Audited ·Last updated 29 Jul 2026·6 citations·Tier 1·0 uses

Telescope Magnification Calculator

Work out telescope magnification from focal lengths, or the eyepiece you need for a target power. Includes exit pupil, Barlow factor and useful limits.

Telescope Magnification Calculator

Solve for
Focal length of the objective lens or primary mirror, in millimetres. Printed on the tube or in the manual. Default is a 200 mm f/6 Newtonian.
mm
Clear diameter of the objective lens or primary mirror, in millimetres. This sets the exit pupil and both usable-magnification bounds.
mm
Focal length engraved on the eyepiece barrel, in millimetres. Used when solving for magnification.
mm
The power you want. Used when solving for the eyepiece focal length you need.
×
Enter 1 for none. A Barlow multiplies the telescope's effective focal length, so a 2× Barlow doubles the magnification and halves the exit pupil.
×
Pupil diameter when fully dark-adapted. About 7 mm at age 20 and roughly 0.4 mm smaller per decade after that (Winn et al. 1994), so enter about 5 mm at 60. This sets the LOWER magnification bound.
mm
A rule of thumb, not physics: 2.0 ×/mm (= 50.8× per inch) is the same as stopping at a 0.5 mm exit pupil. Drop it to 1.0 for a large scope in poor seeing.
×/mm
Magnification
120
Angular magnification, dimensionless: the ratio of the angle an object subtends through the eyepiece to the angle it subtends with the naked eye.
Eyepiece focal length
10 mm
Exit pupil
1.6667 mm
Focal ratio (f/#)
6
Effective focal length
1,200 mm
Magnification per inch of aperture
15.24 ×/in
Lower bound (exit pupil = your pupil)
28.5714×
Upper bound (convention)
400×
Verdict
Usable: 120x sits inside the 28.6x to 400x band for a 200 mm aperture, giving a 1.67 mm exit pupil. The upper end of that band is a convention, not a physical limit; atmospheric seeing often caps you lower.

Background.

This calculator answers the two questions every telescope owner asks about eyepieces, and it answers them in both directions. Give it a telescope focal length and an eyepiece focal length and it returns the magnification. Give it the magnification you want and it returns the eyepiece focal length you need to buy, including the effect of a Barlow lens if you own one. Alongside the headline number it reports the exit pupil, the focal ratio, the effective focal length behind the Barlow, and both ends of the magnification range that is actually worth using with your aperture and your eyes.

The arithmetic is one division, but the physics behind it is worth understanding because it is not the physics of a camera lens. A telescope used visually is an afocal instrument: light arrives from an object effectively at infinity and leaves the eyepiece as a parallel bundle heading for an eye focused at infinity. There is no image on a sensor, so there is no image-to-object size ratio to quote. The only magnification that means anything is angular magnification — how much bigger the object looks in angle — and for an afocal telescope that equals the objective's focal length divided by the eyepiece's focal length. That is why our thin-lens Lens Equation page, which solves 1/f = 1/u + 1/v for a single lens at finite distances, cannot answer this question: both of its distances are infinite here.

The number to watch is not the magnification but the exit pupil. The exit pupil is the image of the objective formed by the eyepiece — the little disc of light you can see floating above the eye lens if you hold the eyepiece at arm's length against a bright sky. Its diameter is the aperture divided by the magnification, and it is the quantity that decides how bright the view is and whether your eye can even take all the light the telescope is delivering. Tele Vue Optics publishes the same relationship two other ways, as aperture divided by exit pupil for the magnification and as eyepiece focal length divided by focal ratio for the exit pupil; this calculator computes it one way and its test suite checks it against the others.

