Audited 29 Jul 2026·Last updated 28 Oct 2026·6 citations·Tier 2·0 uses

Roche Limit Calculator

Find the Roche limit for fluid, rubble-pile or rigid satellites from the planet's radius and both densities, plus the density needed to survive at any orbit.

Roche Limit Calculator

Satellite model
Radius of the body being orbited. Default is Earth's volumetric mean radius, 6371.0084 km (JPL) — use a mean radius so it is consistent with the bulk density.
km
Default is Earth, 5.5134 g/cm³ (JPL). Only the ratio of the two densities matters, so any consistent unit works.
g/cm³
Default is the Moon, 3.344 g/cm³ (JPL DE440). Water ice is about 0.9; a porous comet nucleus can be 0.3–0.6; solid iron is 7.9.
g/cm³
Distance from the CENTRE of the primary. Default is the Moon's mean distance, 384 400 km (NASA). Used for the inside-or-outside verdict and the critical density.
km
Roche limit (selected model)
18,472.382
The distance from the primary's centre, in kilometres, inside which a satellite of the chosen kind and density would be pulled apart by tides.
Roche limit in primary radii
2.8994
Verdict, regime and limits
OUTSIDE the Roche limit: at 384400 km this satellite is farther out than the 18472.382 km limit for the selected model, so self-gravity alone is enough to hold it together. Only a body less dense than 0.000371095 g/cm³ would be disrupted at this distance. The Roche limit assumes the satellite is held together by SELF-GRAVITY ALONE — material strength is ignored, which is why small solid bodies routinely survive far inside it. The primary is treated as a point mass, the satellite as uniform, and the orbit as circular. A differentiated satellite with a dense core disrupts closer in than a homogeneous one of the same mean density. Coefficient note: this page uses C = 2.454315, from γ ≈ 0.85 as given by Tiscareno et al. (2013) after Chandrasekhar (1969). Much of the literature quotes 2.456 instead, from γ = 0.848252 — a 0.069 % difference, about 13 km on the Earth–Moon figure.
Roche critical density at that orbit
3.711 × 10⁻⁴ g/cm³
Coefficient C used
2.4543
Fluid-body limit
18,472.382 km
Rubble-pile limit
14,960.8367 km
Rigid sphere, synchronous
10,855.0795 km
Rigid sphere, tidal term only
9,482.7854 km
Satellite distance in primary radii
60.3358

Background.

Bring the Moon in towards Earth and, somewhere around 18,000 km from Earth's centre, it stops being a moon. The pull on its near side is now so much stronger than the pull on its far side that its own gravity can no longer hold it together, and the pieces spread into a ring. That distance is the Roche limit, named after Édouard Roche, who worked it out for a fluid satellite in 1848.

Only three numbers decide it: the radius of the planet and the bulk densities of planet and satellite. A dense satellite can come closer; a dense planet pushes the limit outward. The satellite's size drops out altogether, so a 10 km moonlet and a 1,000 km moon of the same density break up at the same distance.

What changes the answer most is the kind of body you assume. A satellite that can flow into a stretched, egg-like shape hands the tide a longer lever and fails far out; a perfectly rigid sphere holds on much closer in. For Earth and a Moon-density satellite the four models offered here span 18,472 km down to 9,483 km, nearly a factor of two, so a Roche limit quoted without its model is half an answer. All four are shown together, with the one you selected as the headline.

The second result turns the question round: given an orbit, how dense must a body be to survive there? Ring scientists use this critical density because a ring's radius can be measured directly while its particles' density cannot.

Behind every figure sits one assumption: the satellite is held together by gravity alone. Rock strength is ignored, which is why spacecraft, boulders and small solid moons can sit well inside the limit without coming apart.

What is roche limit calculator?

The Roche limit is the orbital distance, measured from the primary's centre, inside which a satellite bound only by its own gravity is pulled apart by tides. Gravity weakens with distance, so across an extended satellite the near side is pulled harder than the centre and the centre harder than the far side. That difference stretches the satellite along the line to the planet. At the Roche limit the stretching just equals the self-gravity holding a surface particle down. Inside it, a loose body breaks up and loose material cannot gather into a moon, which is why planetary rings are found close to their planets.

How to use this calculator.

