 mm Plössl is around 21.5 mm. Used by the accurate method.
mm
The eyepiece's marketed field: about 50° for a Plössl, 68–82° for a wide-field. Used by the shortcut method.
°
About 27 mm for a 1.25-inch focuser and about 46 mm for a 2-inch one. Above this the barrel itself becomes the aperture you are looking through.
mm
Used only for the drift time. Stars near the celestial pole drift more slowly because they trace a smaller circle; at exactly ±90° they never drift out at all.
°
True field of view
1.0265
The angular diameter of the patch of sky visible through the eyepiece, in degrees. For reference, the full Moon is about half a degree across.
True field (arcminutes)
61.593′
Magnification
48×
Apparent field of view
49.2744°
Field stop diameter
21.5 mm
Widest field this barrel can pass
1.2892°
Star drift time across the field
245.6991 s
Reading
1.027° (61.6′) of sky. Computed from the 21.5 mm field stop, which is the accurate method. Your focuser barrel can pass up to 1.289°, so nothing is being clipped here. A star at this declination takes 245.7 s to drift across the field with the drive off.

Background.

This calculator tells you how much sky an eyepiece actually shows in your telescope, using either of the two methods observers use — and it deliberately lets you compare them, because they frequently disagree.

The accurate method uses the eyepiece's field stop. That stop is a physical ring of metal sitting in the focal plane, and its diameter divided by the telescope's focal length is the field in radians, no assumptions required. Tele Vue publishes exactly this relation for its own eyepieces, written with the degrees-per-radian constant rounded to 57.3; this page uses the unrounded 57.29577951, which is 0.0074 % smaller.

The shortcut method divides the eyepiece's marketed apparent field by the magnification. It is the only method available when a manufacturer publishes a degree figure and no field stop, and it assumes the eyepiece maps angle to image height without distortion. Real wide-field designs do not. In the worked example on this page the same 25 mm eyepiece gives 1.0265° from its 21.5 mm field stop and 1.0833° from its marketed 52° apparent field — a gap of 5.5 %, which is not an error in either number but a measure of the eyepiece's distortion. Whenever the two disagree, believe the field stop, and treat the implied field stop this page reports as a cross-check on the marketing figure.

Two outputs make the number useful rather than abstract. The first is the widest field your focuser can physically deliver: a 1.25-inch barrel tops out at a field stop of about 27 mm and a 2-inch barrel at about 46 mm, so on a 1200 mm telescope no 1.25-inch eyepiece can ever show more than about 1.29° no matter what its apparent field claims. The calculator says so directly when your chosen field exceeds the barrel limit. The second is the drift time — how many seconds a star takes to cross the field with the drive switched off. That is a genuinely astronomical quantity rather than a geometric one: the sky turns 360° in one mean sidereal day of 86164.09 seconds, and a star at declination δ traces a smaller circle, so its rate across the field falls with cos δ. Timing a drift is also the classic way to measure a field stop nobody published.

Units are declared throughout. Focal lengths and field stops are in millimetres; all fields and the declination are in degrees; the field is also given in arcminutes because that is the unit deep-sky catalogues use for object sizes; and the drift time is in seconds of time, not seconds of arc. Only the cosine of the declination is used, so a field at −45° and one at +45° drift at the same rate. The field-stop relation is the linear small-angle mapping that is universal for eyepieces; the exact tangent form differs by less than 0.01 % at a 1.3° field and about 0.1 % at 5°, always smaller than the uncertainty in a published field stop. Three significant figures is the honest precision. A declination of exactly ±90° is refused rather than returned as infinity, because a star at the celestial pole genuinely never drifts out of the field.

What is telescope field of view calculator?

The true field of view is the angular diameter of the piece of sky you can see through the eyepiece at one time, measured in degrees or arcminutes. The full Moon is about 0.52° or 31 arcminutes across, so a 1° field shows roughly two Moon-widths.

It is not the same as the apparent field of view, which is how wide the illuminated circle looks to your eye — typically 50° for a Plössl and up to 100° for the widest modern designs. The apparent field is a property of the eyepiece alone; the true field depends on the eyepiece and the telescope together.

