Audited 29 Jul 2026·Last updated 28 Oct 2026·4 citations·Tier 2·0 uses

Telescope Focal Ratio Calculator

Telescope focal ratio from focal length and aperture, with reducer or Barlow: arcsec per pixel, Airy disc size, sampling verdict and stops gained.

Telescope Focal Ratio Calculator

Solve for
Native focal length of the telescope, before any reducer or Barlow. Default is a 200 mm f/6 Newtonian.
mm
Clear diameter of the objective or primary mirror. This — not the focal ratio — is what decides how much light a star delivers.
mm
The focal ratio you want, used when solving for focal length or aperture.
f/
1 = none. A focal reducer is less than 1 (0.63 and 0.8 are common); a Barlow or extender is greater than 1. It multiplies the effective focal length.
×
Pixel pitch of the sensor. 3.76 µm is the IMX571/IMX533 family; DSLRs are typically 3.7–6 µm; older CCDs 6–9 µm.
µm
Used only for the Airy disc, which scales linearly with wavelength. 550 nm is the conventional visual green.
nm
The width of a star image the atmosphere actually delivers. This, not the Airy disc, is what your pixels have to sample from the ground.
″
Focal ratio (f/#)
f/6
The telescope's native focal ratio, focal length divided by aperture, before any reducer or Barlow.
Effective focal ratio
f/6
Image scale
0.6463 ″/px
Plate scale
171.8873 ″/mm
Focal length
1,200 mm
Aperture
200 mm
Effective focal length
1,200 mm
Airy disc in the focal plane
8.052 µm
Pixels across the Airy disc
2.1415 px
Pixels across the seeing disc
3.0946 px
Stops gained on extended objects
0 stops
Verdict
Oversampled: 0.646″ per pixel spreads the 2″ seeing disc over 3.09 pixels. Nothing is lost, but the same photons are split between more pixels, so each one is noisier for a given exposure. The Airy disc at f/6 spans 2.14 pixels, which is the limit only if the seeing is better than the optics. Remember that focal ratio sets exposure for nebulosity, not for stars: a point source's total flux depends on the 200 mm aperture alone, and a reducer only repacks it into fewer pixels.

Background.

A 200 mm mirror with a focal length of 1,200 mm is an f/6 telescope: the focal ratio is focal length divided by aperture. Astrophotographers call a low focal ratio fast, and for nebulae, galaxies and the sky background that holds, because the same light is spread over a smaller image and each square millimetre of sensor fills up sooner. Halve the focal ratio and an extended target needs a quarter of the exposure.

Stars do not follow that rule. A star is a point, and the light it delivers depends on the area of the aperture alone; a lower focal ratio only squeezes the same photons onto fewer pixels. So a focal reducer that speeds up a nebula does nothing for the faintest star you can record, and the aperture is reported beside every result to keep that in view.

What a reducer or Barlow does change is the image scale, the number of arcseconds of sky that land on each camera pixel, and that decides whether stars are sampled finely enough to stay round and sharp. Enter the telescope, any reducer or Barlow, your camera's pixel size and your usual seeing, and you get the scale, the size of the diffraction disc, how many pixels span the star image the atmosphere actually delivers, and whether the camera is undersampled, well matched or oversampled. You can also work backwards to the focal length or aperture that gives a target focal ratio.

What is telescope focal ratio calculator?

Focal ratio, or f-number, is the focal length of a telescope's objective lens or primary mirror divided by its clear aperture, written f/6 for a ratio of 6. It is dimensionless, so a 1,200 mm focal length on a 200 mm aperture is f/6 in any unit. The effective focal ratio is the same quantity after a focal reducer (a factor below 1, commonly 0.63 or 0.8) or a Barlow lens or extender (a factor above 1) has changed the effective focal length; the aperture is untouched by either. Image scale turns the effective focal length into arcseconds of sky per millimetre of focal plane, and into arcseconds per pixel once the camera's pixel pitch is known.

How to use this calculator.