One caveat belongs here rather than buried further down the page, because it changes how you should read the answer. The upper bound labelled 'maximum useful magnification' is a convention, not a law. The familiar version of it — fifty times per inch of aperture, or two times per millimetre — is simply the statement 'stop when the exit pupil reaches half a millimetre', dressed up as a limit. It has no primary source and no derivation, and the two popular forms of it do not even agree with each other: 50× per inch is 1.97× per millimetre, not 2.0. Tele Vue publishes no maximum-magnification formula at all and treats the whole idea as a marketing myth. In practice the atmosphere usually decides for you: a small refractor can be pushed past that ceiling on a steady night with no loss, while a large reflector on an ordinary night may be capped nearer twenty or thirty times per inch by the seeing. Because there is no authority to hard-code, the factor is an editable input on this page, and so is your own pupil diameter, since the lower bound genuinely does depend on the observer.

The lower bound is the one that is real physics. When the exit pupil grows wider than your own dark-adapted pupil, the outer ring of the light cone lands on your iris instead of your retina, and that part of the aperture stops contributing. A twenty-year-old typically dark-adapts to about 7 mm; the measured decline is roughly four tenths of a millimetre per decade after that, so a sixty-year-old should enter about 5 mm and will find the useful range starts higher.

Units and conventions are fixed throughout. Every focal length, aperture and pupil diameter is in millimetres; magnification, focal ratio and the Barlow factor are dimensionless; the inch used for the per-inch figure is the international inch of exactly 25.4 millimetres. The model is paraxial, thin-lens and afocal, and all quantities are reported as positive magnitudes — a Newtonian inverts the image and a star diagonal mirrors it, but neither changes the magnification. Because manufacturers quote focal lengths as round numbers good to a percent or two, treat about three significant figures as meaningful no matter how many the display shows. Any input of zero or less is rejected with a message against the offending field rather than returning an infinity: a zero eyepiece focal length really is a singularity.

What is telescope magnification calculator?

Telescope magnification, also called power, is the ratio of the angle an object subtends when seen through the telescope to the angle it subtends with the unaided eye. It is written with a multiplication sign — 120× means the Moon looks 120 times wider in angle than it does naked-eye — and it is a property of the telescope and eyepiece together, never of the telescope alone. Swap the eyepiece and the magnification changes; the telescope has not changed at all.

For an afocal visual telescope the magnification is the objective's focal length divided by the eyepiece's focal length. A Barlow lens or focal extender sits in front of the eyepiece and multiplies the effective focal length of the objective, so a 2× Barlow doubles whatever magnification the eyepiece was giving.

The exit pupil is the companion quantity: the diameter of the beam leaving the eyepiece, equal to the aperture divided by the magnification. High magnification and a small exit pupil go together by definition, which is why 'more power' always means 'a dimmer image' for an extended object such as a nebula or a planet's disc.

How to use this calculator.

  1. Choose whether you want the magnification an eyepiece gives, or the eyepiece needed for a magnification you have in mind.
  2. Enter the telescope's focal length in millimetres — it is usually printed on the tube, or is the aperture multiplied by the focal ratio.
  3. Enter the aperture, the clear diameter of the objective lens or primary mirror, in millimetres.
  4. Enter either the eyepiece focal length engraved on the barrel, or the magnification you are aiming for.
  5. Set the Barlow factor to 1 if you are not using one, or to its stated power if you are.
  6. Adjust your dark-adapted pupil diameter if you are not in your twenties — subtract roughly 0.4 mm per decade from 7 mm.
  7. Read the magnification, then look straight at the exit pupil: it tells you more about how the view will actually look than the magnification does.
  8. Read the verdict line before trusting the upper bound. It is a convention you can edit, and on most nights the atmosphere is the real ceiling.

The formula.

M = (f_tel × B) ⁄ f_eye d_exit = D ⁄ M = f_eye ⁄ (f_tel·B⁄D) f/# = f_tel ⁄ D

Start from the geometry. A ray from an object at angle θₒ off-axis crosses the objective's focal plane at a height f_tel·tan θₒ. The eyepiece, whose front focal plane sits at that same surface, re-collimates it at an angle θᵢ with the same height f_eye·tan θᵢ. Dividing one by the other gives tan θᵢ ⁄ tan θₒ = f_tel ⁄ f_eye, which is the magnification. Within the paraxial thin-lens model this is exact, not an approximation. The exit pupil follows from the same similar triangles: the eyepiece images the objective at a diameter D·f_eye⁄f_tel, which is the same thing as D⁄M.

