Audited 29 Jul 2026·Last updated 28 Oct 2026·6 citations·Tier 1·0 uses

Telescope Magnification Calculator

Telescope power from focal lengths, or the eyepiece needed for a target power, with Barlow factor, exit pupil, f-ratio and the useful range for your aperture.

Telescope Magnification Calculator

Solve for
Focal length of the objective lens or primary mirror, in millimetres. Printed on the tube or in the manual. Default is a 200 mm f/6 Newtonian.
mm
Clear diameter of the objective lens or primary mirror, in millimetres. This sets the exit pupil and both usable-magnification bounds.
mm
Focal length engraved on the eyepiece barrel, in millimetres. Used when solving for magnification.
mm
The power you want. Used when solving for the eyepiece focal length you need.
×
Enter 1 for none. A Barlow multiplies the telescope's effective focal length, so a 2× Barlow doubles the magnification and halves the exit pupil.
×
Pupil diameter when fully dark-adapted. About 7 mm at age 20 and smaller with age, roughly 5 mm at 60 as a rule of thumb; individual pupils vary widely, so measure yours in dim light if you can. Winn et al. (1994) documented the age decline for light-adapted pupils only, so it is not a source for this dark-adapted figure. This sets the LOWER magnification bound.
mm
A rule of thumb, not physics: 2.0 ×/mm (= 50.8× per inch) is the same as stopping at a 0.5 mm exit pupil. Drop it to 1.0 for a large scope in poor seeing.
×/mm
Magnification
120
Angular magnification, written with ×: how many times wider an object looks through the eyepiece than to the naked eye.
Eyepiece focal length
10 mm
Exit pupil
1.6667 mm
Focal ratio (f/#)
6
Effective focal length
1,200 mm
Magnification per inch of aperture
15.24 ×/in
Lower bound (exit pupil = your pupil)
28.5714×
Upper bound (convention)
400×
Verdict
Usable: 120x sits inside the 28.6x to 400x band for a 200 mm aperture, giving a 1.67 mm exit pupil. The upper end of that band is a convention, not a physical limit; atmospheric seeing often caps you lower.

Background.

Slide a 10 mm eyepiece into a telescope with a focal length of 1,200 mm and Jupiter looks 120 times wider than it does to the naked eye. Swap in a 25 mm eyepiece and the same telescope gives 48×. Magnification belongs to the pairing rather than to the tube: it is the telescope's focal length divided by the eyepiece's, and changing either one changes the view.

That division is the easy part. Whether a given power is worth using depends on two more numbers that come from the same inputs. The exit pupil, the width of the beam of light leaving the eyepiece, equals the aperture divided by the magnification, and it decides how bright the view is and whether your eye can take in all the light the telescope gathers. The useful range of powers runs from a lower bound set by your own pupil to an upper bound set by a rule of thumb, 2× per millimetre of aperture unless you change it. For the default 200 mm f/6 reflector that range is 28.6× to 400×.

The sum also runs backwards. Enter the power you want and you get the eyepiece focal length that delivers it, with any Barlow lens you own built in, so you can see whether a new eyepiece would duplicate one already in the case or ask for more than the sky will allow before you spend money on it.

What is telescope magnification calculator?

Telescope magnification is angular. It is the ratio of the angle an object spans as seen through the eyepiece to the angle it spans to the unaided eye, so at 120× the Moon, half a degree across without the telescope, overflows the field of many eyepieces. A telescope used by eye is afocal: light arrives from a distant object and leaves the eyepiece as a parallel beam for a relaxed eye, so there is no image on a screen whose size could be measured, only angles. Within that model the magnification is exactly the objective's focal length divided by the eyepiece's. The exit pupil is the image of the objective formed by the eyepiece, the small bright disc you can see floating behind the eye lens when the telescope points at a bright sky. Its diameter is the aperture divided by the magnification.

How to use this calculator.

