Audited 31 Jul 2026·Last updated 28 Oct 2026·3 citations·Tier 3·0 uses

Compton Wavelength Calculator

Find a particle's Compton wavelength h/(mc) from its rest mass in kilograms, using the exact SI values of Planck's constant and light speed.

Compton Wavelength Calculator

kg
Compton wavelength
2.426 × 10⁻¹²
The unreduced Compton wavelength h/(mc) for the mass you entered, in metres; very small values are shown in the form 2.426 × 10⁻¹².
Model scope
Unreduced wavelength h/(mc), not reduced ħ/(mc); the entered mass is rest mass and relativistic scattering kinematics are not calculated.

Background.

Every particle with mass carries a built-in length fixed by nothing but its mass and two constants of nature: λ_C = h/(mc). For the electron it is 2.426 × 10⁻¹² m, about 2.43 picometres, some 22 times smaller than the Bohr radius of a hydrogen atom.

The name comes from Arthur Compton's X-ray experiments of the early 1920s. When X-rays scatter off electrons, the scattered rays emerge with a longer wavelength, and the stretch depends only on the scattering angle: Δλ = λ_C(1 − cos θ). At 90° the shift is exactly one Compton wavelength; straight back, at 180°, it is two. That angle-only dependence was strong evidence that light arrives in quanta carrying momentum, colliding with electrons like billiard balls.

The length has a meaning of its own, too. A photon whose wavelength equals a particle's Compton wavelength carries an energy equal to that particle's rest energy mc², which is 511 keV for the electron. Squeeze a particle into a region much smaller than its Compton wavelength and the energies involved are enough to create particle–antiparticle pairs, so the picture of one well-defined particle breaks down. Roughly, it marks where quantum field theory has to take over from ordinary quantum mechanics.

Because mass sits in the denominator, heavier particles have shorter Compton wavelengths in exact proportion. A proton, about 1,836 times as massive as the electron, comes out at about 1.321 × 10⁻¹⁵ m, comparable to the proton's own size.

The page returns the unreduced form, h/(mc). Many theory texts use the reduced version, ħ/(mc), which is smaller by a factor of 2π. Planck's constant and the speed of light are both exact by definition in the SI, so the result is as precise as the mass you enter.

What is compton wavelength calculator?

The Compton wavelength of a particle is Planck's constant divided by the product of the particle's rest mass and the speed of light, λ_C = h/(mc). It is a length in metres that depends on nothing but the mass. It sets the size of the wavelength shift when a photon scatters off that particle, it equals the wavelength of a photon whose energy matches the particle's rest energy, and it marks roughly the scale below which the particle cannot be confined without creating new particles.

How to use this calculator.

  1. Enter the particle's rest mass in kilograms. The default is the electron, 9.1093837139 × 10⁻³¹ kg, the CODATA 2022 recommended value.
  2. If your mass is listed in MeV/c², multiply by 1.78266 × 10⁻³⁰ to get kilograms; if it is in unified atomic mass units, multiply by 1.66054 × 10⁻²⁷.
  3. Read the result in metres. Divide by 10⁻¹² for picometres or by 10⁻¹⁵ for femtometres.
  4. If your textbook or formula uses the reduced Compton wavelength ħ/(mc), divide the result by 2π.

The formula.

λ_C = h / (mc)

λ_C = h / (m c), where h = 6.62607015 × 10⁻³⁴ J s is the Planck constant, c = 299,792,458 m/s is the speed of light and m is the rest mass in kilograms. Both constants are exact by definition in the SI, so the only uncertainty in the answer comes from the mass. The product mc has the units of momentum, kg m/s, and h divided by a momentum is a length, the same structure as the de Broglie wavelength h/p. The result is inversely proportional to the mass: double the mass and the wavelength halves. It is the rest mass that goes in; the page does not use a speed-dependent mass, and it does not compute scattering angles or energies. The Compton shift at any angle θ follows directly from the result as λ_C(1 − cos θ).

A worked example.

Example

For the electron, m = 9.1093837139 × 10⁻³¹ kg. Multiplying by the speed of light gives mc = 9.1093837139 × 10⁻³¹ × 299,792,458 = 2.7309 × 10⁻²² kg m/s. Dividing Planck's constant by that, 6.62607015 × 10⁻³⁴ ÷ 2.7309 × 10⁻²², gives λ_C = 2.426 × 10⁻¹² m, about 2.426 picometres (2.42631023538 × 10⁻¹² m to twelve significant figures). An X-ray photon scattered through 90° by a free electron is lengthened by exactly that amount, and one scattered straight back by twice it, 4.853 × 10⁻¹² m. Enter a proton's mass, 1.6726 × 10⁻²⁷ kg, and the wavelength drops to about 1.321 × 10⁻¹⁵ m, roughly 1,836 times shorter.

particle Rest Mass Kg0

Frequently asked questions.

Should I use the Compton wavelength or the reduced Compton wavelength?
It depends on the formula in front of you. The scattering shift Δλ = λ_C(1 − cos θ) uses the unreduced h/(mc) returned here. Quantum field theory and work in natural units usually use ħ/(mc), which is 2π times smaller: 3.862 × 10⁻¹³ m for the electron.
Why is the Compton shift easy to see with X-rays but not with visible light?
The shift is the same absolute length whatever the incoming wavelength, at most 4.853 × 10⁻¹² m off an electron. Against a 0.1 nm X-ray that is a change of about 4.85%, easily measured. Against visible light of around 500 nm it is about a thousandth of a percent.
What does the Compton wavelength have to do with a particle's rest energy?
A photon's energy is hc/λ, so a photon with wavelength λ_C = h/(mc) has energy exactly mc², the particle's rest energy. For the electron that is about 511 keV, the energy of each gamma ray produced when an electron and a positron annihilate at rest.
How is this different from the de Broglie wavelength?
The de Broglie wavelength h/p depends on how fast the particle moves, while the Compton wavelength uses mc and depends on mass alone. The two coincide when the particle's momentum equals mc, which happens at 1/√2 of the speed of light, about 0.707c, once relativity is taken into account.
Does the result mean anything for an atom or an everyday object?
The arithmetic works for any mass, but the meaning fades. A 1 kg mass gives about 2.21 × 10⁻⁴² m, far below anything measurable. For whole atoms the Compton wavelength is much smaller than the atom itself, and X-ray Compton scattering is governed by the electrons, so use the electron's mass.

How this page was produced

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Method
λ_C = h / (mc)
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