Work through the page's default configuration. A 200 mm f/6 Newtonian has a focal length of 1200 mm. With no Barlow the effective focal length is still 1200 mm, so a 10 mm eyepiece gives M = 1200 ⁄ 10 = 120×. The exit pupil is 200 ⁄ 120 = 1.6666666667 mm; computed Tele Vue's other way it is 10 ⁄ 6 = 1.6666666667 mm, identically. The focal ratio is 1200 ⁄ 200 = 6. Expressed per inch of aperture, 120 × 25.4 ⁄ 200 = 15.24× per inch, a long way below the traditional fifty. The lower bound with a 7 mm pupil is 200 ⁄ 7 = 28.5714285714× and the upper bound at 2.0 ×/mm is 400×, so 120× sits comfortably inside the band.

ROUNDING STAGE. Nothing is rounded part-way through. All arithmetic runs at forty significant digits in a dedicated decimal context, and rounding happens exactly once, at the moment a result is returned, to ten decimal places. The numbers that appear inside the verdict sentence are rounded to one or two decimals for readability only, and they are formatted from the same unrounded values that feed the numeric outputs — there is no second, independent calculation behind the prose.

SIGNIFICANT FIGURES. The inputs govern the answer. A telescope advertised as '1200 mm' is typically that to within a percent or so, and eyepiece focal lengths are nominal too, so about three significant figures is the honest precision. The extra digits on screen are display precision, not accuracy.

APPROXIMATION REGIME. Paraxial optics, thin lenses, an afocal train, and an eye accommodated to infinity. The relation stops describing your instrument if you focus on something close enough that the conjugates are finite, or if the train is not afocal at all — a camera at prime focus has no eyepiece and therefore no magnification in this sense. Eyepiece distortion leaves M untouched but breaks the naive 'true field = apparent field ⁄ M' shortcut, which is why true field of view is deliberately left to the Telescope Field of View calculator and its field-stop method rather than being reported here.

INVALID DOMAIN. Every input must be strictly greater than zero. A zero eyepiece focal length sends the magnification to infinity; a zero aperture leaves both the exit pupil and the focal ratio undefined; a zero pupil sends the lower bound to infinity. Each of these raises a labelled error against the field that caused it rather than quietly returning NaN or Infinity.

A worked example.

Example

Jupiter is well placed and you want 240× on your 200 mm f/6 Newtonian. You already own a 2× Barlow. Which eyepiece do you need? The Barlow multiplies the objective's effective focal length, so 1200 mm becomes 2400 mm. The eyepiece that yields 240× is therefore 2400 ⁄ 240 = 10 mm — which is to say the 10 mm eyepiece you already own, used with the Barlow. The same 10 mm eyepiece without the Barlow gives 1200 ⁄ 10 = 120×, exactly half, which is the check that the Barlow is being applied the right way round. The exit pupil at 240× is 200 ⁄ 240 = 0.8333333333 mm, half the 1.6666666667 mm it was at 120×. That halving is the price of the extra power: the same light is spread over four times the apparent area, so Jupiter's disc looks bigger and dimmer. Expressed against the old rule of thumb, 240 × 25.4 ⁄ 200 = 30.48× per inch — well short of the traditional fifty. Both bounds are unchanged by the Barlow because they depend only on the aperture and your eye: the lower bound is 200 ⁄ 7 = 28.5714285714× and the upper bound at the default 2.0 ×/mm convention is 400×. So 240× is inside the band and the verdict reads 'usable'. Whether it is actually usable on the night is a question about the atmosphere, not about the telescope.

dark Adapted Pupil Mm7
target Magnification240
eyepiece Focal Length Mm10
aperture Mm200
telescope Focal Length Mm1,200
max Magnification Per Mm2
barlow Factor2
solve ForeyepieceFocalLength

Frequently asked questions.

