Audited ·Last updated 29 Jul 2026·6 citations·Tier 2·0 uses

Tidal Force Calculator

Tidal force calculator: differential gravity across a body, with exact near-side and far-side values, the transverse squeeze and the tidal gradient.

Tidal Force Calculator

Which component
Default is the Moon: GM_Moon = 4902.800118 km³/s² (JPL DE440) divided by G = 6.67430 × 10⁻¹¹ (CODATA 2022). For the Sun use 1.98841 × 10³⁰ kg.
kg
Default is the Moon's mean distance, 384 400 km (NASA). For the Sun use 1.495978707 × 10¹¹ m. Must be larger than the body radius below.
m
Default is Earth's volumetric mean radius, 6371.0084 km (JPL). For a person, use half their height.
m
Only converts the acceleration into a force in newtons. It does not affect the acceleration itself.
kg
Tidal acceleration (selected component)
0
Magnitude of the differential gravitational acceleration for the component you chose.
Tidal force on the test mass
0.0001 N
Sign convention, regime and limits
SIGN CONVENTION: every figure is a positive magnitude. The RADIAL components point AWAY from the body's centre on BOTH the near and the far side — the tide stretches the body along the line to the perturber, which is why there are two bulges, not one. The TRANSVERSE component points INWARD: it squeezes the body at 90° to that line, and it is exactly half the linearised radial term. This calculator gives the FORCING only. It is not a tide height and not a tide time: real tides depend on ocean depth, basin resonance, coastline shape and the Earth's own elastic response, none of which is modelled here.
Radial, linearised (2GMr/d³)
0 m/s²
Radial, exact near side
0 m/s²
Radial, exact far side
0 m/s²
Transverse (compressive)
0 m/s²
Tidal gradient (2GM/d³)
0 s⁻²
Linearisation error
2.54

Background.

A tide is not gravity — it is the difference in gravity across an extended body. The Moon pulls harder on the ocean nearest it than on Earth's centre, and harder on Earth's centre than on the ocean on the far side, and it is those differences, not the pull itself, that raise the tides. This calculator computes that differential acceleration for any perturbing mass, separation and body radius, in four forms at once: the standard linearised expression, the exact near-side and far-side values, and the transverse component that squeezes rather than stretches.

The distinction from ordinary gravitational attraction is worth being precise about, because it produces a result most people find backwards. Total attraction falls off as the square of distance; a tide falls off as the cube. The Sun's total pull on Earth is about 178 times the Moon's, yet the Sun's tide is only about 46 % of the Moon's — a ratio of roughly 2.18 in the Moon's favour. That inversion happens entirely because of the extra power of distance, and it is why the Moon rather than the Sun governs the tides.

Sign convention matters here more than in most calculations, so it is stated beside the results rather than left implicit. Every number returned is a positive magnitude, but the directions differ. The radial components point away from the body's centre on both the near side and the far side — the tidal field stretches the body along the line joining it to the perturber. That is why there are two tidal bulges and two high tides a day, not one. The transverse component points inward: at right angles to that line the tidal field squeezes, with exactly half the magnitude of the linearised radial term. Stretch along one axis and squeeze along the other two, in that two-to-one ratio, is the complete description.

The linearised expression 2GMr/d³ that appears in every textbook is the first term of an expansion in r/d, and it is exact only in the limit where the body is vanishingly small compared with the separation. This page reports the exact near-side value alongside it and tells you the percentage difference. For the Earth–Moon system, where r/d is 0.0166, the linearised form is 2.54 % low. For the Earth–Sun system, where r/d is 4.3 × 10⁻⁵, it is low by 0.0064 %. The error grows quickly as bodies approach each other, and the page raises a warning once it passes 5 %, which happens at r/d ≈ 0.032. Past that point the near and far bulges also stop being the same size, so quoting a single tidal figure becomes misleading.

One scope limit belongs where the answer is. This calculator gives the tidal FORCING, and nothing more. Actual tides at a coastline depend on ocean depth, basin resonance, coastline geometry, friction and the solid Earth's own elastic response — effects that can shift high tide by hours and change its height by an order of magnitude between two places on the same shore. A tide table is the product of numerical models fitted to a century of gauge records, not of this equation. What this equation gives you is the driver those models respond to.