  1. Under "Solve for", choose focal ratio to analyse a telescope you have, or focal length or aperture to find the size that reaches a target ratio, such as the focal length a 150 mm mirror needs to be f/8.
  2. Enter the native focal length and clear aperture in millimetres as the maker lists them, before any accessory is added.
  3. Set the reducer or Barlow factor: 1 for none, 0.63 or 0.8 for common reducers, 2 for a 2× Barlow. The real factor shifts with the spacing behind a reducer, so a measured value beats the nominal one.
  4. Enter the camera's pixel size from its specification sheet (3.76 µm for the IMX571 and IMX533 sensors, roughly 3.7–6 µm for DSLRs, 6–9 µm for older CCDs) and your typical seeing as a star's full width at half maximum in arcseconds; 2″ is an ordinary night.
  5. Leave the wavelength at 550 nm for broadband imaging or set your filter's wavelength for narrowband; it affects only the Airy disc. Then read the image scale and the sampling verdict together.

The formula.

f/# = f ⁄ D f/#_eff = f/# × k scale = 206264.806 ⁄ f_eff d_Airy = 2.44 λ · f/#_eff Δstops = 2 log₂(f/# ⁄ f/#_eff)

The focal ratio is N = f ÷ D, focal length over aperture. A reducer or Barlow factor k makes the effective focal length f × k and the effective focal ratio N × k. Solving backwards, f = D × N for a target ratio, or D = f ÷ N.

Image scale comes from small-angle geometry: an object θ radians across forms an image f·θ long, so one millimetre of focal plane covers 1/f radians, which is 206,264.806 ÷ f arcseconds, the constant being 648,000/π, the number of arcseconds in a radian. Multiply by the pixel pitch in millimetres for arcseconds per pixel; with pitch in micrometres this reduces to the familiar shortcut 206.265 × pixel ÷ focal length.

The Airy disc, the diffraction image of a star measured to its first dark ring, is 2.44 × λ × N_eff across, twice Rayleigh's 1.22 coefficient. It assumes perfect optics and an unobstructed circular aperture; the secondary mirror of a reflector moves some light from the core into the rings. Pixels across the seeing disc are the seeing divided by the image scale, and the verdict calls fewer than 2 undersampled, following Shannon's sampling theorem, and more than 3 oversampled, a working convention rather than a theorem.

For extended objects the brightness of the image falls as 1 ÷ N², so the change in photographic stops is 2 log₂(N_native ÷ N_eff): positive with a reducer, negative with a Barlow, and exactly −2 with a 2× Barlow.

A worked example.

Example

A 200 mm Newtonian with a 1,200 mm focal length is 1,200 ÷ 200 = f/6. Adding a 0.63× reducer makes the effective focal length 1,200 × 0.63 = 756 mm and the effective ratio f/3.78. The plate scale becomes 206,264.806 ÷ 756 = 272.837″ per millimetre, and a 3.76 µm pixel, 0.00376 mm, covers 272.837 × 0.00376 = 1.0259″. A 2″ seeing disc then spans 2 ÷ 1.0259 = 1.95 pixels, just under the floor of two, so the verdict is undersampled. The Airy disc at 550 nm is 2.44 × 0.55 × 3.78 = 5.0728 µm, about 1.35 pixels, smaller than the seeing disc as usual from the ground. On nebulosity the reducer gains 2 log₂(6 ÷ 3.78) = 1.3332 stops, so a target that needed four hours at f/6 needs about 95 minutes. Without the reducer the same camera samples at 0.6463″ per pixel, 3.09 pixels across the seeing disc and slightly oversampled. The reducer carries this rig from one edge of the two-to-three window to the other, trading crisp stars for speed on faint, extended targets.

reducer Barlow Factor0.63
pixel Size Um3.76
seeing Arcsec2
aperture Mm200
target Focal Ratio6
solve ForfocalRatio
wavelength Nm550
focal Length Mm1,200

Frequently asked questions.