Why does my telescope's box claim 675× when this calculator says 400×?
Because the box is quoting the highest number that can be reached with the eyepiece and Barlow in the accessory tray, not a magnification at which anything can be seen. At 675× on a small aperture the exit pupil collapses to a fraction of a millimetre, the diffraction pattern is blown up far past the point where it contains any new detail, and the image is dim, soft and impossible to keep in the field. This is the single most common way beginner telescopes are mis-sold. Judge a telescope by its aperture, not by a magnification claim.
Is the '50× per inch' maximum a real physical limit?
No. It is a rule of thumb with no primary source and no derivation, and it is exactly equivalent to 'stop when the exit pupil reaches half a millimetre'. Even its two popular forms disagree: 50× per inch is 1.97× per millimetre while the metric version of the same rule is 2.0× per millimetre. Tele Vue Optics, which publishes formula sheets for magnification, exit pupil, focal ratio and resolving power, publishes no maximum-magnification formula at all and treats the concept as a myth. That is why the factor is an editable input on this page rather than a hard-coded constant.
What exit pupil should I aim for?
It depends on the target. For faint extended objects such as galaxies and large nebulae, a 4–7 mm exit pupil puts the maximum amount of light on your retina and gives the widest field. For planets, double stars and the Moon, an exit pupil around 0.7–1.5 mm is the usual sweet spot: enough magnification to spread the detail out, not so much that the image goes soft. Below about 0.5 mm most observers see floaters and no new detail. Because exit pupil is aperture divided by magnification, choosing an exit pupil is the same decision as choosing a magnification — it is just expressed in the units that matter to your eye.
How does a Barlow lens fit into the formula?
A Barlow multiplies the telescope's effective focal length, so a 2× Barlow with a 10 mm eyepiece behaves exactly like a 5 mm eyepiece on the bare telescope. This calculator applies it that way: effective focal length equals telescope focal length times the Barlow factor, and the magnification is that divided by the eyepiece focal length. In the worked example above, 1200 mm becomes 2400 mm and a 10 mm eyepiece therefore gives 240× rather than 120×. The exit pupil halves at the same time, because exit pupil is aperture divided by magnification and the aperture has not changed. Real Barlows deviate a little from their nominal factor depending on how far the eyepiece sits from the lens, so treat the stated power as approximate.
Why is there a minimum useful magnification at all?
Because your iris is an aperture stop too. The beam leaving the eyepiece has a diameter of aperture divided by magnification. If that beam is wider than your pupil, the outer annulus of it lands on your iris rather than entering your eye, and the light collected by that outer ring of the objective is simply thrown away — you are using a smaller telescope than you paid for. On a Newtonian it is worse than a plain loss, because the central obstruction sits in the middle of the surviving beam and can become visible as a dark spot. The threshold is your own dark-adapted pupil diameter, which is why it is an input rather than a constant.
How much does my age change the lower bound?
Enough to matter. The dark-adapted pupil is widest in the late teens and early twenties, around 7 mm for most people, and shrinks with age at roughly four tenths of a millimetre per decade; Winn and colleagues measured about 0.043 mm per year in a study of ninety-one normal eyes aged 17 to 83. On a 200 mm aperture a 7 mm pupil puts the lower bound at 28.6×, while a 5 mm pupil raises it to 40×. That is why an eyepiece that gives a glorious wide view to a young observer can look slightly dimmed to an older one through the same telescope. Enter your own figure; the calculator will move the bound with it.
Does the magnification depend on the type of telescope?
No. Refractor, Newtonian, Schmidt-Cassegrain, Maksutov — the magnification is the objective's focal length divided by the eyepiece's focal length in every case, because every one of them is an afocal system when used visually. What differs between designs is the focal length itself for a given tube size: a Schmidt-Cassegrain folds a long focal length into a short tube, so the same eyepiece gives far more magnification in a 2000 mm SCT than in a 600 mm short-tube refractor. Central obstruction, contrast and thermal behaviour differ too, but none of those appear in the magnification formula.
Why does this page not give me the field of view?
Because doing it properly needs information this page does not ask for. The shortcut 'true field equals apparent field divided by magnification' assumes an eyepiece with no distortion, and real wide-field eyepieces have enough of it that the shortcut can be several percent out. The accurate method uses the eyepiece's field stop diameter instead, which is a number the manufacturer publishes separately. Keeping the two calculations on separate pages avoids implying that a magnification alone determines what you see. Use the Telescope Field of View calculator for that, and the Camera Field of View calculator if there is a sensor rather than an eye at the back.
Can I use these numbers for binoculars?
The exit pupil relation transfers directly, and it is the reason binoculars are named the way they are: a 10×50 binocular has a 50 mm aperture at 10×, so the exit pupil is 50 ⁄ 10 = 5 mm. The magnification of a binocular is fixed by its internal design rather than by a swappable eyepiece, so the f_tel ⁄ f_eye calculation is not something you can perform from the outside — but if you know the aperture and the stated magnification you can compute the exit pupil and apply exactly the same reasoning about whether it suits your eyes.
How precise are these answers?
The arithmetic is carried at forty significant digits and rounded once at the end, so the calculation contributes no error worth discussing. The inputs do. Manufacturers' stated focal lengths are nominal and are commonly a percent or two off; eyepiece focal lengths are nominal too; and a Barlow's real amplification depends on the spacing to the eyepiece. Treat about three significant figures as meaningful. None of this affects the decisions the page is for, which are choosing an eyepiece and judging an exit pupil — both of which are robust to a couple of percent.