  1. Choose the satellite model: fluid for a molten, icy or very weak body; rubble pile for an aggregate of loose fragments, as many small moons and asteroids are; rigid synchronous for a solid sphere that keeps one face to its planet; rigid tidal-term-only to match the 1.26 figure in most textbooks.
  2. Enter the primary's mean radius in kilometres. Use the volumetric mean radius rather than the equatorial one, because that is the radius consistent with a published bulk density; JPL's planetary physical parameters list both.
  3. Enter the two bulk densities. Only their ratio enters, so any unit works as long as both match; g/cm³ is what agencies tabulate. Water ice is about 0.9, porous comet nuclei 0.3 to 0.6, solid iron 7.9.
  4. Enter the satellite's orbital distance from the centre of the primary, not its height above the surface, to get the inside-or-outside verdict and the critical density.
  5. Compare the four limits. If your orbit falls between them, the verdict depends on what the body is made of, and the range is the result worth quoting.

The formula.

d = R_p · (4π ρ_p ⁄ (γ ρ_s))^(1⁄3) = C · R_p · (ρ_p ⁄ ρ_s)^(1⁄3), C = (4π ⁄ γ)^(1⁄3), ρ_Roche = ρ_p (C·R_p ⁄ d)³

Consider a small particle on the surface of a satellite of radius r, a distance d from a planet of mass M_p. The tide trying to lift it off is about 2GM_p r / d³; the satellite's gravity holding it down is GM_s / r². Write each mass as density times (4/3)πR³ and set the two equal: the radius r cancels and d³ = 2R_p³ ρ_p / ρ_s, so d = 1.260 R_p (ρ_p / ρ_s)^(1/3). That is the textbook rigid-sphere result.

A satellite this close is tidally locked, and in its rotating frame a centrifugal term of GM_p r / d³ joins the tide, raising the 2 to a 3 and the coefficient to 3^(1/3) = 1.442. Tiscareno, Hedman, Burns and Castillo-Rogez (2013) write every case as d = R_p (4π ρ_p / (γ ρ_s))^(1/3), so C = (4π/γ)^(1/3). Their shape factors are γ = 4π/3 for a rigid sphere (C = 1.442), γ ≈ 1.6 for an elongated rubble pile after Porco and colleagues (C = 1.988), and γ ≈ 0.85 for an incompressible fluid after Chandrasekhar's work on equilibrium ellipsoids (C = 2.454). The tidal-term-only case corresponds to γ = 2π.

Rearranged for density, ρ_Roche = ρ_p (C R_p / d)³: the density a body must exceed to hold together at distance d. Because of the cube, halving the distance multiplies the required density by eight.

The primary is treated as a point mass, the satellite as uniform throughout and the orbit as circular. All four inputs must be greater than zero.

A worked example.

Example

How close could the Moon come before tides tore it apart? JPL gives Earth a mean radius of 6,371.0084 km and a bulk density of 5.5134 g/cm³, and the Moon a bulk density of 3.344 g/cm³. The density ratio is 5.5134 ÷ 3.344 = 1.6487, and its cube root is 1.1814. For a fluid body the coefficient is (4π ÷ 0.85)^(1/3) = 2.4543. Their product, 2.4543 × 1.1814 = 2.8994, is the limit in Earth radii, and 2.89944 × 6,371.0084 km puts the Roche limit at 18,472.382 km from Earth's centre, about 12,100 km above the surface. The rubble-pile model gives 14,960.837 km, the rigid synchronous sphere 10,855.079 km and the tidal-term-only sphere 9,482.785 km. The real Moon orbits at 384,400 km, 60.3358 Earth radii and about 20.8 times the fluid limit. At that distance the critical density is 5.5134 × (2.4543 × 6,371.0084 ÷ 384,400)³ = 3.711 × 10⁻⁴ g/cm³, so a satellite there would need to be roughly 9,000 times less dense than the Moon before tides could pull it apart. The Moon is in no danger, and it is in fact slowly receding.

primary Radius Km6,371.008
satellite Density Gcm33.344
body Modelfluid
primary Density Gcm35.513
satellite Distance Km384,400

Frequently asked questions.