What is tidal force calculator?

Tidal force is the differential gravitational force across an extended body: the difference between the pull on its near side, its centre, and its far side. Because it is a difference rather than a total, the uniform part of the field cancels, and what is left is a stretching along the line to the perturber and a compression at right angles to it.

For a body of radius r at distance d from a mass M, the leading term is a = 2GMr/d³. The cube in the denominator is the defining feature, and it comes from differentiating the inverse-square law: d/dr of GM/r² is −2GM/r³. This is why a nearby small body can dominate a distant large one. It is also why tidal effects become extreme near compact objects, where d can be tiny — the stretching an infalling body experiences near a black hole, informally called spaghettification, is this same expression evaluated at very small d.

Tidal forces do a great deal of work in the solar system beyond raising ocean tides. They lock moons into synchronous rotation, so that one face permanently points at the planet. They heat interiors: Io, squeezed by Jupiter on an eccentric orbit, is the most volcanically active body known, and Europa and Enceladus owe their subsurface oceans to the same mechanism. Push far enough and tides disrupt a body entirely, which is the subject of the Roche Limit calculator.

How to use this calculator.

  1. Choose which component you want as the headline: the linearised radial term, the exact near or far side, or the transverse squeeze.
  2. Enter the perturbing body's mass in kilograms. The Moon is pre-filled; for the Sun use 1.98841 × 10³⁰ kg.
  3. Enter the centre-to-centre separation in metres. It must be larger than the body radius, or the near-side expression is singular.
  4. Enter the radius of the body being stretched — for Earth, its mean radius; for a person, about half their height.
  5. Enter a test mass if you want the answer as a force in newtons rather than an acceleration.
  6. Check the linearisation error before quoting the simple 2GMr/d³ figure. Above 5 % it is flagged, and you should use the exact values instead.
  7. Remember this is the forcing only: it is not a tide height and not a tide time.

The formula.

a_t = 2GMr ⁄ d³ · a_near = GM[1⁄(d−r)² − 1⁄d²] · a_far = GM[1⁄d² − 1⁄(d+r)²] · a_⊥ = GMr ⁄ d³

Start from Newton's law. The gravitational acceleration a perturbing mass M produces at distance x is GM/x². A body of radius r centred at distance d has its near face at d − r and its far face at d + r, so the near face feels GM/(d − r)² and the centre feels GM/d². The difference between them is the near-side tidal acceleration, GM[1/(d − r)² − 1/d²], and it is directed towards the perturber. On the far side the same subtraction gives GM[1/d² − 1/(d + r)²], directed away from the perturber. Both point away from the body's centre, which is why there are two bulges.

Expanding either expression for small r/d gives 2GMr/d³, the familiar textbook form, which is the same on both sides at first order. The inverse cube is the whole story: differentiating an inverse-square field with respect to distance necessarily raises the power by one.

The transverse component comes from geometry rather than magnitude. At 90° from the line of centres the perturber's pull is essentially the same size as at the body's centre but points in a slightly different direction, and the component of that difference is directed inward with magnitude GMr/d³ — exactly half the radial term. The two-to-one ratio of stretch to squeeze is a signature of any inverse-square field and is a direct consequence of the tidal tensor being trace-free in vacuum.

ROUNDING STAGE. Nothing is rounded part-way through. All arithmetic runs at 40 significant digits in a dedicated high-precision decimal context. Rounding happens once, at the return boundary, to 12 significant digits rather than a fixed decimal place — tidal accelerations are of order 10⁻⁷ m/s² and the gradient of order 10⁻¹³ s⁻², both of which a fixed decimal place would round to a flat zero. The linearisation error is rounded once and that same rounded value drives both the displayed percentage and the 5 % warning, so the note and the number on screen can never disagree.

SIGNIFICANT FIGURES. The arithmetic is exact to twelve figures, but the inputs are not: a mass entered in kilograms carries the 22-parts-per-million uncertainty of the gravitational constant G, and real separations vary continuously — the Moon's distance swings between roughly 363 000 and 406 000 km over a month, changing the lunar tide by about 40 %. Three significant figures is a generous ceiling for any real application.