References& sources.

  1. [1]Tele Vue Optics, Inc., 'Telescope Formulas / Common Telescope Myths'. Manufacturer engineering note. Verified by retrieval to state: Magnification = 'Objective focal length / Eyepiece focal length' and 'Objective diameter / Exit pupil'; Exit Pupil = 'Objective diameter / Magnification' and 'Eyepiece focal length / (Objective f/#)'; Focal Ratio = 'Objective focal length / objective diameter'. Independent of the optics textbooks below, open access. Retrieved 2026-07-29.
  2. [2]Hecht, E. (2017). Optics, 5th edition, §5.7.3 'Telescopes', Pearson Education. Derivation of the angular magnification MP = f_objective / f_eyepiece for the afocal refracting telescope, and of the exit pupil as the image of the aperture stop. Print / bibliographic reference — no authoritative free full text exists, so no URL is offered rather than linking a scan of uncertain provenance.
  3. [3]Winn, B., Whitaker, D., Elliott, D.B. & Phillips, N.J. (1994). 'Factors affecting light-adapted pupil size in normal human subjects.' Investigative Ophthalmology & Visual Science 35(3):1132–1137. Source of the age-related decline in pupil diameter used to justify making the dark-adapted pupil an editable input rather than a fixed 7 mm. Abstract open access; full text paywalled. Retrieved 2026-07-29.
  4. [4]National Institute of Standards and Technology, Special Publication 811 (2008 edition), Appendix B.8 'Factors for Units Listed Alphabetically': inch (in) → metre (m), factor 2.54 E-02, printed in boldface, which the table's own legend defines as exact. That is 25.4 mm exactly, following the 1959 international yard and pound agreement. Used for the magnification-per-inch output. Open access. Retrieved 2026-07-29.
  5. [5]ISO 14132-1:2015, 'Optics and photonics — Vocabulary for telescopic systems — Part 1: General terms and alphabetical indexes of terms'. Standardises the definitions of magnification and exit pupil for telescopic systems used here. Paywalled standard; listed as a bibliographic reference for the terminology, not as free full text.
  6. [6]Born, M. & Wolf, E. (1999). Principles of Optics, 7th (expanded) edition, §4.8 and §8.6, Cambridge University Press. Paraxial treatment of afocal systems and of the pupils of an optical instrument. Print / bibliographic reference.

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