Will a lower focal ratio let me record fainter stars?
No. The total light a star delivers is set by the collecting area of the aperture, and a reducer leaves the aperture unchanged. It concentrates each star onto fewer pixels, which raises the signal per pixel without adding a single photon. To reach fainter stars you need more aperture or more exposure; the focal ratio governs how quickly extended objects build up.
What image scale should I aim for?
Two to three pixels across the star image your sky delivers. With 2″ seeing that means about 0.67 to 1.0″ per pixel; with 3″ seeing, 1.0 to 1.5″ per pixel. Below two pixels per seeing disc, detail is lost for good; above three, the same light is split among more pixels, each noisier for a given exposure, with nothing gained in sharpness.
Would a 0.8× reducer suit this telescope better than a 0.63×?
On a 2″ night, yes. A 0.8× reducer on the 1,200 mm f/6 telescope gives 960 mm at f/4.8 and 0.8079″ per pixel with 3.76 µm pixels, putting 2.48 pixels across the seeing disc, inside the window. It gains 0.6439 stops, cutting nebula exposures to 64% of the native time, against 1.3332 stops for the 0.63× unit.
Why does the verdict depend on seeing rather than the Airy disc?
Because from the ground the atmosphere usually blurs stars more than diffraction does. On the native f/6 telescope the Airy disc spans 2.14 pixels while a 2″ seeing disc spans 3.09, so the seeing sets the star size. The verdict also changes with the night: with 3″ seeing, the 0.63× reducer setup puts 2.92 pixels across each star and counts as well matched.
How much does a 2× Barlow slow the telescope down?
Two full stops on extended objects. Doubling the effective focal ratio from f/6 to f/12 cuts the image brightness to a quarter, so a nebula needs four times the exposure. The image scale drops to 0.3231″ per pixel with 3.76 µm pixels, 6.19 pixels across a 2″ star, which is heavily oversampled for deep-sky work but suits planets, where very short exposures can freeze moments of steady air.
Does a reducer widen the field of view?
Yes. The field covered by a given sensor scales inversely with the effective focal length, so a 0.63× reducer widens it by a factor of about 1.59 in each direction and 2.52 in area. That is often the real reason to fit one: large nebulae that overflow the frame at native focal length fit with room to spare.

References& sources.

  1. [1]Tele Vue Optics, Inc., 'Telescope Formulas'. Manufacturer engineering note, verified by retrieval to state verbatim: Focal Ratio (f/#) = 'Objective focal length / objective diameter'. Open access. Retrieved 2026-07-29.
  2. [2]Shannon, C.E. (1949). 'Communication in the presence of noise.' Proceedings of the IRE 37(1):10–21 (reprinted in Proceedings of the IEEE 86(2):447–457, 1998). Source of the two-samples-per-resolution-element floor used as the undersampling threshold. The three-sample upper bound used on this page is a practical convention and is labelled as such, not attributed to Shannon. Peer-reviewed; the IEEE reprint is paywalled and its landing page returns no content to automated retrieval, so this is shipped as a bibliographic reference rather than a link that reads as dead.
  3. [3]Born, M. & Wolf, E. (1999). Principles of Optics, 7th (expanded) edition, §8.5.2, Cambridge University Press. The Airy pattern and the 1.22 coefficient that doubles to the 2.44 used for the disc diameter. Print / bibliographic reference; the publisher's page refuses automated retrieval, so no URL is shipped.
  4. [4]Rayleigh, Lord (J. W. Strutt) (1879). 'Investigations in optics, with special reference to the spectroscope.' Philosophical Magazine, Series 5, 8(49), 261–274. Origin of the 1.22 coefficient. Print / bibliographic reference.

How this page was produced

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Quanta Calculator
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Method
f/# = f ⁄ D f/#_eff = f/# × k scale = 206264.806 ⁄ f_eff d_Airy = 2.44 λ · f/#_eff Δstops = 2 log₂(f/# ⁄ f/#_eff)
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