  1. Under Solve for, choose Magnification from an eyepiece to check an eyepiece you have, or Eyepiece needed for a target power to plan a purchase.
  2. Enter the telescope focal length in millimetres from the tube label or manual. If only the focal ratio is printed, multiply it by the aperture: a 200 mm f/6 mirror has a 1,200 mm focal length.
  3. Enter the aperture, the clear diameter of the main lens or mirror, in millimetres. A telescope sold as an 8-inch has an aperture of 8 × 25.4 = 203.2 mm.
  4. Enter the eyepiece focal length engraved on its barrel, or the magnification you want. Set Barlow / focal extender to its stated factor, or to 1 if you are not using one.
  5. Adjust Your dark-adapted pupil to suit your age: about 7 mm suits most young adults, and many people in their sixties reach only about 5 mm. Leave the upper-limit convention at 2 unless you want a stricter ceiling, such as 1 for a large telescope under unsteady air.
  6. Read the magnification together with the exit pupil and the verdict. The exit pupil says more about how the view will look than the magnification does.

The formula.

M = (f_tel × B) ⁄ f_eye d_exit = D ⁄ M = f_eye ⁄ (f_tel·B⁄D) f/# = f_tel ⁄ D

With a Barlow of factor B, M = (f_tel × B) ⁄ f_eye, where f_tel is the telescope's focal length and f_eye the eyepiece's, both in millimetres. Solving for the eyepiece instead gives f_eye = (f_tel × B) ⁄ M. The exit pupil is d_exit = D ⁄ M, with D the aperture; written another way it is the eyepiece focal length divided by the focal ratio the eyepiece actually sees, f_tel × B ⁄ D. The focal ratio reported is that of the telescope alone, f_tel ⁄ D. Magnification per inch of aperture is M × 25.4 ⁄ D, using the inch of exactly 25.4 mm.

The main relation comes straight from geometry. A ray from a star at angle θ off the axis crosses the objective's focal plane at a height of f_tel × tan θ. The eyepiece shares that focal plane and sends the ray out parallel at a new angle θ′, where the same height equals f_eye × tan θ′. Dividing one by the other, tan θ′ ⁄ tan θ = f_tel ⁄ f_eye. Within the thin-lens, paraxial model this is exact rather than a small-angle approximation.

The two bounds are of different kinds. The lower one, M_min = D ⁄ p with p your dark-adapted pupil, is physics: below that power the exit pupil is wider than your pupil and the iris blocks the outer part of the beam. The upper one, M_max = k × D, is a convention, and at the default k of 2 per millimetre it is simply another way of saying stop at an exit pupil of 0.5 mm. A rough justification exists. By the Rayleigh criterion an aperture of D millimetres resolves about 138 ⁄ D arcseconds in green light, and at 1× per millimetre that detail is already enlarged to about 2.3 arcminutes, above the roughly one arcminute a normal eye can separate; doubling the power again makes the image larger without revealing anything new.

Brightness follows the exit pupil. For an extended object such as a planet's disc or a nebula, the surface brightness you see scales with the square of the exit pupil, as long as the exit pupil is no wider than your own, so halving it leaves a quarter of the brightness. The model stops applying when the telescope is focused on something close, when a camera sits at prime focus with no eyepiece, or when you want the true field of view, which depends on the eyepiece's field stop and has its own calculator.

A worked example.