Why is the satellite's own size not one of the inputs?
Because it cancels. The tidal pull on a surface particle grows in proportion to the satellite's radius, and so does the satellite's surface gravity when its density is fixed, since its mass grows as the radius cubed while gravity falls as the radius squared. Both sides of the balance carry the same factor of r, which is why only the planet's radius and the two densities remain.
Which satellite model should I choose?
Match it to the body. Phobos shows why it matters: it orbits Mars at about 9,376 km, and with Mars at 3.93 g/cm³ and Phobos near 1.9 g/cm³ the fluid limit is roughly 10,600 km while the rubble-pile limit is roughly 8,600 km. Phobos sits inside one and outside the other, so its fate depends on how strong and how coherent it is, not on the arithmetic.
Why do some books give 2.456 for the fluid coefficient instead of 2.454?
The two come from slightly different values of the fluid shape factor. 2.456 corresponds to γ = 0.848252; the 2.454315 used here follows from the γ ≈ 0.85 printed by Tiscareno and colleagues. The gap is 0.069 percent, about 13 km on the Earth–Moon fluid limit, far smaller than the uncertainty in most measured bulk densities.
How do astronauts, spacecraft and small rocks survive inside the Roche limit?
They are held together by chemical bonds, not gravity. For anything smaller than tens of kilometres, material strength is enormously larger than self-gravity, so the Roche limit says nothing about it. A boulder on Mars sits inside Mars's Roche limit by definition and stays whole. The limit is a good guide for large moons, loose aggregates, comets and fluid bodies.
What happens to a comet that passes inside a planet's Roche limit?
A weak, low-density nucleus can be pulled into a string of fragments. Comet Shoemaker–Levy 9 broke up this way during a close pass by Jupiter in 1992, and its fragments struck the planet two years later. With a porous nucleus of 0.3 to 0.6 g/cm³, the critical density is easy to fall short of close to a giant planet.
Does a satellite with a dense core break up at the same distance?
No. N-body simulations by Leinhardt, Ogilvie, Latter and Kokubo (2012) found that a differentiated satellite disrupts closer to the planet than a uniform body of the same mean density, and that a rubble pile disrupts closer in than a fluid body. For a satellite with a core, the limits here, which assume uniform density, will run somewhat too far out.

References& sources.

  1. [1]Tiscareno, M.S., Hedman, M.M., Burns, J.A. and Castillo-Rogez, J. (2013). 'Compositions and origins of outer planet systems: insights from the Roche critical density'. The Astrophysical Journal Letters 765, L28. Equation 1, a_Roche = R_p(4πρ_p/γρ)^(1/3); Equation 3, ρ_Roche = 3M_p/γa³; γ = 4π/3 ≈ 4.2 for a sphere, γ ≈ 1.6 for an elongated body after Porco et al. (2007), γ ≈ 0.85 for an incompressible fluid after Chandrasekhar (1969). Primary source for all four coefficients on this page. Peer-reviewed, open access. Retrieved 2026-07-29.
  2. [2]Leinhardt, Z.M., Ogilvie, G.I., Latter, H.N. and Kokubo, E. (2012). 'Tidal disruption of satellites and formation of narrow rings'. Monthly Notices of the Royal Astronomical Society; doi:10.1111/j.1365-2966.2012.21328.x. N-body result quoted on this page: 'the Roche limit for a rubble pile is closer to the planet than for a fluid body of the same mean density. The Roche limit for a differentiated body is also closer to the planet than for a homogeneous satellite of the same mean density.' Peer-reviewed; abstract open access, journal version paywalled. Retrieved 2026-07-29.
  3. [3]NASA JPL Solar System Dynamics, 'Planetary Physical Parameters': Earth volumetric mean radius 6371.0084 ± 0.0001 km and bulk density 5.5134 ± 0.0003 g/cm³; Saturn mean radius 58 232 km and bulk density 0.6871 g/cm³. Independent, open access. Retrieved 2026-07-29.
  4. [4]NASA JPL Solar System Dynamics, 'Planetary Satellite Physical Parameters': Earth's Moon, mean radius 1737.4 ± 0.1 km and mean density 3.344 ± 0.001 g/cm³, from ephemeris DE440. Independent, open access. Retrieved 2026-07-29.
  5. [5]NASA Science, 'Moon Facts' (page updated 12 February 2026): 'The Moon is an average of 238,855 miles (384,400 kilometers) away.' Source of the default orbital distance. Independent, open access. Retrieved 2026-07-29.
  6. [6]Chandrasekhar, S. (1969). Ellipsoidal Figures of Equilibrium. New Haven: Yale University Press — the equilibrium-ellipsoid analysis behind the fluid coefficient. Print/bibliographic reference, cited here through Tiscareno et al. (2013) rather than consulted directly.

How this page was produced

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Method
d = R_p · (4π ρ_p ⁄ (γ ρ_s))^(1⁄3) = C · R_p · (ρ_p ⁄ ρ_s)^(1⁄3), C = (4π ⁄ γ)^(1⁄3), ρ_Roche = ρ_p (C·R_p ⁄ d)³
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