SIGN CONVENTION AND INVALID DOMAIN. All outputs are positive magnitudes; the directions are given in words beside the result. Every input must be strictly positive, and the separation must exceed the body's radius: at d = r the term 1/(d − r)² is a genuine singularity, and d < r would place the perturbing mass inside the body, where none of these expressions apply. That case raises a labelled error naming the minimum valid separation.

APPROXIMATION REGIME. Newtonian, point-mass perturber, rigid body, no ocean response, no Love numbers, no resonance, no coastline. Near a black hole or a neutron star the Newtonian expression also stops being adequate and a general-relativistic treatment is required.

A worked example.

Example

How strong is the Moon's tide on Earth? The Moon's gravitational parameter is GM = 4 902.800118 km³/s² from JPL's DE440 ephemeris, which is 4.902800118 × 10¹² m³/s²; dividing by G gives a mass of 7.34578924831 × 10²² kg. The mean distance is 384 400 km and Earth's volumetric mean radius is 6 371.0084 km. The linearised tidal acceleration is 2GMr/d³ = 2 × 4.902800118 × 10¹² × 6.3710084 × 10⁶ ⁄ (3.844 × 10⁸)³ = 1.09984687261 × 10⁻⁶ m/s². On a 70 kg person that is a force of 7.698928108 × 10⁻⁵ newtons — about eight micrograms' worth, which is why you do not feel it. The exact values bracket that figure. The near side gives GM[1/(d − r)² − 1/d²] = 1.12780702154 × 10⁻⁶ m/s², and the far side gives GM[1/d² − 1/(d + r)²] = 1.07309570834 × 10⁻⁶ m/s². The linearised form sits 2.54 % below the near-side value, which is the size of the r/d correction it drops. The transverse component is 5.49923436305 × 10⁻⁷ m/s², exactly half the linearised radial term, and the tidal gradient is 1.72633090958 × 10⁻¹³ s⁻². Now substitute the Sun: mass 1.98841 × 10³⁰ kg at 1.495978707 × 10¹¹ m. The linearised solar tide is 5.05095583805 × 10⁻⁷ m/s². Dividing the lunar figure by the solar one gives 2.1775 — the Moon's tide is 2.18 times the Sun's, and the Sun contributes 45.92 % of the Moon's. Yet the Sun's total gravitational pull on Earth is about 178 times the Moon's. The inverse cube is the entire reason those two comparisons point in opposite directions. Note too that the linearisation error for the Sun is only 0.0064 %, because Earth's radius is a far smaller fraction of an astronomical unit than it is of the lunar distance.

test Mass Kg70
componentradialApproximate
perturbing Mass Kg73,457,892,483,100,000,000,000
body Radius M6,371,008.4
separation M384,400,000

Frequently asked questions.