Example

Jupiter is high and you want 240× on the 200 mm f/6 reflector, which has a 1,200 mm focal length. You already own a 2× Barlow, so choose Eyepiece needed for a target power, enter 240 as the target and 2 as the Barlow factor. The Barlow doubles the effective focal length: 1,200 × 2 = 2,400 mm. The eyepiece that gives 240× behind it is 2,400 ÷ 240 = 10 mm, which turns out to be the 10 mm eyepiece already in the case, now used with the Barlow. The exit pupil is 200 ÷ 240 = 0.8333 mm, shown as 0.83 mm in the verdict. Per inch of aperture the power is 240 × 25.4 ÷ 200 = 30.48×. The bounds depend only on the aperture and your eye, so the Barlow leaves them alone: 200 ÷ 7 = 28.5714, shown as 28.6×, at the bottom and 2 × 200 = 400× at the top. At 240× the verdict reads Usable. Compared with the same 10 mm eyepiece without the Barlow, at 120× and a 1.6667 mm exit pupil, the planet now spans twice the angle but each part of its disc has about a quarter of the surface brightness. Whether that trade pays off on a given night depends on how steady the air is, not on the telescope.

dark Adapted Pupil Mm7
target Magnification240
eyepiece Focal Length Mm10
aperture Mm200
telescope Focal Length Mm1,200
max Magnification Per Mm2
barlow Factor2
solve ForeyepieceFocalLength

Frequently asked questions.

My small telescope's box promises 525×. Why does the calculator put the top at 140×?
Because the box quotes the highest power the supplied accessories can reach, not a power at which anything useful can be seen. A 70 mm refractor with a 700 mm focal length, a 4 mm eyepiece and a 3× Barlow does reach 700 × 3 ÷ 4 = 525×, but the exit pupil shrinks to 0.1333 mm, and the image is dim, blurred and hard to keep in view. At the default 2× per millimetre, 70 mm of aperture tops out at 140×. Aperture is the specification to compare.
Is 50× per inch of aperture a real optical limit?
No. It is a rule of thumb, equivalent to stopping when the exit pupil reaches about half a millimetre. Its two common forms do not quite agree: 50× per inch is 1.9685× per millimetre, while the metric version is 2× per millimetre, or 50.8× per inch. On many nights turbulence in the atmosphere limits a large telescope well below either figure, which is why the factor is an input you can lower rather than a fixed constant.
What exit pupil should I aim for on planets, nebulae and the Moon?
Large exit pupils of several millimetres give the brightest and widest views and suit sweeping star fields and big, faint nebulae. Planets, the Moon and close double stars are usually observed with exit pupils around 1 mm or a little less, where detail is spread out enough to see. Below about 0.5 mm the image dims and floaters drifting in your eye become distracting. Since exit pupil is aperture divided by magnification, choosing one fixes the other.
How does a Barlow lens change the numbers?
It multiplies the telescope's effective focal length, so a 10 mm eyepiece behind a 2× Barlow behaves like a 5 mm eyepiece on the bare telescope, and the exit pupil halves along with the doubling in power. The focal ratio shown stays that of the telescope itself, since the Barlow is an accessory. A Barlow's real factor varies a little with how far the eyepiece sits from it, so the stated value is nominal.
Why is there a lowest useful magnification at all?
Because your iris acts as a second aperture. When the beam leaving the eyepiece is wider than your pupil, its outer ring lands on the iris instead of entering the eye, and the light collected by the outer zone of the lens or mirror is wasted. In effect you are observing with a smaller telescope. The threshold is the power at which the exit pupil equals your pupil: 200 ÷ 7 = 28.6× on the default telescope.
What pupil size should I enter if I am over fifty?
Something smaller than 7 mm. The pupil's maximum opening shrinks with age; around 7 mm is typical in young adults, while many people in their sixties reach only about 5 mm, and individuals vary widely. On a 200 mm telescope that change moves the lower bound from 28.6× to 40×. If you are unsure, entering a slightly smaller pupil is the safer error, since it only raises the lowest power the calculator recommends.
What is the longest eyepiece worth buying for my telescope?
Multiply your pupil diameter by the telescope's focal ratio. On an f/6 telescope with a 7 mm pupil that gives 7 × 6 = 42 mm; with a 5 mm pupil it is 30 mm. Any eyepiece longer than that produces an exit pupil wider than your eye can use. The same logic at the other end, 0.5 mm × 6, puts the shortest eyepiece suggested by the default convention at 3 mm before any Barlow.
Does the type of telescope change the magnification formula?
No. Refractors, Newtonian reflectors, Schmidt-Cassegrains and Maksutovs are all afocal when used with an eyepiece, so in every case the power is focal length divided by eyepiece focal length. What differs is how much focal length each design packs into its tube. A 10 mm eyepiece gives 200× in a Schmidt-Cassegrain with a 2,000 mm focal length but only 60× in a 600 mm short refractor.
Why do faint stars get easier to see at higher power while nebulae get dimmer?
A star is a point, so its light stays concentrated whatever the magnification, while the sky background is extended and spreads out and darkens as the exit pupil shrinks. More contrast makes faint stars stand out. A nebula, a galaxy or a planet's disc is extended too, so it dims along with the background. That is why deep-sky observers use low powers for large faint objects and higher ones for star clusters.
Can I work out the same numbers for binoculars?
Partly. Binocular magnification is fixed inside the instrument, so you cannot divide focal lengths from the outside, but the exit pupil relation works directly from the name. A 10×50 binocular has 50 mm objectives at 10×, so its exit pupil is 50 ÷ 10 = 5 mm, a good match for an older observer, while a 7×42 gives 6 mm. The reasoning about whether that suits your eye is exactly the same.