The field stop is the physical aperture inside the eyepiece that defines the edge of the field. Because it sits in the telescope's focal plane, its diameter converts directly into a sky angle through the telescope's focal length, which makes it the most reliable route to the true field.

How to use this calculator.

  1. Choose the field-stop method if you know the eyepiece's field stop diameter — it is the accurate one.
  2. Choose the apparent-field method if the manufacturer only publishes a degree figure.
  3. Enter the telescope's focal length in millimetres.
  4. Enter the eyepiece focal length, and then either its field stop diameter or its apparent field.
  5. Set the barrel limit: about 27 mm for a 1.25-inch focuser, about 46 mm for a 2-inch one.
  6. Enter the declination of what you are observing if you want a meaningful drift time; leave it at 0 for the celestial equator.
  7. Compare the implied field stop against the manufacturer's published one. A large gap means the eyepiece has significant distortion and the shortcut method is over-reporting.

The formula.

TFOV = (d_stop ⁄ f_tel) × 180⁄π TFOV ≈ AFOV ⁄ M, M = f_tel ⁄ f_eye t_drift = TFOV × T_sid ⁄ (360 × cos δ)

The field stop sits in the telescope's focal plane, so a ring of diameter d there subtends an angle d/f_tel radians at the objective. Multiplying by 180/π converts that to degrees. Nothing about the eyepiece's internal design enters, which is why this route is trustworthy. The shortcut route instead assumes the eyepiece expands a true angle θ into an apparent angle Mθ exactly, which is only true for a distortion-free design.

Work through the default configuration. A 1200 mm telescope with a 25 mm eyepiece magnifies 48×. A 21.5 mm field stop gives 21.5 × 57.29577951308232 ⁄ 1200 = 1.0265493829°, or 61.5929629766 arcminutes. Multiplying back by the magnification, that field implies an apparent field of 49.2743703813° — noticeably less than the 52° such an eyepiece is usually sold as, which is exactly the discrepancy the page exists to expose. A 27 mm barrel limit corresponds to 1.2891550390°, so nothing is being clipped. And on the celestial equator a star crosses the field in 1.0265493829 × 86164.0905 ⁄ 360 = 245.699 seconds, four minutes and six seconds.

The sidereal day is not typed in as a literal. It is derived as 86400 divided by 1.00273790935, the ratio of mean solar to mean sidereal time published by the U.S. Naval Observatory, which gives 86164.0905 seconds — equivalently 15.041069 arcseconds of sky per second of time at the equator. Deriving it this way means this page and the Sidereal Time calculator cannot drift apart.

ROUNDING STAGE. Nothing is rounded part-way through; all arithmetic runs at forty significant digits and the single rounding is at the return boundary, to ten decimal places. The numbers inside the reading sentence are display-rounded from those same unrounded values.

SIGNIFICANT FIGURES. Three. Field stops are published to a tenth of a millimetre at best, apparent fields are marketing round numbers, and the drift time assumes a perfectly stationary, well-aligned telescope.

APPROXIMATION REGIME. The field-stop formula is the linear mapping y = f·θ, universal for eyepiece field stops. The exact tangent mapping y = f·tan θ differs by about θ²/3 — under 0.01 % on a 1.3° field, roughly 0.1 % at 5°. No telescope-and-eyepiece combination reaches a true field where this matters. The shortcut mode's assumption of zero eyepiece distortion is the one that actually fails, sometimes by several percent.

INVALID DOMAIN. Every focal length and stop diameter must be strictly positive. The declination is restricted to ±89.9°: at exactly ±90° the cosine is zero and the drift time is infinite — physically correct, since a star at the celestial pole never leaves the field, but not a number, so the calculator refuses it with a message that says so.

A worked example.

