Audited 31 Jul 2026·Last updated 28 Oct 2026·3 citations·Tier 2·0 uses

Heat of Combustion Calculator

Find the heat released by burning a fuel: mass in kg times its heat of combustion (gross or net) in J/kg, with the result in joules. No fuel table built in.

Heat of Combustion Calculator

kg
J/kg
Released heat magnitude
1
The magnitude of the heat released by completely burning the entered mass of fuel, in joules.
Model scope
Multiplication of entered mass by an entered HHV or LHV; it does not choose a fuel value, reconcile HHV versus LHV, predict completeness, or size combustion equipment.

Background.

Burning a fuel rearranges its atoms into lower-energy products — carbon dioxide and water for anything built from carbon and hydrogen — and the energy difference comes out as heat. How much heat each kilogram gives up is a property of the fuel called its heat of combustion, or calorific value. Methane, the main component of natural gas, releases about 55.5 MJ per kilogram on the gross basis; hydrogen releases about 142. Multiply the per-kilogram value by the mass burned and you have the total: Q = m × H_c. The multiplication is trivial. Choosing the right H_c is not.

The first trap is that every fuel has two heating values. Hydrogen in a fuel burns to water, and whether that water ends up as liquid or vapour changes the answer. The higher heating value (HHV, or gross calorific value) counts the latent heat released when the vapour condenses; the lower heating value (LHV, or net) assumes it leaves as steam. For methane the gap is about 10%, 55.5 against 50.0 MJ/kg, and efficiency figures are quoted on either basis, so mixing them quietly skews any comparison.

The second is units. Tables list heats of combustion in MJ/kg, kJ/g (numerically the same), kJ/mol, BTU/lb and kcal/g, while the field here expects joules per kilogram, so 55.5 MJ/kg goes in as 55,500,000.

The third is sign. Thermochemistry writes an enthalpy of combustion as negative, because the burning system loses energy; methane's is about −890 kJ/mol. Here both inputs are positive magnitudes and the answer is the size of the heat released.

That answer assumes complete combustion. How much of it actually reaches the water in a boiler or the pistons of an engine is a separate question of efficiency.

What is heat of combustion calculator?

The heat of combustion of a substance is the heat released when a unit amount of it burns completely in oxygen, with the products returned to a reference temperature, usually 25 °C. Per kilogram, it is the fuel's specific energy or calorific value. It comes in two versions: gross, or higher heating value, with the water formed condensed to liquid, and net, or lower heating value, with that water left as vapour. The heat released by a given mass is the per-kilogram value times the mass, in joules.

How to use this calculator.

  1. Enter the Fuel mass in kilograms. A litre of liquid fuel is not a kilogram, so convert volumes with the fuel's density first.
  2. Enter the Heat of combustion magnitude in joules per kilogram, as a positive number. Multiply MJ/kg or kJ/g by 1,000,000, so methane's 55.5 MJ/kg becomes 55,500,000 J/kg.
  3. Pick the basis before you pick the number: the gross value if flue gases are cooled enough to condense their water, as in a condensing boiler; the net value if the water leaves as vapour.
  4. Read the released heat in joules. Divide by 1,000,000 for megajoules or by 3,600,000 for kilowatt-hours.

The formula.

|Q| = mH_c

|Q| = m × H_c. Here m is the mass of fuel burned in kilograms, H_c is the magnitude of the heat of combustion per kilogram in joules per kilogram, and |Q| is the magnitude of the heat released in joules; the kilograms cancel, leaving joules. The relationship is strictly proportional: twice the fuel gives twice the heat, and a fuel with twice the heating value gives twice the heat. There is no fuel library and no built-in constant, so the value you enter for H_c carries all of the chemistry. The absolute-value bars appear because thermodynamics gives combustion a negative enthalpy change; the result reports how much heat leaves the fuel, not its sign. Completeness of burning, the gross-or-net choice and equipment efficiency all sit outside the equation and must be built into H_c or applied afterward. The result is given to twelve significant figures.

A worked example.

Example

The page opens with deliberately bare defaults: 1 kg of fuel and a heat of combustion of 1 J/kg. Multiplying gives |Q| = 1 × 1 = 1 J. That shows the unit bookkeeping — kilograms times joules per kilogram leaves joules — but describes no real fuel. Put in methane's gross heating value instead, 55.5 MJ/kg or 55,500,000 J/kg, and the same kilogram releases 1 × 55,500,000 = 55,500,000 J, which is 55.5 MJ or 55.5 ÷ 3.6 = 15.42 kWh. On the net basis, 50,000,000 J/kg, the answer drops to 50,000,000 J; the missing 5,500,000 J is the latent heat that leaves with the water vapour when it is not condensed.

fuel Mass Kg1
heat Of Combustion J Per Kg1

Frequently asked questions.

Should I use the higher or the lower heating value?
Use the one that matches what happens to the water vapour. A condensing boiler recovers latent heat, so the gross value describes it; an engine or ordinary furnace exhausts the vapour, so the net value is closer. When comparing appliances, put both on the same basis, since for methane the two differ by about 10%.
How do I convert a heat of combustion in kJ/mol to J/kg?
Multiply by 1,000 to get joules per mole, then divide by the molar mass in kilograms per mole. For methane, about 890 kJ/mol divided by 0.01604 kg/mol gives roughly 55,490,000 J/kg, the familiar 55.5 MJ/kg. Drop the minus sign that thermochemical tables carry before entering it.
Why do chemistry tables show heats of combustion as negative numbers?
By convention an enthalpy change is negative when a system gives out heat, and combustion always does, so methane is listed at about −890 kJ/mol. The negative sign records direction, not size. This page asks for the magnitude and returns the magnitude, which is why both fields must be positive.
Is this the heat my boiler or stove actually delivers?
No. It is the heat the chemistry gives up when the fuel burns completely. Appliances lose some through the flue and casing, and incomplete burning releases less to begin with. Multiply by the appliance's efficiency for delivered heat: at 80%, a kilogram of methane would deliver about 44.4 MJ of its 55.5 MJ.
How do I get the fuel mass if I only know the volume?
Multiply the volume by the fuel's density at the temperature you measured it, keeping units consistent, for example litres times kilograms per litre. For gases, density depends strongly on pressure and temperature, so either use a density for those exact conditions or work from a volumetric heating value instead of this mass-based one.
How is a heat of combustion actually measured?
Usually in a bomb calorimeter: a weighed sample burns in pressurised oxygen inside a sealed steel vessel sitting in water, and the temperature rise, times the calorimeter's calibrated heat capacity, gives the heat. Standards such as ASTM D240 for liquid hydrocarbon fuels and ISO 1928 for coal define the procedure. The measurement gives the gross value; the net value is then calculated from the fuel's hydrogen and moisture content.

How this page was produced

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Quanta Calculator
Primary sources
3 cited below
Method
|Q| = mH_c
Published
Last verified

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