References& sources.

  1. [1]Tele Vue Optics, Inc., 'Telescope Formulas / Common Telescope Myths'. Manufacturer engineering note. Verified by retrieval to state: Magnification = 'Objective focal length / Eyepiece focal length' and 'Objective diameter / Exit pupil'; Exit Pupil = 'Objective diameter / Magnification' and 'Eyepiece focal length / (Objective f/#)'; Focal Ratio = 'Objective focal length / objective diameter'. Independent of the optics textbooks below, open access. Retrieved 2026-07-29.
  2. [2]Hecht, E. (2017). Optics, 5th edition, §5.7.3 'Telescopes', Pearson Education. Derivation of the angular magnification MP = f_objective / f_eyepiece for the afocal refracting telescope, and of the exit pupil as the image of the aperture stop. Print / bibliographic reference — no authoritative free full text exists, so no URL is offered rather than linking a scan of uncertain provenance.
  3. [3]Winn, B., Whitaker, D., Elliott, D.B. & Phillips, N.J. (1994). 'Factors affecting light-adapted pupil size in normal human subjects.' Investigative Ophthalmology & Visual Science 35(3):1132–1137. Shows that pupil diameter falls with age, which is why the dark-adapted pupil is an editable input rather than a fixed 7 mm. It measured light-adapted pupils, so it does not give a dark-adapted decline rate. Abstract open access; full text paywalled. Retrieved 2026-07-29.
  4. [4]National Institute of Standards and Technology, Special Publication 811 (2008 edition), Appendix B.8 'Factors for Units Listed Alphabetically': inch (in) → metre (m), factor 2.54 E-02, printed in boldface, which the table's own legend defines as exact. That is 25.4 mm exactly, following the 1959 international yard and pound agreement. Used for the magnification-per-inch output. Open access. Retrieved 2026-07-29.
  5. [5]ISO 14132-1:2015, 'Optics and photonics — Vocabulary for telescopic systems — Part 1: General terms and alphabetical indexes of terms'. Standardises the definitions of magnification and exit pupil for telescopic systems used here. Paywalled standard; listed as a bibliographic reference for the terminology, not as free full text.
  6. [6]Born, M. & Wolf, E. (1999). Principles of Optics, 7th (expanded) edition, §4.8 and §8.6, Cambridge University Press. Paraxial treatment of afocal systems and of the pupils of an optical instrument. Print / bibliographic reference.

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M = (f_tel × B) ⁄ f_eye d_exit = D ⁄ M = f_eye ⁄ (f_tel·B⁄D) f/# = f_tel ⁄ D
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