Why are there two tidal bulges instead of one?
Because the tidal field stretches rather than pulls. Work in the frame of Earth's centre: the near-side ocean is closer to the Moon than the centre is, so it feels a stronger pull and is displaced towards the Moon. The far-side ocean is farther away, so it feels a weaker pull than the centre and is effectively left behind — displaced away from the Moon. Both displacements are outward from Earth's centre, so both produce a bulge. Earth rotates through both of them each day, which is why most coasts see two high tides.
Why does the Moon raise a bigger tide than the Sun when the Sun pulls far harder?
Because tides depend on the cube of distance rather than the square. Total attraction goes as M/d², and by that measure the Sun beats the Moon by a factor of about 178. Tidal acceleration goes as M/d³, and dividing by one more power of distance is enough to reverse the comparison: with the values on this page the Moon's tide is 2.18 times the Sun's, and the Sun supplies 45.9 % of the lunar figure. The Sun's contribution is what makes spring and neap tides, by adding to or partly cancelling the lunar tide.
Sources disagree on the Moon-to-Sun tidal ratio — which is right?
There is a real disagreement worth naming. NOAA's 'Our Restless Tides' states that 'the tide producing force of the moon is approximately 2.5 times that of the sun'. Computing it directly from JPL DE440's gravitational parameters, the IAU's astronomical unit and CODATA 2022's G gives 2.1775 — and the widely used figure that the solar tide is 46 % of the lunar one corresponds to 2.17, agreeing with the calculation rather than with 2.5. This page reports 2.18, because that is what the inverse-cube law and the published constants give; NOAA's own chapter on the subject states the inverse-cube dependence that produces it. The 2.5 appears to be a legacy rounding, and it is recorded here rather than quietly dropped.
When is the simple 2GMr/d³ formula not good enough?
When the body's radius is a significant fraction of the separation. The formula is the first term of an expansion in r/d, and its error is roughly 1.5 × r/d. For Earth and the Sun, r/d is 4.3 × 10⁻⁵ and the error is 0.0064 % — utterly negligible. For Earth and the Moon, r/d is 0.0166 and the error is 2.54 %. This page flags the case once the error passes 5 %, at r/d ≈ 0.032, and past that point the near and far bulges also differ noticeably from each other, so no single number describes the tide.
Can I use this to predict high tide where I live?
No, and it is important to be clear about it. This calculator gives the tidal forcing — the driver. The actual tide at any coastline is the ocean's response to that driver, and it depends on water depth, the resonant properties of the ocean basin, the shape of the coast, friction, weather and the solid Earth's elastic deformation. Those effects shift the timing by hours and change the range enormously: the Bay of Fundy sees over 15 metres where the open-ocean equilibrium tide is well under a metre. Published tide tables come from numerical models fitted to long gauge records, not from this equation.
What is the tidal gradient, and what are its units?
It is 2GM/d³, the difference in gravitational acceleration per metre of separation, with units of inverse seconds squared — metres per second squared, per metre. It is a convenient intermediate: multiply it by any body's radius and you get that body's tidal acceleration directly. For the Moon acting at Earth's distance it is 1.726 × 10⁻¹³ s⁻², so a two-metre-tall person is stretched by about 3.5 × 10⁻¹³ m/s² from head to toe.
Is this the same thing as spaghettification near a black hole?
It is the same expression, evaluated where d is small. Stretching goes as M/d³, so as an object falls towards a compact mass the tidal difference across its own length grows without bound, and at some point exceeds the strength of the material holding it together. The Newtonian formula on this page becomes inadequate close to a black hole and a general-relativistic treatment is required, but the scaling and the physical picture — stretched along the radial direction, squeezed transversely at half the rate — carry over.

References& sources.

  1. [1]NIST, CODATA 2022 recommended value of the Newtonian constant of gravitation: G = 6.674 30(15) × 10⁻¹¹ m³ kg⁻¹ s⁻², relative standard uncertainty 2.2 × 10⁻⁵. Independent, open access. Retrieved 2026-07-29.
  2. [2]NASA JPL Solar System Dynamics, 'Planetary Satellite Physical Parameters': Earth's Moon, GM = 4902.800 ± 0.001 km³/s² and mean radius 1737.4 km, from ephemeris DE440. Source of the default perturbing mass. Independent, open access. Retrieved 2026-07-29.
  3. [3]NASA JPL Solar System Dynamics, 'Astrodynamic Constants': astronomical unit 149 597 870 700 m; heliocentric gravitational constant GM_Sun = 1.327 124 400 412 794 19 × 10²⁰ m³ s⁻² (DE440). Source of the solar comparison figures. Independent, open access. Retrieved 2026-07-29.
  4. [4]NASA JPL Solar System Dynamics, 'Planetary Physical Parameters': Earth volumetric mean radius 6371.0084 ± 0.0001 km. Source of the default body radius. Independent, open access. Retrieved 2026-07-29.
  5. [5]NOAA, Center for Operational Oceanographic Products and Services, 'Our Restless Tides', chapter 4: states that the tide-producing force varies 'in inverse proportion to the third power of the distance' between the bodies. Chapter 3 of the same document states that 'the tide producing force of the moon is approximately 2.5 times that of the sun' — a figure this page does NOT adopt; see the FAQ on the Moon-to-Sun ratio for the recorded disagreement. Independent, open access. Retrieved 2026-07-29.
  6. [6]NASA Science, 'Moon Facts' (page updated 12 February 2026): 'The Moon is an average of 238,855 miles (384,400 kilometers) away.' Source of the default separation. Independent, open access. Retrieved 2026-07-29.

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