Example

Take the same 1200 mm telescope and 25 mm Plössl, but now use the shortcut method with the eyepiece's marketed 52° apparent field, and point it at declination +23.5° — roughly the Beehive Cluster in Cancer. The magnification is 1200 ⁄ 25 = 48×, so the shortcut gives 52 ⁄ 48 = 1.0833333333°, which is exactly 65.0 arcminutes. Inverting the field-stop relation, that field would require a stop of 22.6892802756 mm. Now compare with the accurate method. The eyepiece's actual published field stop is 21.5 mm, which gives 1.0265493829°. The shortcut is over-reporting the field by a factor of 1.0553, or 5.5 %. Neither number is a mistake: the eyepiece simply does not have a full 52° of distortion-free apparent field, and the 22.7 mm stop the shortcut implies does not exist. This is why the calculator shows the implied stop — it is the one number you can check against the manufacturer. The drift time is where the declination earns its place. On the celestial equator this 1.0833° field would take 1.0833333333 × 86164.0905 ⁄ 360 = 259.29 seconds to cross. At +23.5° the star traces a smaller circle, cos 23.5° = 0.9170600743, so it drifts more slowly and takes 282.74 seconds — nearly four minutes and forty-three seconds. Point the same eyepiece near the pole and the drift stretches towards hours; that is why polar targets are so much easier to observe without a drive.

max Field Stop Mm27
methodapparentField
eyepiece Focal Length Mm25
apparent Field Degrees52
declination Deg23.5
telescope Focal Length Mm1,200
eyepiece Field Stop Mm21.5

Frequently asked questions.

Why do the two methods give different answers for the same eyepiece?
Because the shortcut assumes the eyepiece has no distortion, and real eyepieces do. The apparent field a maker quotes is measured to the edge of the illuminated circle as the eye sees it, and the mapping from true angle to apparent angle across that circle is not perfectly linear — most designs have several percent of angular-magnification distortion, and wide-field designs have more. The field stop is a physical ring you could put a caliper on, so it does not care about distortion. When the two disagree, believe the field stop.
Where do I find my eyepiece's field stop diameter?
In the manufacturer's specification table — Tele Vue, Explore Scientific and Baader publish it for every eyepiece, and it is often the most useful single number in the spec. If it is not published, you can measure it: point the telescope at a star on the celestial equator with the drive off, time how many seconds it takes to cross the centre of the field, and rearrange the drift-time formula. The calculator's drift-time output is the forward version of exactly that measurement.
What is the widest field my telescope can show?
It is set by the focuser barrel, not by the eyepiece. A 1.25-inch barrel can pass a field stop of about 27 mm and a 2-inch barrel about 46 mm, so on a 1200 mm telescope the ceilings are roughly 1.29° and 2.20° respectively. No eyepiece can beat its own barrel: an eyepiece advertised with a 100° apparent field in a 1.25-inch barrel simply has a short focal length so that the same 27 mm stop covers more apparent degrees. The calculator reports the barrel ceiling and warns when your chosen field exceeds it.
Why does the drift time depend on declination?
Because a star's daily path is a circle of constant declination, and the radius of that circle shrinks as cos δ towards the pole. A star on the celestial equator moves at the full sidereal rate of 15.041069 arcseconds per second of time; one at +60° moves at half that; one at the pole barely moves at all. The calculator refuses a declination of exactly ±90° because the drift time there is genuinely infinite rather than merely large — a star at the celestial pole never drifts out of the field.
Should I use this page or the camera field of view calculator?
Use this page when there is an eye at the back of the telescope, and the Camera Field of View calculator when there is a sensor. They are different calculations: a camera at prime focus has no eyepiece, so there is no field stop and no apparent field, and the field is set by the sensor's physical dimensions and the telescope's focal length through an arctangent. If you are putting a camera on a telescope, treat the telescope's focal length as the lens focal length and use that page.
How accurate is this?
The arithmetic is exact to forty digits and rounded once at the end, so all the uncertainty is in the inputs. Field stops are published to about a tenth of a millimetre; apparent fields are round marketing numbers; and telescope focal lengths are nominal to a percent or two. The linear field-stop mapping introduces less than 0.01 % of error on a typical 1.3° field. Treat three significant figures as meaningful, and expect the drift time to be the most robust number on the page because it depends only on the field and on the rotation of the Earth.

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